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What is bond enthalpy? Bond enthalpies of polyatomic molecules are average values, whereas those of diatomic molecules can be accurately determined. Why?

Short Answer

Expert verified
Bond enthalpy is the energy needed to break a bond. Average for polyatomic due to interactions; precise for diatomic due to lack thereof.

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01

Understanding Bond Enthalpy

Bond enthalpy, also known as bond-dissociation energy, is the energy required to break one mole of a specific type of bond in gaseous molecules. It is usually expressed in kilojoules per mole (kJ/mol). This concept helps us understand the strength of a bond: higher bond enthalpies mean stronger bonds.
02

Bond Enthalpies in Polyatomic Molecules

For polyatomic molecules, bond enthalpies are average values. This is because a particular type of bond can be influenced by the presence of other bonds in the molecule, as well as the molecule's geometry. Therefore, breaking a bond within a polyatomic molecule may require slightly more or less energy depending on the molecule's specific structure.
03

Accurate Bond Enthalpies in Diatomic Molecules

In diatomic molecules, which consist of only two atoms, bond enthalpies can be determined accurately. Since there are no other bonds present to affect the bond in question, the energy needed to break the bond is specific and can be precisely measured for each pair of atoms.
04

Conclusion on the Nature of Bond Enthalpies

The difference in how bond enthalpies are determined between diatomic and polyatomic molecules arises due to the complexity and interactions within the molecule. Polyatomic molecules have multiple interactions affecting each bond, leading to the use of average values, while diatomic molecules have a singular and distinct interaction, allowing for precise measurement.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polyatomic Molecules
Polyatomic molecules are composed of more than two atoms, and the molecule's structure can significantly influence the bond enthalpies within it. Each bond within a polyatomic molecule might interact with other nearby bonds. This interaction can alter the energy required to break any single bond. Think of it like a dance where each partner affects the movement of the others. Hence, the bond energies are often reported as average values for a bond type. This averaging helps to manage the complexity that arises from various interactions and molecular structure variations within such molecules.
Diatomic Molecules
Diatomic molecules consist of exactly two atoms. In these simple molecules, the bond enthalpy can be determined with great accuracy. With only one bond to consider, the measurement is straightforward and precise. There's no neighboring bond or complex interaction to skew the energy measurement required to break the bond. Examples of diatomic molecules include oxygen (\(O_2\)), nitrogen (\(N_2\)), and hydrogen (\(H_2\)). The simplicity of their structure allows scientists to measure and report exact bond enthalpy values for these molecules.
Molecular Structure
The molecular structure of a compound greatly influences its physical and chemical properties, including bond-dissociation energies. In complex molecules, bond angles, bond lengths, and spatial arrangements can affect the energy a bond requires to break. Different molecular structures, even with the same types of atoms and bonds, can lead to significant variations in bond enthalpies. This is why chemists consider molecular geometry and the orientation of bonds while calculating the energy requirements for breaking bonds within polyatomic molecules.
Bond-Dissociation Energy
Bond-dissociation energy, often used interchangeably with bond enthalpy, is a key concept in understanding molecular stability. It represents the energy needed to dissociate one mole of a specific bond type into separate atoms in the gas phase. A higher bond-dissociation energy indicates a stronger bond. Stronger bonds are typically more stable and require more energy to break.
  • Reflected in reaction kinetics, stronger bonds usually result in slower reactions.
  • Bond-dissociation energies help predict reaction pathways and stability of products.
  • Essential in fields like thermochemistry and molecular physics for interpreting experimental data.
Understanding bond-dissociation energy provides valuable insights into how molecules interact and react.

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Most popular questions from this chapter

(a) From the following data calculate the bond enthalpy of the \(\mathrm{F}_{2}^{-}\) ion. $$ \begin{array}{ll} \mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{~F}(g) & \Delta H_{\mathrm{rxn}}^{\circ}=156.9 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{F}^{-}(g) \longrightarrow \mathrm{F}(g)+e^{-} & \Delta H_{\mathrm{rxn}}^{\circ}=333 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{F}_{2}^{-}(g) \longrightarrow \mathrm{F}_{2}(g)+e^{-} & \Delta H_{\mathrm{rxn}}^{\circ}=290 \mathrm{~kJ} / \mathrm{mol} \end{array} $$ (b) Explain the difference between the bond enthalpies of \(\mathrm{F}_{2}\) and \(\mathrm{F}_{2}^{-}\).

An ionic bond is formed between a cation \(\mathrm{A}^{+}\) and an anion \(\mathrm{B}^{-}\). Based on Coulomb's law $$ E \propto \frac{Q_{1} \times Q_{2}}{d} $$ how would the energy of the ionic bond be affected by the following changes: (a) doubling the radius of \(\mathrm{A}^{+}\) (b) tripling the charge on \(\mathrm{A}^{+},(\mathrm{c})\) doubling the charges on \(\mathrm{A}^{+}\) and \(\mathrm{B}^{-},(\mathrm{d})\) decreasing the radii of \(\mathrm{A}^{+}\) and \(\mathrm{B}^{-}\) to half their original values?

In 1998 , scientists using a special type of electron microscope were able to measure the force needed to break a single chemical bond. If \(2.0 \times 10^{-9} \mathrm{~N}\) was needed to break a \(\mathrm{C}-\mathrm{Si}\) bond, estimate the bond enthalpy in \(\mathrm{kJ} / \mathrm{mol}\). Assume that the bond has to be stretched by a distance of \(2 \AA\) ( \(2 \times 10^{-10} \mathrm{~m}\) ) before it is broken.

List the following bonds in order of increasing ionic character: the lithium- to-fluorine bond in LiF, the potassium-to-oxygen bond in \(\mathrm{K}_{2} \mathrm{O},\) the nitrogen-tonitrogen bond in \(\mathrm{N}_{2}\), the sulfur-to- oxygen bond in \(\mathrm{SO}_{2}\), the chlorine-to-fluorine bond in \(\mathrm{ClF}_{3}\).

Which of the following molecules has the shortest nitrogen-to-nitrogen bond: \(\mathrm{N}_{2} \mathrm{H}_{4}, \mathrm{~N}_{2} \mathrm{O}, \mathrm{N}_{2}, \mathrm{~N}_{2} \mathrm{O}_{4} ?\) Explain.

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