Chapter 8: Problem 96
Draw four reasonable resonance structures for the \(\mathrm{PO}_{3} \mathrm{~F}^{2-}\) ion. The central \(\mathrm{P}\) atom is bonded to the three \(\mathrm{O}\) atoms and to the \(\mathrm{F}\) atom. Show formal charges.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Valence Electrons
For example, phosphorus (P) contributes 5 electrons, each oxygen (O) contributes 6, and fluorine (F) contributes 7. Since \( \mathrm{PO}_3\mathrm{~F}^{2-} \) carries a \( 2- \) charge, you add 2 additional electrons to your total. This gives us \( 32 \) valence electrons to work with.
Recognizing valence electrons informs how atoms will connect and what types of bonds, like single or double, might form in different structures.
Formal Charges
The formula to calculate formal charge is:
- \( \text{Formal charge} = \text{Valence electrons} - \text{Non-bonding electrons} - \frac{1}{2}\text{Bonding electrons} \)
Octet Rule
For the \( \mathrm{PO}_3\mathrm{~F}^{2-} \) ion, each oxygen and the fluorine will aim to have an octet. Phosphorus, although typically surrounded by more due to its ability to expand its octet, generally will follow this rule as well.
When drawing the resonance structures, the redistribution of electrons must consider fulfilling the octet requirement. Generally, moving pairs of electrons to form double bonds between phosphorus and oxygen atoms can help maintain the octet across different resonance forms.
Lewis Structures
For \( \mathrm{PO}_3\mathrm{~F}^{2-} \), you start by placing phosphorus in the center, given its lower electronegativity, and link it with oxygen and fluorine using initial single bonds. The total count of electrons used should sum to \( 32 \), as calculated from the valence electrons.
Resonance structures are variants of Lewis structures which showcase possibilities of electron placement. They provide a more comprehensive understanding of electron distribution, which cannot always be captured by a single static diagram. Through resonance and Lewis structures, we can appreciate both the molecule's stable state and the dynamic nature of electron positions.