Chapter 22: Problem 25
Write electron-dot structures for each of the following molecules, and use VSEPR theory to predict the structure of each: (a) \(\mathrm{H}_{2} \mathrm{~S}\) (b) \(\mathrm{SO}_{2}\) (c) \(\mathrm{SO}_{3}\)
Short Answer
Expert verified
H₂S is bent; SO₂ is bent; SO₃ is trigonal planar.
Step by step solution
01
Electron-Dot Structure for H2S
Start with counting the valence electrons. Hydrogen has 1 valence electron, and each sulfur atom has 6 valence electrons. Therefore, H₂S has a total of \(1 \times 2 + 6 = 8\) valence electrons. Sulfur is the central atom. Place H atoms around the S atom, and use 2 electrons to form each S-H bond. Distribute remaining electrons to give sulfur a complete octet. The electron-dot structure is ``` H-S-H```with 2 lone pairs on the S atom.
02
VSEPR Prediction for H2S
With two bonded pairs and two lone pairs on the central sulfur atom, VSEPR theory predicts a bent or V-shaped molecular geometry for H₂S.
03
Electron-Dot Structure for SO2
Sulfur has 6 valence electrons and each oxygen also has 6. Therefore, SO₂ has a total of \(6 + 6 \times 2 = 18\) valence electrons. Sulfur is the central atom. To satisfy the octet rule, double bond each O to the S and leave two lone pairs on the sulfur atom. The structure is:```O=S=O```with two lone pairs on the sulfur atom and one lone pair per oxygen atom.
04
VSEPR Prediction for SO2
With two bonding pairs and one lone pair on the central sulfur atom, using VSEPR theory, SO₂ has a bent geometry.
05
Electron-Dot Structure for SO3
Sulfur has 6 valence electrons, and each oxygen has 6, giving us a total of \(6 + 6 \times 3 = 24\) valence electrons for SO₃. Place the sulfur in the center and form double bonds with each of the oxygen atoms. All atoms achieve an octet:``` O || S || O || O```No lone pairs remain on the sulfur atom, and each oxygen atom has two lone pairs.
06
VSEPR Prediction for SO3
With three bonding pairs and no lone pairs on the central sulfur atom, VSEPR theory predicts a trigonal planar geometry for SO₃.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron-Dot Structures
Imagine using a simple drawing to figure out how atoms might connect in a molecule. That's what electron-dot structures, also known as Lewis structures, can help us do! They are diagrams showing the arrangement of valence electrons around atoms within a molecule. Each dot represents a valence electron, and lines represent bonds between them.
Electron-dot structures begin with identifying the number of valence electrons each atom brings. Valence electrons are found in the atom's outermost shell and are critical because they are involved in chemical bonding. You then decide which atom will be central. Typically, it's the least electronegative one because it can share electrons more easily—a common choice in molecules is sulfur or carbon.
Once you've drawn the central atom, you connect other atoms using dots or lines to form bonds. The rest of the dots are placed to ensure each atom fulfills the octet rule (or duet for hydrogen), meaning it has eight electrons in its outer shell (or two in the case of H). The goal is to have all atoms stable. For example, in the molecule \( ext{H}_2 ext{S}\), sulfur is the central atom and forms bonds with two hydrogen atoms, leaving it with extra pairs of electrons, called lone pairs. Drawing electron-dot structures requires some practice but provides insights into where bonds and electrons reside in a molecule. This picture helps predict the shape it might naturally adopt.
Electron-dot structures begin with identifying the number of valence electrons each atom brings. Valence electrons are found in the atom's outermost shell and are critical because they are involved in chemical bonding. You then decide which atom will be central. Typically, it's the least electronegative one because it can share electrons more easily—a common choice in molecules is sulfur or carbon.
Once you've drawn the central atom, you connect other atoms using dots or lines to form bonds. The rest of the dots are placed to ensure each atom fulfills the octet rule (or duet for hydrogen), meaning it has eight electrons in its outer shell (or two in the case of H). The goal is to have all atoms stable. For example, in the molecule \( ext{H}_2 ext{S}\), sulfur is the central atom and forms bonds with two hydrogen atoms, leaving it with extra pairs of electrons, called lone pairs. Drawing electron-dot structures requires some practice but provides insights into where bonds and electrons reside in a molecule. This picture helps predict the shape it might naturally adopt.
Molecular Geometry Prediction
Predicting the shape of a molecule involves thinking like the bonds are moving away from each other as far as possible. Visualize this as playing with balloons, where each balloon represents an electron pair.
VSEPR theory (Valence Shell Electron Pair Repulsion theory) assists in this task. It suggests that electron pairs around a central atom will arrange themselves to minimize repulsion, leading to a shape that dictates the molecule's properties.
Each molecule has a central atom strategically surrounded by other atoms or lone pairs. This distribution affects the space around the central atom, and VSEPR predicts the resulting geometry, like these examples:
VSEPR theory (Valence Shell Electron Pair Repulsion theory) assists in this task. It suggests that electron pairs around a central atom will arrange themselves to minimize repulsion, leading to a shape that dictates the molecule's properties.
Each molecule has a central atom strategically surrounded by other atoms or lone pairs. This distribution affects the space around the central atom, and VSEPR predicts the resulting geometry, like these examples:
- For \( ext{H}_2 ext{S}\), with two bonding pairs (to hydrogen) and two lone pairs, the repulsion from the lone pairs makes the shape bent or V-shaped.
- In \( ext{SO}_2\), there are two oxygen atom bonds and one lone pair on the sulfur, again leading to a bent shape.
- With \( ext{SO}_3\), the sulfur has no lone pairs, just three double bonds to oxygen, resulting in a trigonal planar shape.
Valence Electrons
Valence electrons are the heart of chemistry! These electrons are in the outermost shell of an atom and are crucial for fostering chemical bonds. Knowing how many valence electrons each atom has can determine how a molecule forms and behaves.
In simple terms, valence electrons are like social points for atoms. They dictate how readily atoms can pair up with others—either by sharing, giving away, or borrowing electrons.
Let's take sulfur, for instance, which has six valence electrons. In molecules like \( ext{H}_2 ext{S}\), \( ext{SO}_2\), and \( ext{SO}_3\), sulfur's valence electrons play a key role in shaping multiple bonds with oxygen or hydrogen:
In simple terms, valence electrons are like social points for atoms. They dictate how readily atoms can pair up with others—either by sharing, giving away, or borrowing electrons.
Let's take sulfur, for instance, which has six valence electrons. In molecules like \( ext{H}_2 ext{S}\), \( ext{SO}_2\), and \( ext{SO}_3\), sulfur's valence electrons play a key role in shaping multiple bonds with oxygen or hydrogen:
- \( ext{H}_2 ext{S}\) has eight total valence electrons, where each hydrogen contributes one.
- \( ext{SO}_2\) has eighteen valence electrons (three sixes: one from sulfur, two from each oxygen).
- In \( ext{SO}_3\), the count rises to twenty-four valence electrons (also from oxygen and sulfur combined).