Chapter 8: Problem 74
Write Lewis structures for \(\mathrm{SeF}_{4}\) and \(\mathrm{SeF}_{6}\). Is the octet rule satisfied for Se?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Octet Rule
- Atoms form bonds to achieve a stable electron configuration.
- The octet rule describes this tendency for having eight valence electrons.
- Exceptions to the octet rule can be seen in compounds with elements like sulfur and phosphorus.
Valence Electrons
Each element's valence electrons can be determined by looking at its group number in the periodic table. For instance:
- Selenium (Se) is in group 16, so it has 6 valence electrons.
- Fluorine (F) is in group 17, with 7 valence electrons.
Expanded Octet
In SeF_4 and SeF_6, selenium uses an expanded octet to achieve stability. This means selenium can accommodate more than the usual eight electrons:
- In SeF_4, selenium has 10 electrons around it.
- In SeF_6, selenium accommodates 12 electrons.
Selenium
Selenium's ability to exceed the octet rule stems from its electronic structure:
- It has 6 valence electrons, allowing it some flexibility in bonding.
- Its position in period 4 grants it access to d-orbitals, crucial for accommodating extra electrons.
Fluorine
In compounds, fluorine consistently seeks to achieve a stable octet by gaining one additional electron:
- This need makes fluorine a consistent bonding partner in many compounds, always forming a single bond.
- In SeF_4 and SeF_6, fluorine always completes its octet, ensuring stability for the compound.