Chapter 4: Problem 95
Oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), is a toxic substance found in spinach leaves. What is the molarity of a solution made by dissolving \(12.0 \mathrm{~g}\) of oxalic acid in enough water to give \(400.0 \mathrm{~mL}\) of solution? How many milliliters of \(0.100 \mathrm{M}\) KOH would you need to titrate \(25.0 \mathrm{~mL}\) of the oxalic acid solution according to the following equation? $$ \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+2 \mathrm{KOH}(a q) \longrightarrow \mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) $$
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