Chapter 9: Problem 50
Draw a molecular orbital energy level diagram for each of the following species: \(\mathrm{He}_{2}, \mathrm{HHe}, \mathrm{He}_{2}^{+}\). Compare their relative stabilities in terms of bond orders. (Treat HHe as a diatomic molecule with three electrons.)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bond Order
\[\text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2}.\]Key insights about bond order include:
- A higher bond order usually correlates with a stronger, more stable bond.
- A bond order of zero indicates that no stable bond exists between the atoms.
- In molecules with unpaired electrons in the antibonding orbital, a fractional bond order can occur, reflecting partial bonding.
Molecular Stability
Here’s how bond order influences molecular stability:
- Molecules with a bond order greater than zero are more stable, indicating a bonding interaction between atoms.
- Higher bond orders suggest that a molecule will require more energy to break its bonds, and hence, is more stable.
- Bond order of zero, as seen in He₂, means that the molecule lacks stability and would not typically exist under normal conditions.
Diatomic Molecules
Here's what to know about diatomic molecules:
- Diatomic molecules composed of similar atoms, like O₂ or N₂, are often used as simple models to describe molecular bonding.
- Heteronuclear diatomic molecules, such as HCl, involve atoms of different elements, providing more complex bonding scenarios.
- For a diatomic molecule, the number of electron pairs shared between the two atoms can be analyzed using their bond order, helping to predict their chemical behavior and reactivity.