Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Define ionization energy. Explain why ionization energy measurements are usually made when atoms are in the gaseous state. Why is the second ionization energy always greater than the first ionization energy for any element?

Short Answer

Expert verified
Ionization energy refers to the energy needed to remove an electron from an atom. It is measured in the gaseous state for accuracy, and the second ionization energy is higher due to increased nuclear attraction after the first electron is removed.

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Defining Ionization Energy

Ionization energy is the amount of energy required to remove an electron from an isolated atom or ion in its gaseous state. This energy is needed to overcome the attractive forces between the electron and the nucleus.
02

Gaseous State for Ionization Energy Measurements

Ionization energy is typically measured in the gaseous state to ensure that atoms are isolated. In a gaseous state, atoms have minimal interactions with each other, providing a clearer and more accurate measurement of the energy required to remove an electron.
03

Understanding the Second Ionization Energy

The second ionization energy is always greater than the first because after the first electron is removed, there is less electron-electron repulsion and the remaining electrons are drawn closer to the nucleus. This increased attraction means more energy is required to remove the next electron.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Gaseous State
When we measure ionization energy, it is crucial to work with atoms in their gaseous state. In this form, atoms exist as individual and isolated entities. There is minimal interaction with other particles. This is important because any interactions could influence the energy measurements, leading to inaccurate results.
  • In the gaseous state, atoms are free from external forces like van der Waals forces that may be present in solid or liquid states.
  • This makes isolating an atom easier, providing a pure measurement of the energy needed to detach an electron.
  • It ensures the results are solely due to the intrinsic properties of the atom being studied.
So, by using the gaseous state, scientists can measure ionization energy with high precision.
The Process of Electron Removal
Ionization energy is fundamentally about removing electrons from an atom. This process involves overcoming the attractive force that the positively-charged nucleus exerts on the negatively-charged electrons. Removing an electron requires a specific amount of energy because you're essentially breaking this attraction.
  • Each electron experiences a pull toward the nucleus due to opposite electrical charges.
  • For the first ionization energy, the outermost electron is removed, which is often the easiest due to its distance from the nucleus.
  • This represents the minimum energy needed to turn an atom into a positively charged ion.
It's important to note that once an electron is removed, the atom undergoes changes that affect further electron removal, impacting the energy required for subsequent electrons.
Why Second Ionization Energy is Higher
Once the first electron is removed, a few things change within the atom. Primarily, with one fewer negatively charged electron to balance the positively charged nucleus, the remaining electrons are held more tightly.
  • The electron cloud is now smaller, increasing the effective nuclear charge felt by the remaining electrons.
  • This leads to stronger attraction between the nucleus and the remaining electrons, making it harder to remove another electron.
  • Consequently, the second ionization energy is the energy needed to remove a second electron from an already positively charged ion, which is always higher than the first ionization energy.
Thus, the second ionization energy is greater because it requires additional energy to overcome the increased attraction and remove another electron.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the ground-state electron configurations of the following ions, which play important roles in biochemical processes in our bodies: (a) \(\mathrm{Na}^{+},\) (b) \(\mathrm{Mg}^{2+}\), (c) \(\mathrm{Cl}^{-}\) (d) \(\mathrm{K}^{+}\) (e) \(\mathrm{Ca}^{2+}\) (f) \(\mathrm{Fe}^{2+},(\mathrm{g}) \mathrm{Cu}^{2+}\) (h) \(\mathrm{Zn}^{2+}\)

In the periodic table, the element hydrogen is sometimes grouped with the alkali metals and sometimes with the halogens. Explain why hydrogen can resemble the Group \(1 \mathrm{~A}\) and the Group \(7 \mathrm{~A}\) elements.

Write balanced equations for the reactions between each of the following oxides and water: (a) \(\mathrm{Li}_{2} \mathrm{O}\) (b) \(\mathrm{CaO}\) (c) \(\mathrm{SO}_{3}\)

Why do elements that have high ionization energies also have more positive electron affinities? Which group of elements would be an exception to this generalization?

In halogen displacement reactions a halogen element can be generated by oxidizing its anions with a halogen element that lies above it in the periodic table. This means that there is no way to prepare elemental fluorine, because it is the first member of Group \(7 \mathrm{~A} .\) Indeed, for years the only way to prepare elemental fluorine was to oxidize \(\mathrm{F}^{-}\) ions by electrolytic means. Then, in 1986 , a chemist reported that by combining potassium hexafluoromanganate(IV) \(\left(\mathrm{K}_{2} \mathrm{MnF}_{6}\right)\) with antimony pentafluoride \(\left(\mathrm{SbF}_{5}\right)\) at \(150^{\circ} \mathrm{C}\), he had generated elemental fluorine. Balance the following equation representing the reaction: $$ \mathrm{K}_{2} \mathrm{MnF}_{6}+\mathrm{SbF}_{5} \longrightarrow \mathrm{KSbF}_{6}+\mathrm{MnF}_{3}+\mathrm{F}_{2} $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free