Chapter 22: Problem 21
The dimerization of \(\mathrm{NO}_{2}\) to form \(\mathrm{N}_{2} \mathrm{O}_{4}\) is an exothermic equilibrium reaction described in this section. Which substance does the equilibrium favor at high temperatures?
Short Answer
Expert verified
The equilibrium favors \(NO_2\) at high temperatures.
Step by step solution
01
Understand the Reaction
The dimerization of nitrogen dioxide \(NO_2\) to form \(N_2O_4\) can be represented by the chemical equation: \(2NO_2
ightleftharpoons N_2O_4\). This is an exothermic reaction, meaning that it releases heat when moving from reactants \(NO_2\) to products \(N_2O_4\).
02
Consider Le Chatelier's Principle
Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the system will adjust itself to partially counteract the effect of the disturbance. In the case of an exothermic reaction, increasing the temperature adds heat to the system.
03
Predict the Effect of Temperature Increase
According to Le Chatelier's Principle, increasing the temperature of an exothermic reaction will shift the equilibrium position to counteract the added heat. Therefore, the system will favor the endothermic direction, which in this case is the reverse reaction: \(N_2O_4\) decomposing back to \(2NO_2\).
04
Equilibrium at High Temperature
At high temperatures, the equilibrium will favor \(NO_2\) rather than \(N_2O_4\), as the reaction shifts left to absorb additional heat in the endothermic direction.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equilibrium reactions
In chemical systems, equilibrium reactions are fascinating because they involve a dynamic balance between reactants and products. For the dimerization of nitrogen dioxide (\(2NO_2 \rightleftharpoons N_2O_4\)), the concept of chemical equilibrium plays a significant role. At this stage, both the forward reaction (which forms \(N_2O_4\)) and the reverse reaction (which breaks it down into \(NO_2\)) occur at equal rates. This results in a stable concentration of reactants and products over time.
- Equilibrium does not mean reactions stop; instead, they happen simultaneously and continuously.
- The position of equilibrium in an exothermic reaction like this one influences how much \(NO_2\) or \(N_2O_4\) is present at any time.
Le Chatelier's Principle
Le Chatelier's Principle is a cornerstone of understanding how equilibrium reactions respond to changes. It essentially states that if a system at equilibrium experiences a change in concentration, temperature, or pressure, the system will adjust to partially counteract that change. For our reaction, \(2NO_2 \rightleftharpoons N_2O_4\), when we alter the conditions, this principle helps us predict the direction of the shift.
- If the concentration of \(NO_2\) increases, the equilibrium will shift to produce more \(N_2O_4\).
- Adding heat to an exothermic reaction disturbs the balance, as the system minimizes the effect by favoring the endothermic reverse reaction.
Exothermic reactions
Exothermic reactions are those that release energy, usually in the form of heat. In the case of dimerization of \(NO_2\) to \(N_2O_4\), this process releases heat energy into the surroundings. The general equation \(2NO_2 \rightleftharpoons N_2O_4 + ext{heat}\) explains why it's classified as exothermic.
- When these reactions proceed in the forward direction, they give off energy, making the surroundings warmer.
- Having energy as one of the products means the reaction's equilibrium is sensitive to temperature changes.
Temperature effects on equilibrium
Temperature effects on equilibrium reactions are intriguing, particularly because of their impact on the direction of the reaction. In exothermic reactions like \(2NO_2 \rightleftharpoons N_2O_4\), temperature changes lead to significant shifts.Increasing temperature in such a reaction introduces additional heat. According to Le Chatelier’s Principle, this prompts the equilibrium to move in the endothermic direction to counterbalance the change.
- For the reaction involving \(NO_2\) and \(N_2O_4\), the endothermic reaction is the breakdown of \(N_2O_4\) back to \(NO_2\).
- This means that higher temperatures will favor the decomposition of \(N_2O_4\), increasing the concentration of \(NO_2\).