Chapter 9: Problem 77
Draw Lewis structures and give the other information requested for the following molecules: (a) \(\mathrm{BF}_{3}\). Shape: planar or nonplanar? (b) \(\mathrm{ClO}_{3}^{-}\). Shape: planar or nonplanar? (c) HCN. Polar or nonpolar? (d) \(\mathrm{OF}_{2}\). Polar or nonpolar? (e) \(\mathrm{NO}_{2}\). Estimate the ONO bond angle.
Short Answer
Step by step solution
Draw Lewis Structure for \( \mathrm{BF}_3 \)
Determine Shape of \( \mathrm{BF}_3 \)
Draw Lewis Structure for \( \mathrm{ClO}_3^- \)
Determine Shape of \( \mathrm{ClO}_3^- \)
Draw Lewis Structure for \( \mathrm{HCN} \)
Determine Polarity of \( \mathrm{HCN} \)
Draw Lewis Structure for \( \mathrm{OF}_2 \)
Determine Polarity of \( \mathrm{OF}_2 \)
Draw Lewis Structure for \( \mathrm{NO}_2 \)
Estimate \( \mathrm{ONO} \) Bond Angle in \( \mathrm{NO}_2 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Shape
- For example, in the molecule of \( \mathrm{BF}_3 \), the boron atom forms three single bonds with fluorine atoms and has no lone pairs. This results in a trigonal planar shape, which is flat and planar.
- In contrast, \( \mathrm{ClO}_3^- \) has chlorine as the central atom with lone pairs, creating a trigonal pyramidal shape, which is non-planar.
Polarity
- HCN is a polar molecule because it has a linear shape and a significant electronegativity difference between hydrogen and the more electronegative nitrogen, causing a dipole moment.
- Similarly, \( \mathrm{OF}_2 \) is polar due to its bent shape and the high electronegativity of fluorine compared to oxygen, resulting in a net dipole moment.
Bond Angles
- For instance, in \( \mathrm{BF}_3 \), the bond angles are 120°, typical for a trigonal planar shape.
- In \( \mathrm{NO}_2 \), although it has a form that could ordinarily have a bond angle near 120°, the presence of a lone electron (forming a free radical) reduces the bond angle to around 115°.
Electron Configuration
- For instance, boron in \( \mathrm{BF}_3 \) has three valence electrons, which bond with the fluorine atoms, filling its electron shell to satisfy the octet rule.
- For \( \mathrm{ClO}_3^- \), the presence of lone pairs on the central chlorine atom affects its electron configuration, contributing to its shape and reactivity.