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Which of the following complexes can exist as diastereoisomers? (a) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{4}\right]^{-}\) (b) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{S} \mathrm{Br}\right]^{2+}\) (c) \(\left[\mathrm{FeCl}_{2}(\mathrm{NCS})_{2}\right]^{2-}\) (tetrahedral) (d) \(\left[\mathrm{PtCl}_{2} \mathrm{Br}_{2}\right]^{2-}\) (square planar)

Short Answer

Expert verified
Complex (a) and (d) can exist as diastereoisomers.

Step by step solution

01

Analyze Complex (a)

The complex \( \left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{2}\mathrm{Cl}_{4}\right]^{-} \) is an octahedral coordination compound. For a complex to exhibit diastereoisomerism, it often requires the presence of chiral centers or different spatial arrangements that aren't mirror images (i.e., geometric isomerism). This complex can have different arrangements of \( \mathrm{NH}_3 \) and \( \mathrm{Cl} \) ligands as cis and trans-isomers, which are not mirror images. Thus, this complex can exist as diastereoisomers.
02

Analyze Complex (b)

The complex \( \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3}\mathrm{Br}\right]^{2+} \) is incorrect as presented. Assuming it should be \( \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\mathrm{Br}\right]^{2+} \), it is an octahedral complex. This complex cannot form diastereoisomers because there are no different spatial arrangements for a single \( \mathrm{Br} \) that can create non-superimposable, non-mirror image stereochemistry.
03

Analyze Complex (c)

The complex \( \left[\mathrm{FeCl}_{2}(\mathrm{NCS})_{2}\right]^{2-} \) is tetrahedral. Tetrahedral complexes with two different types of ligands do not show geometric isomerism because all angles are 109.5°, leading to equivalent positions for all ligands, thus no diastereoisomers are possible.
04

Analyze Complex (d)

The complex \( \left[\mathrm{PtCl}_{2}\mathrm{Br}_{2}\right]^{2-} \) is square planar. In square planar complexes, when there are two pairs of different monodentate ligands, it can exhibit geometric isomerism (cis and trans forms). Therefore, this complex can exist as diastereoisomers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diastereoisomers
Diastereoisomers are a fascinating aspect of chemistry, especially in coordination complexes. These are stereoisomers that are not mirror images of each other, which allows them to have distinct spatial arrangements. They can arise in coordination complexes featuring metal centers with ligands arranged differently.
One key point about diastereoisomers is that they usually involve different geometries such as cis and trans forms, as seen in some octahedral and square planar complexes.
  • In an octahedral complex, diastereoisomerism often occurs when different ligands can be swapped between adjacent (cis) and opposite (trans) positions around a metal center.
  • For square planar complexes, the arrangement on a flat plane allows certain complexes to exhibit cis and trans forms depending on the arrangement of differing ligands.
This difference in spatial arrangement leads them to have different physical and chemical properties, making them significant in various chemical reactions and industrial applications.
Geometric Isomerism
Geometric isomerism is a type of stereoisomerism that is crucial in understanding the structural arrangement of coordination complexes. It occurs due to different positions of ligands around the central metal atom without breaking any bonds.
  • For example, in octahedral complexes, which have six ligands around a metal, such isomerism can lead to cis and trans configurations, particularly when the ligands are not identical.
  • In square planar complexes, geometric isomerism happens when there are two pairs of identical ligands, allowing for different spatial configurations.
The distinct configuration affects the physical and chemical properties of the complexes, such as color, magnetic properties, and reactivity. Understanding geometric isomerism is therefore essential for both academic studies and practical applications in chemistry.
Octahedral Complexes
Octahedral complexes are a common and intriguing category within coordination chemistry. These complexes consist of a central metal atom surrounded symmetrically by six ligands, forming a structure similar to an octahedron.
This geometry allows for a variety of isomeric forms, which impacts their chemical behavior. Geometric isomerism is prevalent among such complexes due to the multiple possible arrangements of ligands.
  • Cis and trans isomers can form when there are two or more different types of ligands, which do not equally share all positions around the metal.
  • These complexes are particularly common with transition metals, and their properties can be precisely tailored by careful selection of ligands.
The versatility and diversity of octahedral complexes make them a prime area of study in both developing new catalytic compounds and understanding fundamental chemical principles.
Square Planar Complexes
Square planar complexes are structured with four ligands positioned on a single plane around the central metal atom, forming a square shape. This configuration is particularly prevalent with d8 metal ions, such as platinum or palladium.
Unlike tetrahedral complexes, square planar complexes can readily display geometric isomerism.
  • The classic example involves the presence of two pairs of different ligands, which can be arranged to form cis or trans isomers.
  • These geometric forms lead to significantly different properties such as solubility, stability, and even biological activity, making these isomers critical in pharmaceuticals.
Understanding square planar complexes is essential because they form the basis for many important catalytic and therapeutic compounds, highlighting their importance in industrial and medical chemistry.

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Most popular questions from this chapter

For each of the following complexes, draw a crystal field energylevel diagram, assign the electrons to orbitals, and predict the number of unpaired electrons: (a) \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (square planar) (b) \(\left[\mathrm{MnCl}_{4}\right]^{2-}\) (tetrahedral) (c) \(\left[\mathrm{Co}(\mathrm{NCS})_{4}\right]^{2-}\) (tetrahedral) (d) \(\left[\mathrm{Cu}(\mathrm{en})_{2}\right]^{2+}\) (square planar)

Write the formula for each of the following: (a) Tetraamminezinc(II) nitrate, the compound formed when zinc nitrate is treated with an excess of ammonia (b) Tetracarbonylnickel(0), the first metal carbonyl (prepared in 1888 ) and an important compound in the industrial refining of nickel metal (c) Potassium amminetrichloroplatinate(II), a compound that contains a square planar anion (d) The dicyanoaurate(I) ion, an ion important in the extraction of gold from its ores

Consider the octahedral complex [Co(en)(dien)Cl] \(]^{2+}\), where dien \(=\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{CH}_{2} \mathrm{NHCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\), which can be abbreviated \(\mathrm{N}\) \(\mathrm{N}\) \(\mathrm{N}\) (a) The dien (diethylenetriamine) ligand is a tridentate ligand. Explain what is meant by "tridentate" and why dien can act as a tridentate ligand. (b) Draw all possible stereoisomers of \([\mathrm{Co}(\mathrm{en})(\text { dien }) \mathrm{Cl}]^{2+}\) (dien is a flexible ligand). Which stereoisomers are chiral, and which are achiral?

There are three coordination compounds with the empirical formula \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\) in which all the nitrite ions are bonded through the \(\mathrm{N}\) atom. Two isomers have the same molar mass but different nonzero dipole moments. The third compound is a salt with singly charged ions and a molar mass twice that of the other compounds. (a) Draw the structures of the isomeric compounds. (b) What is the chemical formula of the third compound?

Conceptual PROBLEM How does the effective nuclear charge, \(Z_{\text {eff }}\) vary from left to right across the first transition series? $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|} \hline \mathrm{Sc} & \mathrm{Ti} & \mathrm{V} & \mathrm{Cr} & \mathrm{Mn} & \mathrm{Fe} & \mathrm{Co} & \mathrm{Ni} & \mathrm{Cu} & \mathrm{Zn} \\ \hline \end{array} $$ Based on the variation in \(Z_{\mathrm{eff}}\) (a) Which \(\mathrm{M}^{2+}\) ion \((\mathrm{M}=\mathrm{Ti}-\mathrm{Zn})\) should be the strongest reducing agent? Which should be the weakest? (b) Which oxoanion \(\left(\mathrm{VO}_{4}{ }^{3-}, \mathrm{CrO}_{4}^{2-}, \mathrm{MnO}_{4}^{2-}\right.\), or \(\left.\mathrm{FeO}_{4}{ }^{2-}\right)\) should be the strongest oxidizing agent? Which should be the weakest?

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