Question

For a reaction \(\mathrm{A} \rightarrow \mathrm{B}, \Delta \mathrm{C}_{\mathrm{B}}\) is \(0.01\) moles \(/ \mathrm{l}\) in \(20 \mathrm{~s}\), what is the average rate of reaction?

Short answer

Answer: The average rate of the reaction is 0.0005 moles/l·s.

Step-by-step solution

Identify the given values

In this problem, we are given: - \(\Delta C_B = 0.01\) moles/l - \(\Delta t = 20\) seconds

Apply the formula for average rate of reaction

To find the average rate of the reaction, we will use the formula: Average rate of reaction = \(\frac{\Delta C_{B}}{\Delta t}\) Plug the given values into the formula: Average rate of reaction = \(\frac{0.01 \text{ moles/l}}{20 \text{ s}}\)

Calculate the average rate of reaction

Divide the change in concentration by the change in time: Average rate of reaction = \(\frac{0.01 \text{ moles/l}}{20 \text{ s}} = 0.0005 \text{ moles/l·s}\) The average rate of reaction for this given process is \(0.0005 \text{ moles/l·s}\).