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Which of the following gives a buffer solution when equal volumes of the two solutions are mixed? (a) \(0.10 \mathrm{M} \mathrm{HF}\) and \(0.10 \mathrm{M} \mathrm{NaF}\) (b) \(0.10 \mathrm{M} \mathrm{HF}\) and \(0.10 \mathrm{M} \mathrm{NaOH}\) (c) \(0.20 \mathrm{M} \mathrm{HF}\) and \(0.10 \mathrm{M} \mathrm{NaOH}\) (d) \(0.10 \mathrm{M} \mathrm{HCl}\) and \(0.20 \mathrm{M} \mathrm{NaF}\)

Short Answer

Expert verified
Options (a) and (c) form buffer solutions.

Step by step solution

01

Identify the Requirements for a Buffer

A buffer solution consists of a weak acid and its conjugate base or a weak base and its conjugate acid. It can also be made from a weak acid and a strong base in the correct proportions or vice versa.
02

Analyze Option (a)

Option (a) consists of 0.10 M HF and 0.10 M NaF. HF is a weak acid and NaF provides the conjugate base F⁻. This forms a buffer solution since it contains a weak acid and its conjugate base.
03

Analyze Option (b)

Option (b) consists of 0.10 M HF and 0.10 M NaOH. Upon mixing, HF will react with NaOH, a strong base, to form F⁻, but all HF will be neutralized. Therefore, this does not form a buffer solution as the weak acid is completely consumed.
04

Analyze Option (c)

Option (c) consists of 0.20 M HF and 0.10 M NaOH. Mixing them in equal volumes will result in HF partially reacting with NaOH, forming some F⁻ and leaving some HF unreacted. This creates a mixture of weak acid (HF) and its conjugate base (F⁻), forming a buffer solution.
05

Analyze Option (d)

Option (d) consists of 0.10 M HCl and 0.20 M NaF. HCl is a strong acid which will fully dissociate, leaving no weak acid. Therefore, this does not form a buffer solution as there is no weak acid/base involved.
06

Determine the Correct Answer

Only options (a) and (c) satisfy the conditions required for forming a buffer solution: a weak acid and its conjugate base in suitable proportions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weak Acid
A weak acid is an acid that does not completely dissociate into its ions in water. This means only a small fraction of the acid molecules will split into hydrogen ions ( H^+ ) and their corresponding negatively charged ions. The most critical property of a weak acid is its equilibrium state in solution, which allows for partial dissociation.

Weak acids play a significant role in forming buffer solutions. These solutions resist changes in pH when small amounts of acids or bases are added. In the context of a buffer solution, a weak acid provides the crucial component. It ensures that upon slight addition of an acid or base, the pH of the solution remains relatively constant.

For example, hydrofluoric acid ( HF ) used in the exercise above is a weak acid. In a buffer, it ensures stable pH levels because it doesn’t fully dissociate in water. This partial dissociation is precisely what provides buffers their capability to protect against pH changes.
Conjugate Base
The conjugate base of an acid is what remains after the acid has donated a hydrogen ion ( H^+ ). When a weak acid, like HF, loses an H^+ , it becomes its conjugate base, F^- .

Conjugate bases are crucial in creating buffer solutions. This is because they can accept hydrogen ions, helping to balance any changes in hydrogen ion concentration that occur due to the addition of acids or bases. Thus, they maintain the pH balance of the solution.

In buffer solutions, typically, you have a weak acid and its conjugate base. This pair works together to absorb any hydrogen or hydroxide ions introduced, thereby preventing drastic shifts in pH. For example, in the problem, NaF provides the F^- , the conjugate base of HF , enabling the buffer action.
Chemical Equilibrium
Chemical equilibrium refers to the state where the rates of the forward and reverse reactions are equal. In other words, the concentration of reactants and products remains constant over time.

In the context of buffers and weak acids, chemical equilibrium is vital. It ensures that there is a constant exchange between the acid and its conjugate base. When a weak acid is in equilibrium, it partially dissociates, with some molecules remaining intact while others produce H^+ and the conjugate base.

This balance is what allows buffer solutions to effectively neutralize acids and bases. When an acid is added to a buffer, the equilibrium shifts slightly to offset the added ions, maintaining the pH. This balancing act is crucial in numerous biochemical and industrial processes where stable pH environments are needed.
Acid-Base Reactions
Acid-base reactions involve the transfer of H^+ ions from an acid to a base. These reactions are fundamental in chemistry, driving processes like neutralization, where an acid and base react to form water and a salt.

In the creation of buffer solutions, understanding acid-base reactions is essential. When a strong base is added to a weak acid, some of the acid molecules will donate H^+ ions to neutralize the base, forming water and leaving the conjugate base. This particular reaction is vital for forming buffer solutions as demonstrated in the exercise.

For instance, in option (c), HF partially reacts with NaOH , producing F^- and some remaining HF , establishing a buffer system. The reaction doesn’t go to completion, allowing for the coexistence of both the weak acid and the conjugate base, which keeps the solution's pH relatively steady even when additional acids or bases are introduced.

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Most popular questions from this chapter

Some progressive hair coloring products marketed to men, such as Grecian Formula 16, contain lead acetate, \(\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2} .\) As the coloring solution is rubbed on the hair, the \(\mathrm{Pb}^{2+}\) ions react with the sulfur atoms in hair proteins to give lead(II) sulfide (PbS), which is black. A typical coloring solution contains \(0.3\) mass \(\% \mathrm{~Pb}\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2}\), and about \(2 \mathrm{~mL}\) of the solution is used per application. (a) Assuming that \(30 \%\) of the \(\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2}\) is converted to \(\mathrm{PbS}\), how many milligrams of \(\mathrm{PbS}\) are formed per application of the coloring solution? (b) Suppose the hair is washed with shampoo and water that has \(\mathrm{pH}=5.50 .\) How many washings would be required to remove \(50 \%\) of the black color? Assume that 3 gal of water is used per washing and that the water becomes saturated with \(\mathrm{PbS}\). (c) Does the calculated number of washings look reasonable, given that frequent application of the coloring solution is recommended? What process(es) in addition to dissolution might contribute to the loss of color?

Does the pH increase, decrease, or remain the same on the addition of each of the following? (a) \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) to an \(\mathrm{NH}_{3}\) solution (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to an \(\mathrm{NaHCO}_{3}\) solution (c) \(\mathrm{NaClO}_{4}\) to an \(\mathrm{NaOH}\) solution

Calculate the molar solubility of \(\mathrm{CaCO}_{3}\) in pure water. \(\left(K_{\mathrm{sp}}\right.\) for \(\left.\mathrm{CaCO}_{3}=5.0 \times 10^{-9}\right)\).

Which of the following mixtures has the higher \(\mathrm{pH}\) ? (a) Equal volumes of \(0.10 \mathrm{M} \mathrm{HCN}\) and \(0.10 \mathrm{M} \mathrm{NaOH}\) (b) Equal volumes of \(0.10 \mathrm{M} \mathrm{HClO}_{4}\) and \(0.10 \mathrm{M} \mathrm{NaOH}\)

A \(1.000 \mathrm{~L}\) sample of \(\mathrm{HCl}\) gas at \(25^{\circ} \mathrm{C}\) and \(732.0 \mathrm{~mm} \mathrm{Hg}\) was absorbed completely in an aqueous solution that contained \(6.954 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(250.0 \mathrm{~g}\) of water. (a) What is the \(\mathrm{pH}\) of the solution? (b) What is the freezing point of the solution? (c) What is the vapor pressure of the solution? (The vapor pressure of pure water at \(25^{\circ} \mathrm{C}\) is \(23.76 \mathrm{~mm} \mathrm{Hg}\).)

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