Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Tell whether the entropy changes for the following processes are likely to be positive or negative: (a) The fizzing of a newly opened can of soda (b) The growth of a plant from seed

Short Answer

Expert verified
(a) Positive, (b) Negative.

Step by step solution

01

Understanding Entropy

Entropy is a measure of disorder or randomness within a system. An increase in disorder generally results in a positive change in entropy, whereas a decrease in disorder leads to a negative change in entropy.
02

Analyzing Process (a)

Consider the fizzing of a newly opened can of soda. When the can is opened, carbon dioxide gas that was dissolved in the liquid is released into the atmosphere, increasing disorder as the gas molecules spread out and move freely compared to being confined in the liquid. Therefore, the entropy change is likely to be positive.
03

Analyzing Process (b)

Consider the growth of a plant from seed. This process involves the organization of cells and structures as the plant grows, resulting in a higher degree of order within the system of the plant itself. However, in the broader context of the environment, the overall entropy might still increase. Notably, for this exercise, we focus on the system level, where entropy change is generally considered negative.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy Change
Entropy change is a crucial concept in understanding the behavior and progress of various systems. Imagine entropy as a measure of disorder or randomness within a system. When the disorder in a system increases, we say there is a positive change in entropy. On the other hand, when we see a more ordered state arise, the entropy change is negative.

To grasp this concept, consider two scenarios involving different kinds of changes:
  • In a positive entropy change, gas molecules spread out. An example is when you open a soda can, releasing carbon dioxide gas, causing more chaos.
  • For a negative entropy change, think about organizing objects or materials, like when a plant organizes its cells to grow, creating more order.
Positive Entropy
Positive entropy occurs when disorder or randomness in a system increases. This can be seen when systems evolve from a structured state to a more disordered one.

Take the example of opening a can of soda:
  • When the soda is opened, the dissolved carbon dioxide gas escapes into the atmosphere.
  • This gas transition from being confined in the liquid to being dispersed freely in the air creates higher entropy.
  • The molecules moving freely demonstrate increased disorder, and thus, there is a positive change in entropy.
Positive entropy changes are a natural tendency in many reactions, often highlighting the spontaneous nature of these processes.
Negative Entropy
Negative entropy, or decreasing entropy, arises when a system becomes more ordered. This involves processes where randomness or disorder decreases, and structure or organization is enhanced.

For example, consider the growth of a plant from a seed:
  • As a plant grows, cells organize into complex tissues and structures.
  • This process involves energy and leads to a more ordered state within the plant.
  • In terms of the system of just the plant, the entropy here is negative as the plant becomes highly organized.
However, it is important to note that while the system itself may experience a negative entropy change, the overall entropy of the surroundings, including energy exchange, may tell a different story.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One of the steps in the cracking of petroleum into gasoline in. volves the thermal breakdown of large hydrocarbon molecules into smaller ones. For example, the following reaction might occur: $$\mathrm{C}_{11} \mathrm{H}_{24} \longrightarrow \mathrm{C}_{4} \mathrm{H}_{10}+\mathrm{C}_{4} \mathrm{H}_{8}+\mathrm{C}_{3} \mathrm{H}_{6}$$ Is \(\Delta S\) for this reaction likely to be positive or negative? Explain.

Is it possible for a reaction to be nonspontaneous yet exothermic? Explain.

When \(0.187 \mathrm{~g}\) of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), is burned in a bomb calorimeter, the temperature of both the water and the calorimeter rise by \(4.53^{\circ} \mathrm{C}\). Assuming that the bath contains \(250.0 \mathrm{~g}\) of water and that the heat capacity for the calorimeter is \(525 \mathrm{~J} /{ }^{\circ} \mathrm{C}\), calculate \(\mathrm{com}\) bustion energies \((\Delta E)\) for benzene in units of \(\mathrm{kJ} / \mathrm{g}\) and \(\mathrm{kJ} / \mathrm{mol}\).

Calculate \(\Delta H_{\mathrm{f}}^{\circ}\) in \(\mathrm{kJ} / \mathrm{mol}\) for benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), from the following data: $$\begin{aligned}2 \mathrm{C}_{6} \mathrm{H}_{6}(l)+15 \mathrm{O}_{2}(g) \longrightarrow 12 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \\ \Delta H^{\circ}=-6534 \mathrm{~kJ} \\ \Delta H_{\mathrm{f}}^{\circ}\left(\mathrm{CO}_{2}\right)=-393.5 \mathrm{~kJ} / \mathrm{mol} \\ \Delta H^{\circ} \mathrm{f}\left(\mathrm{H}_{2} \mathrm{O}\right)=-285.8 \mathrm{~kJ} / \mathrm{mol}\end{aligned}$$

When a bottle of perfume is opened, odorous molecules mix with air and slowly diffuse throughout the entire room. Is \(\Delta G\) for the diffusion process positive, negative, or zero? What about \(\Delta H\) and \(\Delta S\) for the diffusion?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free