Question

Calculate the volume occupied by \(0.01\) moles of helium gas at STP.

Short answer

Answer: The volume occupied by 0.01 moles of helium gas at STP is approximately 0.224 liters.

Step-by-step solution

Identify the given information

We have the following information given: - \(\displaystyle n=0.01\) moles - Pressure is at STP, \(\displaystyle P=1\) atm - Temperature is at STP, \(\displaystyle T=273.15\) K - Gas constant \(\displaystyle R=0.0821\ \dfrac{L\cdot atm}{mol\cdot K}\)

Use the ideal gas law formula

We have the ideal gas law formula: \(\displaystyle PV=nRT\). Our task is to find the volume \(\displaystyle V\). We can rearrange the formula to solve for volume: \(\displaystyle V=\dfrac{nRT}{P}\)

Enter the given values

Enter the known values into the equation: \(\displaystyle V=\dfrac{(0.01\ mol)(0.0821\ \dfrac{L\cdot atm}{mol\cdot K})(273.15\ K)}{1\ atm}\)

Calculate the volume

Perform the calculation: \(\displaystyle V=\dfrac{(0.01)(0.0821)(273.15)}{1}\ L \approx 0.224\ L\) The volume occupied by \(\displaystyle 0.01\) moles of helium gas at STP is approximately \(\displaystyle 0.224\) liters.