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Cobra venom helps the snake secure food by binding to acetylcholine receptors on the diaphragm of a bite victim, leading to the loss of function of the diaphragm muscle tissue and eventually death. In order to develop more potent antivenoms, scientists have studied what happens to the toxin once it has bound the acetylcholine receptors. They have found that the toxin is released from the receptor in a process that can be described by the rate law Rate \(=k[\) acetylcholine receptor-toxin complex \(]\) If the activation energy of this reaction at \(37.0^{\circ} \mathrm{C}\) is \(26.2 \mathrm{~kJ} / \mathrm{mol}\) and \(A=0.850 \mathrm{~s}^{-1}\), what is the rate of reaction if you have a \(0.200 M\) solution of receptor-toxin complex at \(37.0^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
The rate of reaction at a concentration of 0.200 M receptor-toxin complex and at 37.0\(^\circ C\) is approximately \(3.1 \times 10^{-4} M s^{-1}\).

Step by step solution

01

Convert temperature to Kelvin

Convert the temperature from Celsius to Kelvin using the formula: \(T(K) = T(^\circ C) + 273.15\) The given temperature is: \(T = 37.0^\circ C\) So, \(T(K) = 37.0 + 273.15 = 310.15 K\)
02

Calculate the rate constant, k, using the Arrhenius equation

The Arrhenius equation is given as: \(k = Ae^{-\frac{Ea}{RT}}\) where k - rate constant A - pre-exponential factor Ea - activation energy (\(26.2 kJ/mol = 26200 J/mol\)) R - gas constant (\(8.314 J/mol K\)) T - temperature in Kelvin Now, plug in the values and compute k: \(k = (0.850 s^{-1})e^{-\frac{(26200 J/mol)}{(8.314 J/mol K)(310.15 K)}} \) Calculating the exponential term first: \(e^{-\frac{26200}{(8.314)(310.15)}} \approx 0.00182\) Now multiplying by A: \(k = 0.850 \times 0.00182 \approx 0.00155 s^{-1}\)
03

Calculate the rate of reaction at the given concentration of the receptor-toxin complex

We know that the rate law for this reaction is given as: Rate \(= k[\text{acetylcholine receptor-toxin complex}]\) Now, plug in the rate constant (k) and the given concentration (0.200 M) of the receptor-toxin complex: Rate \(= (0.00155 s^{-1})(0.200 M)\) Rate \(= 3.1 \times 10^{-4} M s^{-1}\) The rate of reaction at a concentration of 0.200 M receptor-toxin complex and at 37.0\(^\circ C\) is approximately \(3.1 \times 10^{-4} M s^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Rate Law in Reactions
In chemical kinetics, the rate law helps us understand how the concentration of substances in a reaction affects the rate of reaction.
In the exercise, the rate law is expressed as:
  • Rate \(= k[\text{acetylcholine receptor-toxin complex}]\)
This indicates that the rate of the reaction is directly proportional to the concentration of the receptor-toxin complex. Here:
  • \(k\) is the rate constant
  • The concentration of the acetylcholine receptor-toxin complex determines how quickly the reaction proceeds
Understanding this relationship helps scientists predict how changes in concentration influence the effectiveness of antidotes.
Exploring the Arrhenius Equation
The Arrhenius equation provides insight into how temperature affects the reaction rate. It is formulated as:
  • \(k = Ae^{-\frac{Ea}{RT}}\)
Here:
  • \(A\) is the pre-exponential factor
  • \(Ea\) is the activation energy
  • \(R\) is the gas constant
  • \(T\) is the temperature in Kelvin
By using this equation in the exercise, we determine the rate constant \(k\). The Arrhenius equation shows how an increase in temperature generally increases the reaction rate, revealing the complex interplay between temperature and reaction kinetics.
Importance of Activation Energy
Activation energy, \(Ea\), is a crucial concept in chemical kinetics. It refers to the minimum energy needed for a reaction to occur. In the exercise, the activation energy is given as \(26.2 \text{kJ/mol}\).
  • This energy barrier determines how fast a reaction takes place
  • Reactions with lower activation energies happen more quickly because less energy is required to begin the process
Understanding activation energy helps scientists design more effective antidotes by lowering this energy barrier, making reactions proceed more swiftly.
Role of Concentration
Concentration plays a vital role in determining the speed of chemical reactions. In the context of this exercise:
  • The concentration of the receptor-toxin complex is \(0.200 M\)
This concentration directly impacts the reaction rate as expressed by the rate law. Increased concentration usually leads to a faster reaction because:
  • More molecules are available to react
  • This results in a higher probability of effective collisions
By managing concentrations, scientists can control how quickly reactions occur and improve the design of antidotes.
Understanding the Rate of Reaction
The rate of reaction is an essential aspect of understanding how quickly a reaction proceeds. In this exercise, it is calculated as \( 3.1 \times 10^{-4} \text{M s}^{-1} \). This calculation reflects:
  • The change in concentration of reactants per unit time
  • How efficiently the receptor-toxin complex forms and decomposes
By knowing the rate of reaction, scientists can evaluate the effectiveness of antivenoms, allowing them to make adjustments for better results.

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Most popular questions from this chapter

The reaction \(\mathrm{H}_{2} \mathrm{SeO}_{3}(a q)+6 \mathrm{I}^{-}(a q)+4 \mathrm{H}^{+}(a q)\) \(\longrightarrow \mathrm{Se}(s)+2 \mathrm{I}_{3}^{-}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l)\) was studied at \(0^{\circ} \mathrm{C}\), and the following data were obtained:

Consider the following statements: "In general, the rate of a chemical reaction increases a bit at first because it takes a while for the reaction to get 'warmed up.' After that, however, the rate of the reaction decreases because its rate is dependent on the concentrations of the reactants, and these are decreasing." Indicate everything that is correct in these statements, and indicate everything that is incorrect. Correct the incorrect statements and explain.

How does temperature affect k, the rate constant? Explain.

Chemists commonly use a rule of thumb that an increase of \(10 \mathrm{~K}\) in temperature doubles the rate of a reaction. What must the activation energy be for this statement to be true for a temperature increase from 25 to \(35^{\circ} \mathrm{C}\) ?

A popular chemical demonstration is the "magic genie" procedure, in which hydrogen peroxide decomposes to water and oxygen gas with the aid of a catalyst. The activation energy of this (uncatalyzed) reaction is \(70.0 \mathrm{~kJ} / \mathrm{mol}\). When the catalyst is added, the activation energy (at \(20 .{ }^{\circ} \mathrm{C}\) ) is \(42.0 \mathrm{~kJ} / \mathrm{mol}\). Theoretically, to what temperature \(\left({ }^{\circ} \mathrm{C}\right)\) would one have to heat the hydrogen peroxide solution so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction at \(20 .{ }^{\circ} \mathrm{C} ?\) Assume the frequency factor \(A\) is constant and assume the initial concentrations are the same.

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