Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the systematic name for each of the following compounds? (a) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) (b) \(\operatorname{Cr}(\mathrm{CO})_{6}\) (c) \(\mathrm{K}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\) (d) \(\left[\mathrm{Co}(\mathrm{en})_{2}\left(\mathrm{NH}_{3}\right) \mathrm{CN}\right] \mathrm{Cl}_{2}\)

Short Answer

Expert verified
(a) Tetraamminecopper(II) sulfate; (b) Hexacarbonylchromium(0); (c) Potassium tris(oxalato)ferrate(III); (d) Diethylenediamineamminecyano cobalt(III) chloride.

Step by step solution

01

Name the Coordination Entity for Compound (a)

For compound (a), \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\), the complex ion is \([\mathrm{Cu}(\mathrm{NH}_3)_4]^{2+}\). Copper has a +2 oxidation state. The ligand \(\mathrm{NH}_3\) is ammonia and is named "ammine." Therefore, the coordination entity is named as tetraamminecopper(II).
02

Name the Anion for Compound (a)

The anion is sulfate (\(\mathrm{SO}_{4}^{2-}\)).
03

Combine Names for Compound (a)

Combine the coordination entity with the anion: Tetraamminecopper(II) sulfate.
04

Name the Compound (b)

For \(\operatorname{Cr}(\mathrm{CO})_{6}\), the ligand \(\mathrm{CO}\) is carbonyl and the complex is neutral, so we name the metal without modification. The compound is named hexacarbonylchromium(0).
05

Name the Coordination Entity for Compound (c)

For compound (c), \(\mathrm{K}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)_{3}\right]\), identify \(\mathrm{Fe}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)_{3}^{3-}\). Oxalate \((\mathrm{C}_{2}\mathrm{O}_{4}^{2-})\) is a bidentate ligand. Iron has a +3 oxidation state. The complex is named as tris(oxalato)ferrate(III).
06

Name the Cation for Compound (c)

The cation is potassium (\(\mathrm{K}^{+}\)).
07

Combine Names for Compound (c)

Combine the cation with the coordination entity: Potassium tris(oxalato)ferrate(III).
08

Name the Coordination Entity for Compound (d)

For compound (d), \([\mathrm{Co}(\mathrm{en})_{2}(\mathrm{NH}_{3})\mathrm{CN}] \mathrm{Cl}_{2}\), \(\mathrm{en}\) is ethylenediamine, a bidentate ligand, and \(\mathrm{NH}_{3}\) and \(\mathrm{CN}^-\) are monodentate ligands. Cobalt has a +3 oxidation state. The coordination entity is named as diethylenediamineamminecyano cobalt(III).
09

Name the Anion for Compound (d)

The anion is chloride (\(\mathrm{Cl}_2\)).
10

Combine Names for Compound (d)

Combine the coordination entity with the anion: Diethylenediamineamminecyano cobalt(III) chloride.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Systematic Naming in Coordination Chemistry
Systematic naming in coordination chemistry helps us ensure we have a clear and standard way to describe complex compounds. This avoids confusion and makes communication easier across the scientific community.
In coordination compounds, the systematic name typically includes:
  • The identity of the ligands around the central metal ion
  • The oxidation state of the metal
  • The structure and order of the compound
For example, a compound like \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) is named based on its coordination entity \([\mathrm{Cu}(\mathrm{NH}_3)_4]^{2+}\) and its sulfate anion. Each ligand, like \(\mathrm{NH}_3\), is given a specific name—in this case, "ammine." The metal's oxidation state is indicated by a Roman numeral following its name, like "Copper(II)."
This results in the full name: "tetraamminecopper(II) sulfate." This systematic approach helps identify exactly what each compound is composed of.
Understanding Ligands
Ligands play a major role in forming coordination complexes. A ligand is an ion or molecule that donates at least one pair of electrons to a central metal atom or ion.
The interactions between ligands and metals are essential for stability and the overall characteristics of the complex.
Here's how ligands are classified in coordination chemistry:
  • Monodentate: Ligands that donate a single pair of electrons. Example – \(\mathrm{NH}_{3}\) (ammonia), \(\mathrm{CN}^-\) (cyano)
  • Bidentate: Ligands that can donate two electron pairs. Example – \(\mathrm{C}_{2}\mathrm{O}_{4}^{2-}\) (oxalate), \(\mathrm{en}\) (ethylenediamine)
These ligands form coordinate bonds with the metal center, impacting properties like stability and reactivity. For instance, in \(\mathrm{K}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2}\mathrm{O}_{4}\right)_{3}\right]\), bidentate oxalate ligands create a stable chelate with the iron ion.
Determining Oxidation States
The oxidation state of the central metal in a coordination compound reveals valuable information about its electronic structure and reactivity.
It is typically a positive integer representing the number of electrons the metal has effectively "lost" to the surrounding ligands.
To determine the oxidation state:
  • Assign a charge of 0 to neutral ligands like \(\mathrm{NH}_{3}\) or \(\mathrm{CO}\).
  • Assign the known charge to ionic ligands, such as -2 for oxalate \((\mathrm{C}_2\mathrm{O}_4^{2-})\) or -1 for cyano \((\mathrm{CN}^-)\).
  • Combine these with the overall charge of the complex to solve for the metal's oxidation state.
For instance, in \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\), \(\mathrm{NH}_3\) is neutral, and assigning these charges leads to understanding copper is in a +2 oxidation state.
Foundations of Coordination Chemistry
Coordination chemistry explores the structure and behavior of complexes formed between transition metals and ligands.
This field underscores the bond formation between metals, which often involve d-orbitals, and surrounding ligands.
Key aspects of coordination chemistry include:
  • The coordination number, which is the count of ligand attachment points to the central metal, varying widely from 2 to 8 or more.
  • The geometry of complexes, which can be linear, square planar, tetrahedral, octahedral, etc., based on coordination number and ligand type.
  • Stability of complexes, influenced by the nature of the metal, the ligands, and the metal-ligand interactions.
An example is \(\operatorname{Cr}(\mathrm{CO})_{6}\), which is hexacoordinate and exhibits an octahedral geometry due to the symmetrical distribution of the carbonyl ligands. Understanding these aspects is crucial for predicting and controlling the chemical behavior of coordination compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw a crystal field energy-level diagram, assign the electrons to orbitals, and predict the number of unpaired electrons for each of the following: (a) \(\left[\mathrm{Cu}(\mathrm{en})_{3}\right]^{2+}\) (b) \(\left[\mathrm{FeF}_{6}\right]^{3-}\) (c) \(\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}\) (low-spin)

Nickel(II) complexes with the formula \(\mathrm{NiX}_{2} \mathrm{~L}_{2}\), where \(\mathrm{X}^{-}\) is \(\mathrm{Cl}\) or N-bonded \(\mathrm{NCS}^{-}\) and \(\mathrm{L}\) is the monodentate triphenylphosphine ligand \(\mathrm{P}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3}\), can be square planar or tetrahedral. (a) Draw crystal field energy-level diagrams for a square planar and a tetrahedral nickel(II) complex, and show the popula- tion of the orbitals. (b) If \(\mathrm{NiCl}_{2} \mathrm{~L}_{2}\) is paramagnetic and \(\mathrm{Ni}(\mathrm{NCS})_{2} \mathrm{~L}_{2}\) is diamagnetic, which of the two complexes is tetrahedral and which is square planar? (c) Draw possible structures for each of the \(\mathrm{NiX}_{2} \mathrm{~L}_{2}\) complexes, and tell which ones have a dipole moment.

The \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) ion is violet, and \(\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}\) is yellow. Ex- plain this difference using crystal field theory. Use the colors to order \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CN}^{-}\) in the spectrochemical series.

Draw the structure of all isomers of the octahedral complex \(\left[\mathrm{NbX}_{2} \mathrm{Cl}_{4}\right]^{-}\left(\mathrm{X}=\mathrm{NCS}^{-}\right)\), and identify those that are linkage isomers.

Spinach contains a lot of iron but is not a good source of dietary iron because nearly all the iron is tied up in the oxalate complex \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\) (a) The formation constant \(K_{\mathrm{f}}\) for \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\) is \(3.3 \times 10^{20}\). Calculate the equilibrium concentration of free \(\mathrm{Fe}^{3+}\) in a \(0.100 \mathrm{M}\) solution of \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\). (Ignore any acid-base reactions.) (b) Under the acidic conditions in the stomach, the \(\mathrm{Fe}^{3+}\) concentration should be greater because of the reaction $$ \begin{aligned} \left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}(a q) &+6 \mathrm{H}_{3} \mathrm{O}^{+}(a q) \\ \mathrm{Fe}^{3+}(a q)+3 \mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \end{aligned} $$ Show, however, that this reaction is nonspontaneous under standard-state conditions. (For \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}, K_{\mathrm{a} 1}=5.9 \times 10^{-2}\) and \(\left.K_{\mathrm{a} 2}=6.4 \times 10^{-5} .\right)\) (c) Draw a crystal field energy-level diagram for \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\), and predict the number of unpaired electrons. \(\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\right.\) is a weak-field bidentate ligand.) (d) Draw the structure of \(\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-}\). Is the complex chiral or achiral?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free