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The critical point of \(\mathrm{NH}_{3}\) is \(132^{\circ} \mathrm{C}\) and \(111 \mathrm{~atm}\), and the critical point of \(\mathrm{N}_{2}\) is \(-147^{\circ} \mathrm{C}\) and 34 atm. Which of these substances cannot be liquefied at room temperature no matter how much pressure is applied? Explain.

Short Answer

Expert verified
Nitrogen (N2) cannot be liquefied at room temperature, no matter how much pressure is applied. This is because its critical temperature (\(T_{c_{N2}}\) = 126.15 K) is lower than room temperature (298 K). On the other hand, ammonia (NH3) can be liquefied at room temperature since its critical temperature (\(T_{c_{NH3}}\) = 405.15 K) is higher than room temperature.

Step by step solution

01

Identify the critical points of NH3 and N2.

The critical point of ammonia (NH3) is given as 132°C and 111 atm. The critical point of nitrogen (N2) is given as -147°C and 34 atm.
02

Convert the critical temperatures to Kelvin.

We need to convert the critical temperatures from Celsius to Kelvin to facilitate the comparison with room temperature (298 K). To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature. For NH3: \(T_{c_{NH3}}\) = 132°C + 273.15 = 405.15 K For N2: \(T_{c_{N2}}\) = -147° + 273.15 = 126.15 K
03

Compare the critical temperatures with room temperature.

If the critical temperature of a substance is below room temperature (298 K), it cannot be liquefied at room temperature, regardless of the pressure applied. For NH3: \(T_{c_{NH3}}\) = 405.15 K > 298 K, so NH3 can be liquefied at room temperature. For N2: \(T_{c_{N2}}\) = 126.15 K < 298 K, so N2 cannot be liquefied at room temperature, no matter how much pressure is applied.
04

State the conclusion.

Based on the comparison of the critical temperatures with room temperature, it is clear that nitrogen (N2) cannot be liquefied at room temperature, regardless of the pressure applied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ammonia (NH3)
Ammonia, or \( ext{NH}_3\), is a colorless gas with a pungent smell that is composed of nitrogen and hydrogen. It is commonly used in various industrial applications, including fertilizers, cleaning products, and refrigeration systems. Ammonia has a relatively high critical temperature of 132°C (405.15 K), \(
\)allowing it to be easily condensed into a liquid at room temperature. This characteristic makes \( ext{NH}_3\) very useful for cooling and other applications involving phase changes. \(
\)Understanding its critical point is essential to efficiently employ it in systems where precise temperature control is needed.
Nitrogen (N2)
Nitrogen, or \( ext{N}_2\), constitutes about 78% of the Earth's atmosphere by volume. It is a diatomic molecule that plays a critical role in supporting life through the nitrogen cycle. The critical point of nitrogen is quite low, at \(-147°C\) or 126.15 K. \(
\)This low critical temperature means at higher temperatures, such as room temperature, \( ext{N}_2\) remains gaseous regardless of the pressure applied. \(
\)It is important to note that nitrogen remains stable and non-reactive under most conditions, which contributes to its wide range of applications from cryogenics to serving as an inert atmosphere for chemical reactions.
Liquefaction
Liquefaction is the process of converting a gas into its liquid form. This process involves changing the temperature and pressure conditions to bring the gas below its critical temperature and above its critical pressure. \(
\)For a gas to liquefy, the temperature must be below its critical temperature. If it is above, like the case with nitrogen at room temperature, \( ext{N}_2\) cannot be compressed into a liquid. \(
\)The practical implications of liquefaction are significant in many industries. By liquefying gases, we can store and transport them more efficiently, especially for gases, such as natural gas and ammonia.
Pressure
Pressure is a fundamental concept in physics that describes the force exerted per unit area. It plays a crucial role in determining the state of a substance (gas, liquid, or solid) under various conditions. \(
\)In the context of liquefaction, pressure is combined with temperature to examine a substance’s critical point. \(
\)If the pressure is increased above the critical pressure while at a temperature below the critical temperature, a gas will turn into a liquid. Thus, by manipulating pressure, substances like ammonia can be liquefied efficiently at room temperature.
Temperature Conversion
Temperature conversion, especially between Celsius and Kelvin, is essential for scientific calculations involving thermal systems. Kelvin is the SI unit for temperature, which starts at absolute zero, the point at which molecular motion stops. \(
\)To convert Celsius to Kelvin, 273.15 is added to the Celsius value. This conversion allows for consistent scientific communication and comparison. \(
\)Understanding these conversions is vital in identifying conditions like critical points where phase changes occur, as seen in the comparison of ammonia and nitrogen critical temperatures to room temperature.

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Most popular questions from this chapter

Why are the dipole-dipole interactions between polar molecules not important in the vapor phase?

Rationalize the differences in physical properties in terms of intermolecular forces for the following organic compounds. Compare the first three substances with each other, compare the last three with each other, and then compare all six. Can you account for any anomalies? $$ \begin{array}{|lccc|} \hline & \text { bp }\left({ }^{\circ} \mathrm{C}\right) & \operatorname{mp}\left({ }^{\circ} \mathrm{C}\right) & \Delta H_{\text {vap }}(\mathbf{k J} / \text { mol }) \\ \hline \text { Benzene, } \mathrm{C}_{6} \mathrm{H}_{6} & 80 & 6 & 33.9 \\ \text { Naphthalene, } & & & \\ \mathrm{C}_{10} \mathrm{H}_{8} & 218 & 80 & 51.5 \\ \text { Carbon tetra- } & & & \\ \text { chloride } & 76 & -23 & 31.8 \\ \text { Acetone, } & & & \\ \mathrm{CH}_{3} \mathrm{COCH}_{3} & 56 & -95 & 31.8 \\ \text { Acetic acid, } & & & \\ \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} & 118 & 17 & 39.7 \\ \text { Benzoic acid, } & & & \\ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H} & 249 & 122 & 68.2 \\\ \hline \end{array} $$

A substance, \(X\), has the following properties: Sketch a heating curve for substance \(\mathrm{X}\) starting at \(-50 .{ }^{\circ} \mathrm{C}\).

Consider the following data for xenon: Triple point: \(-121^{\circ} \mathrm{C}, 280\) torr Normal melting point: \(\quad-112^{\circ} \mathrm{C}\) Normal boiling point: \(-107^{\circ} \mathrm{C}\) Which is more dense, \(\operatorname{Xe}(s)\) or \(\operatorname{Xe}(I) ?\) How do the melting point and boiling point of xenon depend on pressure?

In each of the following groups of substances, pick the one that has the given property. Justify each answer. a. highest boiling point: \(\mathrm{CCl}_{4}, \mathrm{CF}_{4}, \mathrm{CBr}_{4}\) b. lowest freezing point: \(\mathrm{LiF}, \mathrm{F}_{2}, \mathrm{HCl}\) c. smallest vapor pressure at \(25^{\circ} \mathrm{C}: \mathrm{CH}_{3} \mathrm{OCH}_{3}, \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\) d. greatest viscosity: \(\mathrm{H}_{2} \mathrm{~S}, \mathrm{HF}, \mathrm{H}_{2} \mathrm{O}_{2}\) e. greatest heat of vaporization: \(\mathrm{H}_{2} \mathrm{CO}, \mathrm{CH}_{3} \mathrm{CH}_{3}, \mathrm{CH}_{4}\) f. smallest enthalpy of fusion: \(\mathrm{I}_{2}, \mathrm{CsBr}, \mathrm{CaO}\)

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