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For an acid or a base, when is the normality of a solution equal to the molarity of the solution and when are the two concentration units different?

Short Answer

Expert verified
The normality (N) and molarity (M) of a solution are equal when an acid or base has only one ionizable hydrogen (H+) ion or hydroxide (OH-) ion in its molecular structure, i.e., monoprotic acids and bases. For example, hydrochloric acid (HCl) and sodium hydroxide (NaOH) have one ionizable H+ ion and OH- ion, respectively, making their normality equal to their molarity. On the other hand, normality and molarity are different for polyprotic acids and bases, which have more than one ionizable hydrogen or hydroxide ion. For instance, sulfuric acid (H2SO4) has two ionizable H+ ions, making its normality double its molarity, while calcium hydroxide (Ca(OH)2) has two hydroxide ions, also resulting in normality being double its molarity.

Step by step solution

01

Define Normality and Molarity

Normality (N) is the measure of the concentration of a solution expressed as the equivalent mass per unit volume (grams equivalent per liter), while molarity (M) is the measure of the concentration of a solution expressed as the number of moles of solute per unit volume (moles per liter). Mathematically, Normality can be defined as: \( Normality = \frac{Equivalent\ mass}{Volume\ of\ solution} \) And, Molarity can be defined as: \( Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution }\)
02

Find the relationship between normality and molarity

To find the relationship between normality and molarity, we must consider the equivalent mass, which is the mass of the solute required to react with or replace an equivalent of a reference substance. For acids, an equivalent is the mass that can release one mole of hydrogen ions (H+). For bases, an equivalent is the mass that can absorb one mole of hydrogen ions (H+). We know that: \( Equivalent\ mass = \frac{molar\ mass}{number\ of\ equivalents} \) So, \( Normality = \frac{moles\ of\ solute \times molar\ mass}{volume\ of\ solution \times number\ of\ equivalents} \) We can rewrite this equation in terms of molarity: \( Normality = Molarity \times number\ of\ equivalents \) From this equation, we can analyze when normality is equal to molarity and when they are different.
03

Determine when normality is equal to molarity

Normality is equal to molarity when the number of equivalents is 1. This happens when an acid or base has only one ionizable hydrogen (H+) ion or hydroxide (OH-) ion in its molecular structure, i.e., monoprotic acids and bases. For example, in the case of hydrochloric acid (HCl) and sodium hydroxide (NaOH), both have only one ionizable H+ ion and OH- ion, respectively. Thus, the normality of HCl and NaOH solutions will be equal to their molarity.
04

Determine when normality is different from molarity

Normality is different from molarity when the number of equivalents is not 1. This happens when an acid or base has more than one ionizable hydrogen (H+) ion or hydroxide (OH-) ion in its molecular structure, i.e., polyprotic acids and bases. For example, in the case of sulfuric acid (H2SO4) which has two ionizable H+ ions. The normality of a sulfuric acid solution will be double its molarity. Similarly, for a diprotic base like calcium hydroxide (Ca(OH)2), the normality will be double its molarity. In summary, normality and molarity are equal for monoprotic acids and bases when they have only one ionizable hydrogen or hydroxide ion. Normality and molarity are different for polyprotic acids and bases when they have more than one ionizable hydrogen or hydroxide ion.

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Most popular questions from this chapter

Erythrocytes are red blood cells containing hemoglobin. In a saline solution they shrivel when the salt concentration is high and swell when the salt concentration is low. In a \(25^{\circ} \mathrm{C}\) aqueous solution of \(\mathrm{NaCl}\), whose freezing point is \(-0.406^{\circ} \mathrm{C}\), erythrocytes neither swell nor shrink. If we want to calculate the osmotic pressure of the solution inside the erythrocytes under these conditions, what do we need to assume? Why? Estimate how good (or poor) of an assumption this is. Make this assumption and calculate the osmotic pressure of the solution inside the erythrocytes.

Calculate the normality of each of the following solutions. a. \(0.250 \mathrm{M} \mathrm{HCl}\) b. \(0.105 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) c. \(5.3 \times 10^{-2} M \mathrm{H}_{3} \mathrm{PO}_{4}\) d. \(0.134 \mathrm{M} \mathrm{NaOH}\) e. \(0.00521 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_{2}\) What is the equivalent mass for each of the acids or bases listed above?

Using the following information, identify the strong electrolyte whose general formula is $$ \mathrm{M}_{x}(\mathrm{~A})_{y} \cdot z \mathrm{H}_{2} \mathrm{O} $$ Ignore the effect of interionic attractions in the solution. a. \(\mathrm{A}^{n-}\) is a common oxyanion. When \(30.0 \mathrm{mg}\) of the anhydrous sodium salt containing this oxyanion \(\left(\mathrm{Na}_{n} \mathrm{~A}\right.\), where \(n=1,2\), or 3 ) is reduced, \(15.26 \mathrm{~mL}\) of \(0.02313 M\) reducing agent is required to react completely with the \(\mathrm{Na}_{n}\) A present. Assume a \(1: 1\) mole ratio in the reaction. b. The cation is derived from a silvery white metal that is relatively expensive. The metal itself crystallizes in a body-centered cubic unit cell and has an atomic radius of \(198.4 \mathrm{pm}\). The solid, pure metal has a density of \(5.243 \mathrm{~g} / \mathrm{cm}^{3}\). The oxidation number of \(\mathrm{M}\) in the strong electrolyte in question is \(+3\). c. When \(33.45 \mathrm{mg}\) of the compound is present (dissolved) in \(10.0 \mathrm{~mL}\) of aqueous solution at \(25^{\circ} \mathrm{C}\), the solution has an osmotic pressure of 558 torr.

A \(2.00-\mathrm{g}\) sample of a large biomolecule was dissolved in \(15.0 \mathrm{~g}\) carbon tetrachloride. The boiling point of this solution was determined to be \(77.85^{\circ} \mathrm{C}\). Calculate the molar mass of the biomolecule. For carbon tetrachloride, the boiling-point constant is \(5.03^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol}\), and the boiling point of pure carbon tetrachloride is \(76.50^{\circ} \mathrm{C}\).

A \(1.60-\mathrm{g}\) sample of a mixture of naphthalene \(\left(\mathrm{C}_{10} \mathrm{H}_{8}\right)\) and anthracene \(\left(\mathrm{C}_{14} \mathrm{H}_{10}\right)\) is dissolved in \(20.0 \mathrm{~g}\) benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\). The freezing point of the solution is \(2.81^{\circ} \mathrm{C}\). What is the composition as mass percent of the sample mixture? The freezing point of benzene is \(5.51^{\circ} \mathrm{C}\) and \(K_{\mathrm{f}}\) is \(5.12^{\circ} \mathrm{C} \cdot \mathrm{kg} / \mathrm{mol}\).

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