Question

Convert the following Celsius temperatures to Kelvin and to Fahrenheit degrees. a. the temperature of someone with a fever, ${39.2}^{\circ }\mathrm{C}$ b. a cold wintery day, $-{25}^{\circ }\mathrm{C}$ c. the lowest possible temperature, $-{273}^{\circ }\mathrm{C}$ d. the melting-point temperature of sodium chloride, ${801}^{\circ }\mathrm{C}$

Short answer

a. Fever Temperature: 312.35 K and 102.56 °F b. Cold Wintery Day Temperature: 248.15 K and -13 °F c. Lowest Possible Temperature: 0.15 K and -459.4 °F d. Melting-point Temperature of Sodium Chloride: 1074.15 K and 1473.8 °F

Step-by-step solution

a. Fever Temperature

Given Celsius temperature: ${39.2}^{\circ }\mathrm{C}$ Celsius to Kelvin: K = C + 273.15 K = 39.2 + 273.15 K = 312.35 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * 39.2) + 32 F = 102.56 °F Therefore, the fever temperature is 312.35 K and 102.56 °F.

b. Cold Wintery Day Temperature

Given Celsius temperature: $-{25}^{\circ }\mathrm{C}$ Celsius to Kelvin: K = C + 273.15 K = -25 + 273.15 K = 248.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * -25) + 32 F = -13 °F Therefore, the cold wintery day temperature is 248.15 K and -13 °F.

c. Lowest Possible Temperature

Given Celsius temperature: $-{273}^{\circ }\mathrm{C}$ Celsius to Kelvin: K = C + 273.15 K = -273 + 273.15 K = 0.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * -273) + 32 F = -459.4 °F Therefore, the lowest possible temperature is 0.15 K and -459.4 °F.

d. Melting-point Temperature of Sodium Chloride

Given Celsius temperature: ${801}^{\circ }\mathrm{C}$ Celsius to Kelvin: K = C + 273.15 K = 801 + 273.15 K = 1074.15 K Celsius to Fahrenheit: F = (9/5 * C) + 32 F = (9/5 * 801) + 32 F = 1473.8 °F Therefore, the melting-point temperature of sodium chloride is 1074.15 K and 1473.8 °F.