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Discuss the similarities and differences between a \(1 s\) and a \(2 s\) orbital.

Short Answer

Expert verified
Both \(1s\) and \(2s\) orbitals are spherical, but \(2s\) has a radial node and is at a higher energy level.

Step by step solution

01

Introduction to Orbitals

Orbitals are regions around the nucleus of an atom where electrons are likely to be found. The designation and understanding of these orbitals are crucial, especially in quantum chemistry and atomic models.
02

Understanding the s Orbital Shape

Both the \(1s\) and \(2s\) orbitals are spherical in shape. Unlike other types of orbitals (like \(p\), \(d\), or \(f\)), s orbitals do not have directional properties due to their spherical nature.
03

Energy Levels: Principal Quantum Number

The \(1s\) and \(2s\) orbitals belong to different energy levels indicated by their principal quantum numbers (n). The \(1s\) orbital is at the first energy level (n=1), whereas the \(2s\) orbital is at the second energy level (n=2). This difference in energy levels affects the internuclear distance of electrons in these orbitals.
04

Node Count and Radial Distribution

A significant difference between the \(1s\) and \(2s\) orbitals is the presence of nodes. The \(1s\) orbital does not possess any nodes, while the \(2s\) orbital has one radial node. Nodes are points where there is zero probability of finding an electron. This affects the radial distribution of electrons for these orbitals.
05

Electrons in Both Orbitals

Both the \(1s\) and \(2s\) orbitals can hold a maximum of two electrons, obeying the Pauli Exclusion Principle. Despite belonging to different energy levels, they share this capacity across orbitals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

s orbital
The "s" orbitals are the simplest type of atomic orbitals and are fascinating because of their symmetry. An "s" orbital is spherical, meaning it is shaped like a perfect sphere. This spherical shape makes the "s" orbital unique compared to others, such as "p", "d", or "f" orbitals, which have more complex shapes.
  • "s" orbitals do not have a preferred direction in space.
  • They are the first to fill in an atom’s electron configuration, starting with the 1s orbital.
Their symmetrical shape helps to evenly distribute electrons around the nucleus, ensuring equal probability in finding an electron in any direction from the center. This property is significant because it influences how electrons interact within chemicals, impacting molecular shapes and reactions.
quantum numbers
Quantum numbers are a set of four values that provide crucial information about the position and energy of an electron in an atom. They work like an address system, helping define where an electron resides around the nucleus. The quantum numbers include:
  • Principal Quantum Number (\(n\)): Indicates the energy level or shell.
  • Angular Momentum Quantum Number (\(l\)): Refers to the shape of the orbital.
  • Magnetic Quantum Number (\(m_l\)): Shows the orientation of the orbital in space.
  • Spin Quantum Number (\(m_s\)): Describes the electron’s spin direction.
For example, the main difference between a 1s and a 2s orbital is visible in the principal quantum number (\(n\)). A 1s orbital has \(n = 1\), while a 2s orbital has \(n = 2\). This majorly impacts the energy and size of the orbital, with higher values of \(n\) resulting in larger and higher-energy orbitals.
radial nodes
When discussing orbitals, the concept of radial nodes becomes very important. Nodes are regions in an orbital where the probability of finding an electron is zero. Radial nodes specifically refer to nodes that occur at certain distances from the nucleus.
  • A 1s orbital has no radial nodes.
  • A 2s orbital has one radial node.
These radial nodes separate the orbital into regions with different probabilities of finding electrons. The presence of nodes impacts the electron distribution, affecting the energy and radial distribution of the electrons, which is the reason the 2s is more spread out and at a higher energy level than the 1s orbital. Understanding radial nodes helps explain why electrons "prefer" certain regions over others in an atomic structure.
electron configuration
Electron configuration is a systematic way of describing the arrangement of electrons in an atom using principles from quantum mechanics. As electrons fill orbitals around a nucleus, they follow a specific order dictated by principles like the Aufbau principle and Hund’s rule. This order shows how electrons are distributed across different shells and subshells.
  • The configuration starts with the lowest available energy level.
  • For example, an atom begins filling into 1s, then moves to 2s, and successively higher shells and orbitals, as in 1s² 2s² 2p⁶, etc.
  • This determines the chemical properties of elements.
The electron configuration reveals the filled state of each energy level, including how 1s and 2s orbitals accept electrons. These configurations help define the atom's reactivity and bonding behavior, making them vital for understanding chemical reactions.

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Most popular questions from this chapter

What is the maximum number of electrons in an atom that can have the following quantum numbers? Specify the orbitals in which the electrons would be found. (a) \(n=2, m_{s}=+\frac{1}{2} ;\) (b) \(n=4, m_{\ell}=+1 ;\) (c) \(n=3\), \(\ell=2 ;(\mathrm{d}) n=2, \ell=0, m_{s}=-\frac{1}{2} ;(\mathrm{e}) n=4, \ell=3\) \(m_{\ell}=-2\)

Why do the \(3 s, 3 p\), and \(3 d\) orbitals have the same energy in a hydrogen atom but different energies in a manyelectron atom?

Careful spectral analysis shows that the familiar yellow light of sodium lamps (such as street lamps) is made up of photons of two wavelengths, \(589.0 \mathrm{nm}\) and \(589.6 \mathrm{nm}\). What is the difference in energy (in joules) between photons with these wavelengths?

The first line of the Balmer series occurs at a wavelength of \(656.3 \mathrm{nm}\). What is the energy difference between the two energy levels involved in the emission that results in this spectral line?

An electron in a hydrogen atom is excited from the ground state to the \(n=4\) state. Comment on the correctness of the following statements (true or false). (a) \(n=4\) is the first excited state. (b) It takes more energy to ionize (remove) the electron from \(n=4\) than from the ground state. (c) The electron is farther from the nucleus (on average) in \(n=4\) than in the ground state. (d) The wavelength of light emitted when the electron drops from \(n=4\) to \(n=1\) is longer than that from \(n=4\) to \(n=2\) (e) The wavelength the atom absorbs in going from \(n=1\) to \(n=4\) is the same as that emitted as it goes from \(n=4\) to \(n=1\)

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