Chapter 6: Problem 117
The wave function for the \(2 s\) orbital in the hydrogen atom is $$ \psi_{2 s}=\frac{1}{\sqrt{2 a_{0}^{3}}}\left(1-\frac{\rho}{2}\right) e^{-\rho / 2} $$ where \(a_{0}\) is the value of the radius of the first Bohr orbit, equal to \(0.529 \mathrm{nm} ; \rho\) is \(Z\left(r / a_{0}\right) ;\) and \(r\) is the distance from the nucleus in meters. Calculate the distance from the nucleus (in \(\mathrm{nm}\) ) of the node of the \(2 s\) wave function.
Short Answer
Step by step solution
Key Concepts
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