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The odor of skunks is caused by chemical compounds called thiols. These compounds, of which butanethiol \(\left(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{~S}\right)\) is a representative example, can be deodorized by reaction with household bleach (NaOCl) according to the following equation: \(2 \mathrm{C}_{4} \mathrm{H}_{10} \mathrm{~S}(l)+\mathrm{NaOCl}(a q) \longrightarrow \mathrm{C}_{s} \mathrm{H}_{18} \mathrm{~S}_{2}(l)+\mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) How many grams of butanethiol can be deodorized by reaction with \(5.00 \mathrm{~mL}\) of \(0.0985 \mathrm{M} \mathrm{NaOCl} ?\)

Short Answer

Expert verified
0.0888 grams of butanethiol can be deodorized.

Step by step solution

01

Calculate Moles of NaOCl

To find out how much butanethiol can be deodorized, we first need to calculate the moles of NaOCl available. We have a volume of 5.00 mL (which is 0.005 L) and a concentration of 0.0985 M. The moles of NaOCl are calculated using the formula: \[ \text{moles of NaOCl} = \text{volume} \times \text{concentration} = 0.005 \times 0.0985 = 0.0004925 \text{ moles} \]
02

Use Stoichiometry to Determine Moles of Butanethiol

According to the balanced equation, 1 mole of NaOCl reacts with 2 moles of butanethiol \((\text{C}_4\text{H}_{10}\text{S})\). Using stoichiometry, we find the moles of butanethiol:\[ \text{moles of butanethiol} = 2 \times \text{moles of NaOCl} = 2 \times 0.0004925 = 0.000985 \text{ moles} \]
03

Calculate Mass of Butanethiol

To find the mass of butanethiol corresponding to the calculated moles, we need the molar mass of butanethiol. The molar mass of \( \text{C}_4 \text{H}_{10} \text{S} \) is calculated as follows: - Carbon (C): 12.01 g/mol, 4 atoms - Hydrogen (H): 1.01 g/mol, 10 atoms - Sulfur (S): 32.07 g/mol, 1 atom The molar mass of butanethiol is:\[ (4 \times 12.01) + (10 \times 1.01) + (32.07) = 90.19 \text{ g/mol} \]Now, calculate the mass:\[ \text{mass} = \text{moles} \times \text{molar mass} = 0.000985 \times 90.19 = 0.0888 \text{ g} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions occur when substances, called reactants, are transformed into different substances, called products. In the context of thiols and household bleach, a fascinating chemical reaction occurs. Thiols, such as butanethiol, are known for their strong and often unpleasant smells. This reaction involves butanethiol reacting with sodium hypochlorite (NaOCl), a common component in bleach. This transformation changes the chemical composition of butanethiol, thus eliminating its odor.
The balanced chemical equation for this reaction is: \[2 \text{C}_4\text{H}_{10}\text{S} + \text{NaOCl} \rightarrow \text{C}_8\text{H}_{18}\text{S}_2 + \text{NaCl} + \text{H}_2\text{O}\]
  • Reactants: Butanethiol (\(\text{C}_4\text{H}_{10}\text{S}\)) and Sodium hypochlorite (\(\text{NaOCl}\))
  • Products: A disulfide compound (\(\text{C}_8\text{H}_{18}\text{S}_2\)), Sodium chloride (\(\text{NaCl}\)), and Water (\(\text{H}_2\text{O}\))
This reaction is made possible through stoichiometry, which allows us to calculate the amount of reactants needed to produce a certain amount of product efficiently.
Molar Mass
Understanding molar mass is crucial when performing chemical calculations. Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). With the help of the molar mass, you can convert between the mass of a substance and the number of moles to participate in a reaction.
To compute the molar mass of butanethiol \((\text{C}_4\text{H}_{10}\text{S})\):
  • Carbon (C): 12.01 g/mol and there are 4 Carbon atoms, thus \(4 \times 12.01 = 48.04\) g/mol
  • Hydrogen (H): 1.01 g/mol and there are 10 Hydrogen atoms, thus \(10 \times 1.01 = 10.10\) g/mol
  • Sulfur (S): 32.07 g/mol and there is 1 Sulfur atom, hence its contribution remains \(32.07\) g/mol
The total molar mass of butanethiol is calculated as: \[ 48.04 + 10.10 + 32.07 = 90.19 \text{ g/mol}\]
This value allows us to find out how much butanethiol is involved in a chemical reaction by converting moles of butanethiol to grams.
Thiols
Thiols, also known as mercaptans, are a class of sulfur-containing organic compounds characterized by the presence of a sulfhydryl group \((-\text{SH})\). They are known for their strong and often unpleasant odors, which is why they are commonly associated with the smell of skunks.
Thiols are important in various applications:
  • Agriculture: Used as soil fumigants.
  • Industrials: Serving as an additive for anti-corrosion, especially in the petroleum industry.
  • Biological: Plays a role in the structure of proteins through the formation of disulfide bonds.
The reaction of thiols with bleach in deodorizing processes is particularly significant. When butanethiol is mixed with \(\text{NaOCl}\), the thiol component is oxidized to form a disulfide bond, transforming it into a less odorous compound. This is the principle used in household deodorizing products where an unpleasant smell is chemically neutralized.

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Most popular questions from this chapter

A sample weighing \(14.98 \mathrm{~g}\) and containing a small amount of copper was treated to give a solution containing aqueous \(\mathrm{Cu}^{2+}\) ions. Sodium iodide was then added to yield solid copper(I) iodide plus \(\mathrm{I}_{3}^{-}\) ion, and the \(\mathrm{I}_{3}^{-}\) was titrated with thiosulfate, \(\mathrm{S}_{2} \mathrm{O}_{3}^{2-}\). The titration required \(10.49 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) for complete reaction. What is the mass percent copper in the sample? The balanced equations are $$ \begin{aligned} &2 \mathrm{Cu}^{2+}(a q)+5 \Pi(a q) \longrightarrow 2 \operatorname{CuI}(s)+\mathrm{I}_{3}^{-}(a q) \\ &\mathrm{I}_{3}^{-}(a q)+2 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-}(a q) \longrightarrow 3 \mathrm{I}^{-}(a q)+\mathrm{S}_{4} \mathrm{O}_{6}^{2-}(a q) \end{aligned} $$

Classify each of the following reactions as a precipitation, acidbase neutralization, or oxidation-reduction: (a) \(\mathrm{S}_{8}(s)+8 \mathrm{O}_{2}(g) \rightarrow 8 \mathrm{SO}_{2}(g)\) (b) \(\mathrm{NiCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{~S}(a q) \rightarrow \mathrm{NiS}(s)+2 \mathrm{NaCl}(a q)\) (c) \(2 \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \rightarrow\) \(\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2} \mathrm{Ba}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)\)

Where in the periodic table are the most easily reduced elements found? The most easily oxidized?

Write balanced ionic equations for the following reactions: (a) Aqueous perchloric acid is neutralized by aqueous calcium hydroxide. (b) Aqueous sodium hydroxide is neutralized by aqueous acetic acid.

Assume that you have an aqueous mixture of \(\mathrm{NaNO}_{3}\) and \(\mathrm{AgNO}_{3}\). How could you use a precipitation reaction to separate the two metal ions?

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