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Which of the following has the highest enthalpy content, and which the lowest at a given temperature: \(\mathrm{H}_{2} \mathrm{O}(\mathrm{s}), \mathrm{H}_{2} \mathrm{O}(l)\), or \(\mathrm{H}_{2} \mathrm{O}(g) ?\) Explain.

Short Answer

Expert verified
\(\mathrm{H}_2\mathrm{O}(g)\) has the highest enthalpy; \(\mathrm{H}_2\mathrm{O}(s)\) has the lowest.

Step by step solution

01

Understand the Problem

We need to determine the enthalpy content of water in its three different states: solid (ice, \(\mathrm{H}_2\mathrm{O}(s)\)), liquid (water, \(\mathrm{H}_2\mathrm{O}(l)\)), and gas (vapor, \(\mathrm{H}_2\mathrm{O}(g)\)). Enthalpy changes with phase transitions due to energy absorption or release.
02

Recognize State Enthalpy

In general, for a given substance, the enthalpy increases from solid to liquid to gas. This is because energy is required to overcome intermolecular forces: \(\mathrm{H}_2\mathrm{O}(s) \to \mathrm{H}_2\mathrm{O}(l)\) absorbs energy (melting), and \(\mathrm{H}_2\mathrm{O}(l) \to \mathrm{H}_2\mathrm{O}(g)\) requires even more energy (vaporization).
03

Rank the Enthalpy Content

Among the states of \(\mathrm{H}_2\mathrm{O}\), the gaseous state \(\mathrm{H}_2\mathrm{O}(g)\) has the highest enthalpy content because it requires the most energy for molecules to escape intermolecular attractions. Conversely, the solid state \(\mathrm{H}_2\mathrm{O}(s)\) has the lowest enthalpy as it involves less energy than other states.
04

Conclusion

Therefore, at a given temperature, \(\mathrm{H}_2\mathrm{O}(g)\) has the highest enthalpy content, while \(\mathrm{H}_2\mathrm{O}(s)\) has the lowest. This conclusion is based on the energy required to transition between different states of matter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phase Transitions
Phase transitions occur when a substance changes from one state of matter to another. For water, these transitions can be from solid (\(\mathrm{H}_2\mathrm{O}(s)\) or ice) to liquid (\(\mathrm{H}_2\mathrm{O}(l)\) or water), and then to gas (\(\mathrm{H}_2\mathrm{O}(g)\) or vapor).
During each of these transitions, energy is either absorbed or released, which affects the enthalpy content.
  • Solid to Liquid: known as melting, it absorbs energy.
  • Liquid to Gas: known as vaporization, it absorbs even more energy.
  • Gas to Liquid: known as condensation, releases energy.
  • Liquid to Solid: known as freezing, releases energy.
These energy changes are crucial for the enthalpy comparison between states.
State of Matter
The state of matter is a distinct form that different phases of matter take on. Common states include solid, liquid, and gas. Water is a great example as it naturally exists in all three states depending on the temperature and pressure conditions.
  • Solid: In the case of water, this is ice. Molecules are tightly packed and vibrate in place.
  • Liquid: Water is in its liquid form, with molecules free to move around but still moderately attracted to each other.
  • Gas: Water vapor, where molecules move freely and are far apart.
Moving from one state to another involves overcoming or reducing intermolecular forces, which impacts enthalpy.
Energy Absorption
Energy absorption is a key process during phase transitions. When a substance absorbs energy, its temperature or state can change.
  • Melting: When ice (\(\mathrm{H}_2\mathrm{O}(s)\)) absorbs heat, it turns into water (\(\mathrm{H}_2\mathrm{O}(l)\)).
  • Vaporization: When water (\(\mathrm{H}_2\mathrm{O}(l)\)) absorbs sufficient heat, it becomes steam (\(\mathrm{H}_2\mathrm{O}(g)\)).
  • This absorbed energy is stored as potential energy in molecular movements and is reflected in higher enthalpy.
Energy absorption facilitates the transition from a lower to a higher state of matter, increasing the enthalpy of the substance.
Intermolecular Forces
Intermolecular forces are the forces that hold molecules together in different states of matter. These include hydrogen bonds, dipole-dipole interactions, and van der Waals forces, varying in strength and consequences.
  • Solid: Strong intermolecular forces keep molecules closely packed, resulting in low enthalpy.
  • Liquid: Forces are moderate, allowing some freedom of movement, and therefore intermediate enthalpy.
  • Gas: Very weak forces as molecules move independently, leading to the highest enthalpy.
To transition from solid to liquid to gas, energy must be input to overcome these forces, explaining why gaseous states have a higher enthalpy content.

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Most popular questions from this chapter

How is the standard state of an element defined? Why do elements always have \(\Delta H_{\mathrm{f}}^{\circ}=0 ?\)

When \(1.045 \mathrm{~g}\) of \(\mathrm{CaO}\) is added to \(50.0 \mathrm{~mL}\) of water at \(25.0^{\circ} \mathrm{C}\) in a calorimeter, the temperature of the water increases to \(32.3^{\circ} \mathrm{C}\). Assuming that the specific heat of the solution is \(4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) and that the calorimeter itself absorbs a negligible amount of heat, calculate \(\Delta H\) in kilojoules \(/ \mathrm{mol} \mathrm{Ca}(\mathrm{OH})_{2}\) for the reaction $$\mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(a q)$$

A reaction is carried out in a cylinder fitted with a movable piston. The starting volume is \(V=5.00 \mathrm{~L}\), and the apparatus is held at constant temperature and pressure. Assuming that \(\Delta H=-35.0 \mathrm{~kJ}\) and \(\Delta E=-34.8 \mathrm{~kJ}\), redraw the piston to show its position after reaction. Does \(V\) increase, decrease, or remain the same?

The familiar "ether" used as an anesthetic agent is diethyl ether, \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\). Its heat of vaporization is \(+26.5 \mathrm{~kJ} / \mathrm{mol}\) at its boiling point. How much energy in kilojoules is required to convert 100 mL of diethyl ether at its boiling point from liquid to vapor if its density is \(0.7138 \mathrm{~g} / \mathrm{mL}\) ?

Instant cold packs used to treat athletic injuries contain solid \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) and a pouch of water. When the pack is squeezed, the pouch breaks and the solid dissolves, lowering the temperature because of the endothermic reaction $$\mathrm{NH}_{4} \mathrm{NO}_{3}(s) \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{NH}_{4} \mathrm{NO}_{3}(a q) \quad \DeltaH=+25.7 \mathrm{~kJ}$$ What is the final temperature in a squeezed cold pack that contains \(50.0 \mathrm{~g}\) of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) dissolved in \(125 \mathrm{~mL}\) of water? Assume a specific heat of \(4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\) for the solution, an initial temperature of \(25.0{ }^{\circ} \mathrm{C}\), and no heat transfer between the cold pack and the environment.

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