Chapter 9: Problem 71
Predict the geometry of sulfur dichloride \(\left(\mathrm{SCl}_{2}\right)\) and the hybridization of the sulfur atom.
Short Answer
Expert verified
SCl2 has a bent geometry and sulfur is sp3 hybridized.
Step by step solution
01
Determine the Valence Electrons
Sulfur ( \(\mathrm{S}\) ) has 6 valence electrons, and each chlorine ( \(\mathrm{Cl}\) ) atom has 7 valence electrons. Since there are two chlorine atoms, the total number of valence electrons is: \(6 + 2 \times 7 = 20\) electrons.
02
Draw the Lewis Structure
With 20 valence electrons, draw the Lewis structure for \(\mathrm{SCl}_{2}\) . Place sulfur in the center, bind two chlorine atoms to it, and complete octets for each atom. There will be 2 lone pairs remaining on sulfur after these bonds and the chlorines satisfy their octets.
03
Determine the Geometry Using VSEPR Theory
According to VSEPR theory, the geometry depends on the number of bonded atoms and lone pairs around the central atom (sulfur). With 2 bonds and 2 lone pairs, use the VSEPR type AX2E2, which corresponds to a bent or angular shape.
04
Identify the Hybridization of Sulfur
Based on the VSEPR model, sulfur uses hybrid orbitals. With 4 regions of electron density (2 single bonds and 2 lone pairs), sulfur is \(\mathrm{sp}^{3}\) hybridized, as it needs four equivalent orbitals to accommodate these areas.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
VSEPR theory
The VSEPR theory, or Valence Shell Electron Pair Repulsion theory, is a model used to predict the geometry of molecules. The main idea is that electron pairs around a central atom will repel each other.
- Because of this repulsion, the molecule will arrange itself in a way that minimizes these repulsions, optimizing the space between the electron pairs.
- This theory helps us determine the shape of a molecule based on the number of bonded atoms and lone pairs around the central atom.
Lewis structure
The Lewis structure is a visual representation to show how valence electrons are arranged in a molecule. For sulfur dichloride (\(\mathrm{SCl}_{2}\)), it helps us understand how the atoms are bonded and where the lone pairs reside.
- First, count the total number of valence electrons involved in the molecule. Sulfur has 6, and each chlorine has 7, resulting in a total of 20 valence electrons.
- Next, arrange the atoms with sulfur in the center and connect each chlorine atom with a single bond. This uses up 4 valence electrons, leaving us with 16 for lone pairs and bonding.
- Assign remaining electrons to satisfy the Octet Rule, prioritizing outer atoms first - here, the chlorine atoms.
- The leftover electrons form lone pairs around the central sulfur atom.
hybridization
Hybridization is a concept that explains how atomic orbitals mix to form new hybrid orbitals, which are used in bonding with other atoms. For sulfur dichloride (\(\mathrm{SCl}_{2}\)), sulfur undergoes \(\mathrm{sp}^{3}\) hybridization.
- This hybridization occurs because sulfur needs to make two sigma bonds (with the chlorine atoms) and also accommodate two lone pairs of electrons.
- In \(\mathrm{sp}^{3}\) hybridization, one s orbital and three p orbitals combine to form four equivalent \(\mathrm{sp}^{3}\) hybrid orbitals.
valence electrons
Valence electrons are the electrons present in the outermost shell of an atom. They are crucial for understanding how atoms bond in molecules. For sulfur dichloride (\(\mathrm{SCl}_{2}\)), counting valence electrons is the first step in predicting its structure.
- Sulfur, as a Group 16 element, has 6 valence electrons.
- Chlorine, a Group 17 element, has 7 valence electrons.
- With two chlorine atoms, the total count becomes 20 valence electrons as shown by the equation: \(6 + 2 \times 7 = 20\).