Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Calculate formal charges on the \(\mathrm{C}\) and \(\mathrm{O}\) atoms in two resonance structures for acetic acid, the main component of vinegar. Decide which structure makes a larger contribution to the resonance hybrid.

Short Answer

Expert verified
The first structure contributes more to the resonance hybrid.

Step by step solution

01

Draw the Lewis Structures

First, we need to draw the two main resonance structures for acetic acid (CH₃COOH). The first structure shows the carbon double-bonded to oxygen (C=O) with a single bond to hydroxyl group (OH). In the second structure, consider the possibility of moving the electrons to show another resonance form (such as an enolate form).
02

Calculate Formal Charge for Carbon

To find the formal charge, use the formula: Formal charge = (Valence electrons) - (Non-bonding electrons) - 0.5*(Bonding electrons). For the carbon atom double-bonded to oxygen in the first structure: - Carbon has 4 valence electrons, 0 lone pairs, and 4 bonding pairs. - Formal charge = 4 - 0 - (4/2) = 0.
03

Calculate Formal Charge for Oxygen in First Structure

For the double-bonded oxygen (C=O): - Oxygen has 6 valence electrons, 4 non-bonding electrons, and 2 bonding pairs. - Formal charge = 6 - 4 - (2/2) = 0. For the single-bonded oxygen (OH group): - Oxygen has 6 valence electrons, 6 non-bonding electrons, and 1 bonding pair. - Formal charge = 6 - 6 - (2/2) = -1.
04

Calculate Formal Charges in Second Resonance Structure

In the second structure, assume that the carbon has a single bond to the oxygen (C-O) and that oxygen has taken a lone pair from carbon, resembling an enolate. For the carbon now singly bonded to oxygen: - Formal charge = 4 - 0 - (6/2) = +1. For the double-bonded oxygen, the formal charge remains 0, and for the single-bonded oxygen: - Formal charge = 6 - 6 - 1 = -1.
05

Compare the Resonance Structures

The first resonance structure, having formal charges of 0 for the carbon and 0 and -1 for oxygens, is more stable due to minimized charges and the negative charge on the more electronegative oxygen. The second structure, bearing a positive charge on carbon, is less favorable energetically.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resonance Structures
In chemistry, resonance structures are essential for understanding the stability and behavior of certain molecules. They offer various ways to represent the electron distribution in a molecule without changing the actual arrangement of atoms. This concept is crucial because some molecules can't be described by a single Lewis structure satisfactorily.

Resonance structures illustrate how electrons can be shifted within a molecule. By considering different resonance structures, chemists can better predict the most stable electron configuration. These structures don't exist independently in reality but are used to visualize potential states of electron distribution. The true representation of the molecule is called a resonance hybrid, which is a weighted average of all possible resonance structures. In acetic acid, for instance, resonance helps us understand the electron shifts between carbon, oxygen, and hydrogen atoms. This process accounts for the molecule’s stability and reactivity, especially when analyzing the effects of various resonance contributors on stability.
Lewis Structures
Lewis structures are diagrams that show the bonding between atoms and the lone pairs of electrons in a molecule. They are a way to represent molecules visually by depicting electron distribution around the atoms. In Lewis structures, we make use of dots to show lone electrons and lines to represent shared electron pairs that form a chemical bond.

The creation of Lewis structures involves a set of steps that begin with counting the total number of valence electrons in the molecule. Once you've determined this number, you arrange the atoms in a way that satisfies the octet rule as much as possible. The goal is to depict each atom reaching a stable electronic configuration by sharing or transferring electrons. Acetic acid, being an organic molecule, contains both single and double bonds that are important to feature accurately in its Lewis structure with respect to its resonance forms. By examining the Lewis structures of acetic acid's resonance forms, we can calculate formal charges and make predictions about molecular stability.
Acetic Acid
Acetic acid, commonly known as the primary component of vinegar, is represented by the chemical formula \( ext{CH}_3 ext{COOH}\). It is an important molecule in organic chemistry and everyday life. Structurally, acetic acid consists of a methyl group (\( ext{CH}_3\)) linked to a carboxylic acid group (\( ext{COOH}\)), making it a simple carboxylic acid.

Understanding the structure of acetic acid involves looking at the connections and bonds between its atomic components. The carbon atoms form the backbone, with the presence of a carbonyl group (a carbon double bonded to an oxygen, \( ext{C}=\text{O}\)) adjacent to the hydroxyl group (\( ext{OH}\)). These functional groups are significant because they contribute greatly to the chemical properties of acetic acid, including acidity and its ability to participate in chemical reactions through the exchange of protons.

By using resonance structures and Lewis structures, we can better appreciate how acetic acid exists in resonance forms, influencing its stability and reactivity. It's this understanding that allows chemists to predict and explain the diverse interactions and behaviors of acetic acid in both natural and industrial contexts.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The neutral OH molecule has been implicated in certain ozonedestroying processes that take place in the upper atmosphere. (a) Draw electron-dot structures for the OH molecule and the \(\mathrm{OH}^{-}\) ion. (b) Electron affinity can be defined for molecules just as it is defined for single atoms. Assuming that the electron added to \(\mathrm{OH}\) is localized in a single atomic orbital on one atom, identify which atom is accepting the electron, and give the \(n\) and \(l\) quantum numbers of the atomic orbital. (c) The electron affinity of \(\mathrm{OH}\) is similar to but slightly more negative than that of \(\mathrm{O}\) atoms. Explain.

In the cyanate ion, \(\mathrm{OCN}^{-}\), carbon is the central atom. (a) Draw as many resonance structures as you can for OCN , and assign formal charges to the atoms in each. (b) Which resonance structure makes the greatest contribution to the resonance hybrid? Which makes the least contribution? Explain.

There are two molecules with the formula \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O} .\) Draw electron-dot structures for both. (Hint: The connection of atoms is different in the two structures.)

Oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), is a mildly poisonous substance found in the leaves of rhubarb, spinach, and many other plants. (You'd have to eat about \(15 \mathrm{lbs}\). or so of spinach leaves to ingest a lethal amount.) If oxalic acid has a \(\mathrm{C}-\mathrm{C}\) single bond and no \(\mathrm{C}-\mathrm{H}\) bond, draw its electron-dot structure showing lone pairs and identifying any multiple bonds.

Draw an electron-dot structure for the following radicals: (a) \(\mathrm{ClO}_{2}\) (involved in depletion of stratospheric ozone) (b) Hydroxyl, OH (important in atmospheric chemistry, aging, and the development of disease) (c) Ethyl, \(\mathrm{C}_{2} \mathrm{H}_{5}\) (involved in synthesis of polyethylene polymer)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free