Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Perform each of the following conversions. a. \(8.43 \mathrm{~cm}\) to millimeters b. \(2.41 \times 10^{2} \mathrm{~cm}\) to meters c. \(294.5 \mathrm{~nm}\) to centimeters d. \(1.445 \times 10^{4} \mathrm{~m}\) to kilometers e. \(235.3 \mathrm{~m}\) to millimeters f. \(903.3 \mathrm{~nm}\) to micrometers

Short Answer

Expert verified
a. \(84.3 \mathrm{~mm}\) b. \(2.41 \mathrm{~m}\) c. \(2.945 \times 10^{-5} \mathrm{~cm}\) d. \(14.45 \mathrm{~km}\) e. \(235300 \mathrm{~mm}\) f. \(0.9033 \mathrm{~\mu m}\)

Step by step solution

01

(Conversion 1: Centimeters to Millimeters)

We have 8.43 cm and we need to convert it to millimeters. We know that 1 cm = 10 mm. Therefore, we multiply the given value by 10: \(8.43 \mathrm{~cm} \times 10 = 84.3 \mathrm{~mm}\)
02

(Conversion 2: Centimeters to Meters)

We have \(2.41 \times 10^2\) cm and need to convert it to meters. We know that 1 m = 100 cm. Therefore, we divide the given value by 100: \(\frac{2.41 \times 10^2 \mathrm{~cm}}{100} = 2.41 \mathrm{~m}\)
03

(Conversion 3: Nanometers to Centimeters)

We have 294.5 nm and need to convert it to centimeters. We know that 1 nm = \(10^{-9}\) m and 1 m = 100 cm. Therefore, we first convert nm to m and then m to cm: \(294.5 \mathrm{~nm} \times 10^{-9} \mathrm{~m/nm} = 2.945 \times 10^{-7} \mathrm{~m}\) \(2.945 \times 10^{-7} \mathrm{~m} \times 100 \mathrm{~cm/m} = 2.945 \times 10^{-5} \mathrm{~cm}\)
04

(Conversion 4: Meters to Kilometers)

We have \(1.445 \times 10^4\) m and need to convert it to kilometers. We know that 1 km = 1000 m. Therefore, we divide the given value by 1000: \(\frac{1.445 \times 10^4 \mathrm{~m}}{1000} = 14.45 \mathrm{~km}\)
05

(Conversion 5: Meters to Millimeters)

We have 235.3 m and need to convert it to millimeters. We know that 1 m = 1000 mm. Therefore, we multiply the given value by 1000: \(235.3 \mathrm{~m} \times 1000 = 235300 \mathrm{~mm}\)
06

(Conversion 6: Nanometers to Micrometers)

We have 903.3 nm and need to convert it to micrometers. We know that 1 nm = \(10^{-9}\) m and 1 μm = \(10^{-6}\) m. Therefore, we first convert nm to m and then m to μm: \(903.3 \mathrm{~nm} \times 10^{-9} \mathrm{~m/nm} = 9.033 \times 10^{-7} \mathrm{~m}\) \(9.033 \times 10^{-7} \mathrm{~m} \times \frac{1 \times 10^{6} \mathrm{~\mu m}}{1 \mathrm{~m}} = 0.9033 \mathrm{~\mu m} \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to the Official Rules of Baseball, a baseball must have a circumference not more than \(9.25\) in or less than \(9.00\) in and a mass not more than \(5.250 \mathrm{z}\) or less than \(5.00 \mathrm{oz}\). What range of densities can a baseball be expected to have? Express this range as a single number with an accompanying uncertainty limit.

The density of osmium (the densest metal) is \(22.57 \mathrm{~g} / \mathrm{cm}^{3} .\) If a \(1.00-\mathrm{kg}\) rectangular block of osmium has two dimensions of \(4.00 \mathrm{~cm} \times 4.00 \mathrm{~cm}\), calculate the third dimension of the block.

You go to a convenience store to buy candy and find the owner to be rather odd. He allows you to buy pieces in multiples of four, and to buy four, you need \(\$ 0.23 .\) He only allows you to do this by using 3 pennies and 2 dimes. You have a bunch of pennies and dimes, and instead of counting them, you decide to weigh them. You have \(636.3 \mathrm{~g}\) of pennies, and each penny weighs \(3.03 \mathrm{~g}\). Each dime weighs \(2.29 \mathrm{~g}\). Each piece of candy weighs \(10.23 \mathrm{~g}\). a. How many pennies do you have? b. How many dimes do you need to buy as much candy as possible? c. How much should all these dimes weigh? d. How many pieces of candy could you buy? (number of dimes from part b) e. How much would this candy weigh? f. How many pieces of candy could you buy with twice as many dimes?

Diamonds are measured in carats, and 1 carat \(=0.200 \mathrm{~g}\). The density of diamond is \(3.51 \mathrm{~g} / \mathrm{cm}^{3}\). a. What is the volume of a \(5.0\) -carat diamond? b. What is the mass in carats of a diamond measuring \(2.8 \mathrm{~mL}\) ?

A rectangular block has dimensions \(2.9 \mathrm{~cm} \times 3.5 \mathrm{~cm} \times 10.0 \mathrm{~cm}\). The mass of the block is \(615.0 \mathrm{~g}\). What are the volume and density of the block?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free