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Write balanced ionic equations for the following reactions: (a) Aqueous hydrobromic acid is neutralized by aqueous calcium hydroxide. (b) Aqueous barium hydroxide is neutralized by aqueous nitric acid.

Short Answer

Expert verified
(a) H⁺(aq) + OH⁻(aq) → H₂O(l); (b) H⁺(aq) + OH⁻(aq) → H₂O(l).

Step by step solution

01

Write the Complete Molecular Equation for (a)

The reaction between aqueous hydrobromic acid (HBr) and aqueous calcium hydroxide (Ca(OH)₂) results in the formation of water and calcium bromide (CaBr₂). The molecular equation is:\[2 \text{HBr} (aq) + \text{Ca(OH)}_2 (aq) \rightarrow \text{CaBr}_2 (aq) + 2 \text{H}_2\text{O} (l)\]
02

Write the Complete Ionic Equation for (a)

Now, we will break down all the soluble ionic compounds into their constituent ions:\[2 \text{H}^+ (aq) + 2 \text{Br}^- (aq) + \text{Ca}^{2+} (aq) + 2 \text{OH}^- (aq) \rightarrow \text{Ca}^{2+} (aq) + 2 \text{Br}^- (aq) + 2 \text{H}_2\text{O} (l)\]
03

Cancel Out Spectator Ions for (a)

Spectator ions appear on both sides of the ionic equation. The spectator ions are \(\text{Ca}^{2+}\) and \(\text{Br}^-\) ions. Cancel them out:\[2 \text{H}^+ (aq) + 2 \text{OH}^- (aq) \rightarrow 2 \text{H}_2\text{O} (l)\]
04

Simplify the Net Ionic Equation for (a)

Finally, simplify the net ionic equation. Divide all coefficients by 2 to get:\[\text{H}^+ (aq) + \text{OH}^- (aq) \rightarrow \text{H}_2\text{O} (l)\]
05

Write the Complete Molecular Equation for (b)

For the neutralization of aqueous barium hydroxide \(\text{Ba(OH)}_2\) by aqueous nitric acid \(\text{HNO}_3\), the products formed are water and barium nitrate \(\text{Ba(NO}_3)_2\). The molecular equation is:\[\text{Ba(OH)}_2 (aq) + 2 \text{HNO}_3 (aq) \rightarrow \text{Ba(NO}_3)_2 (aq) + 2 \text{H}_2\text{O} (l)\]
06

Write the Complete Ionic Equation for (b)

Convert the molecular equation into an ionic one by dissociating all soluble compounds into ions:\[\text{Ba}^{2+} (aq) + 2 \text{OH}^- (aq) + 2 \text{H}^+ (aq) + 2 \text{NO}_3^- (aq) \rightarrow \text{Ba}^{2+} (aq) + 2 \text{NO}_3^- (aq) + 2 \text{H}_2\text{O} (l)\]
07

Cancel Out Spectator Ions for (b)

Identify and cancel the ions that appear on both sides of the equation, which are \(\text{Ba}^{2+}\) and \(\text{NO}_3^-\) ions:\[2 \text{OH}^- (aq) + 2 \text{H}^+ (aq) \rightarrow 2 \text{H}_2\text{O} (l)\]
08

Simplify the Net Ionic Equation for (b)

Simplify the resulting net ionic equation by dividing through by 2:\[\text{H}^+ (aq) + \text{OH}^- (aq) \rightarrow \text{H}_2\text{O} (l)\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutralization Reactions
Neutralization reactions are chemical processes where an acid and a base react to form water and a salt. These reactions are crucial in chemistry because they help in understanding how different compounds interact with each other.
In a typical neutralization reaction, hydrogen ions (\(\text{H}^+\)) from the acid combine with hydroxide ions (\(\text{OH}^-\)) from the base to create water (\(\text{H}_2\text{O}\)). This process not only reduces the acidity or basicity of the solution but also can produce a salt, such as calcium bromide (\(\text{CaBr}_2\)) or barium nitrate (\(\text{Ba(NO}_3)_2\)).
Neutralization reactions are useful in many real-world applications:
  • Cleaning products often rely on neutralization to target acidic or basic stains.
  • Our bodies use neutralization reactions in digestion and blood pH regulation.
  • Environmental management uses neutralization to treat acidic rain or waste products.

Understanding these reactions helps in predicting the outcomes and managing reactions in various scientific and industrial processes.
Spectator Ions
In many chemical reactions, not all ions participate directly in the reaction. These non-participating ions are called spectator ions.
Spectator ions are ions that appear unchanged on both sides of a chemical equation. They do not participate in the chemical change and remain in the aqueous solution throughout the reaction process.
Identifying spectator ions is important for simplifying ionic equations. In the given example, for both hydrobromic acid with calcium hydroxide and barium hydroxide with nitric acid reactions, \(\text{Ca}^{2+}\) and \(\text{Ba}^{2+}\) ions are spectator ions since they appear on both sides of the equation without undergoing any transformation.
Recognizing which ions are merely spectators allows chemists to focus on the actual chemical changes occurring in a reaction. This simplification leads to the derivation of the net ionic equation, making it easier to understand the reaction's essence.
Net Ionic Equation
A net ionic equation presents only the ions and molecules directly involved in the chemical reaction, stripping away the spectator ions.
This equation showcases what is most important in the reaction, highlighting the transformation of the involved reactants to their products. For the neutralization reactions given, the net ionic equation for both reactions simplifies to:\(\text{H}^+ (aq) + \text{OH}^- (aq) \rightarrow \text{H}_2\text{O} (l)\). This succinctly shows that the primary reaction is the formation of water from hydrogen and hydroxide ions.
The net ionic equation is especially valuable because it helps chemists understand the true basics of chemical reactivity and stoichiometry without superfluous information.
Creating a net ionic equation involves:
  • Writing the balanced molecular equation.
  • Breaking it down into the complete ionic equation.
  • Identifying and removing spectator ions.

This approach simplifies the study of reactions and provides a more streamlined view of chemical processes.

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Most popular questions from this chapter

In each of the following instances, tell whether the substance gains electrons or loses electrons in a redox reaction: (a) An oxidizing agent (b) A reducing agent (c) A substance undergoing oxidation (d) A substance undergoing reduction

Nitrogen can have several different oxidation numbers ranging in value from \(-3\) to \(+5\). (a) Write the formula and give the name of the nitrogen oxide compound in which nitrogen has an oxidation number of \(+1,+2,+4\), and \(+5\). (b) Based on oxidation numbers, which nitrogen oxide from part (a) cannot react with molecular oxygen?

Assign oxidation numbers to each element in the following ions: (a) \(\mathrm{Cr}(\mathrm{OH})_{4}^{-}\) (b) \(\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2-}\) (c) \(\mathrm{NO}_{3}^{-}\) (d) \(\mathrm{MnO}_{4}{ }^{2-}\) (e) \(\mathrm{HPO}_{4}{ }^{2-}\) (f) \(\mathrm{V}_{2} \mathrm{O}_{7}{ }^{4-}\)

The odor of skunks is caused by chemical compounds called thiols. These compounds, of which butanethiol \(\left(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{~S}\right)\) is a representative example, can be deodorized by reaction with household bleach (NaOCl) according to the following equation: \(2 \mathrm{C}_{4} \mathrm{H}_{10} \mathrm{~S}(l)+\mathrm{NaOCl}(a q) \longrightarrow \mathrm{C}_{s} \mathrm{H}_{18} \mathrm{~S}_{2}(l)+\mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) How many grams of butanethiol can be deodorized by reaction with \(5.00 \mathrm{~mL}\) of \(0.0985 \mathrm{M} \mathrm{NaOCl} ?\)

On heating a \(0.200 \mathrm{~g}\) sample of a certain semimetal \(\mathrm{M}\) in air, the corresponding oxide \(\mathrm{M}_{2} \mathrm{O}_{3}\) was obtained. When the oxide was dissolved in aqueous acid and titrated with \(\mathrm{KMnO}_{4}, 10.7 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{MnO}_{4}^{-}\) was required for complete reaction. The unbalanced equation is \(\mathrm{H}_{3} \mathrm{MO}_{3}(a q)+\mathrm{MnO}_{4}^{-}(a q) \longrightarrow \mathrm{H}_{3} \mathrm{MO}_{4}(a q)\) \(+\mathrm{Mn}^{2+}(a q)(\) in acid \()\) (a) Balance the equation. (b) How many moles of oxide were formed, and how many moles of semimetal were in the initial \(0.200 \mathrm{~g}\) sample? (c) What is the identity of the semimetal M?

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