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Decomposition reactions are usually endothermic, whereas combination reactions are usually exothermic. Give a qualitative explanation for these trends.

Short Answer

Expert verified
Decomposition reactions absorb energy (endothermic), while combination reactions release energy (exothermic), due to bond energy differences.

Step by step solution

01

Define Decomposition Reactions

Decomposition reactions involve the breaking down of a compound into simpler substances. This process generally requires energy because chemical bonds in the compound must be broken, leading to an absorption of heat, making these reactions endothermic.
02

Define Combination Reactions

Combination reactions involve the formation of a compound from simpler substances. In these reactions, new chemical bonds are formed, which often release energy in the form of heat, thereby making these reactions exothermic.
03

Explain Energy Changes in Decomposition

For decomposition reactions, the energy needed to break the bonds is greater than the energy released from the formation of any new bonds. This difference results in an overall absorption of energy, which is why these reactions are typically endothermic.
04

Explain Energy Changes in Combination

In combination reactions, the energy released from forming new bonds is often greater than the energy required to break any initial bonds. This excess release of energy makes the reaction exothermic.
05

Compare and Conclude

Decomposition reactions require an input of energy to break bonds, making them endothermic, while combination reactions release energy through bond formation, making them exothermic. This reflects the general relationship between bond energy considerations and the thermal nature of these chemical reactions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decomposition Reactions
In the world of chemistry, decomposition reactions are an intriguing type of chemical reaction. Imagine them as taking apart a Lego model to reuse the bricks. This involves breaking down a complex compound into simpler substances. To achieve this, energy is necessary to break the chemical bonds holding the compound together.

Because energy is required, these reactions absorb heat from their surroundings. This absorption is what makes decomposition reactions endothermic. When you think about it, breaking things down often needs effort, just like splitting a log of wood. By understanding this fundamental concept, you can see why decomposition processes are vital in chemical reactions.
Combination Reactions
Picture a combination reaction as assembling a puzzle. Unlike decomposition reactions, combination reactions involve joining simpler substances to form a more complex compound. During this process, new bonds are created. Creating those new connections releases energy in the form of heat.

This release of energy generally makes combination reactions exothermic. It's like the warmth you feel during a hug, a natural byproduct of coming together. These reactions showcase how energy dynamics are crucial, and that forming bonds typically releases more energy than breaking them. This is why combining elements into compounds often generates heat.
Endothermic Processes
Endothermic processes are fascinating because they are all about energy intake. During these processes, substances absorb heat from their surroundings. This is why they often feel cold to the touch. The need for energy often arises when something complex is being broken down, as in decomposition reactions.

Common endothermic processes include:
  • Melting ice cubes
  • Evaporation of water
  • Photosynthesis in plants
Understanding endothermic processes is key to grasping how energy flows within reactions. By pulling in energy, these processes support changes that otherwise would not occur on their own.
Exothermic Processes
Exothermic processes stand out because they release energy. You can think of them as sharing warmth with the environment. These are processes where, typically, new bonds form in a way that releases excess energy, much like combination reactions.

Here are some everyday examples:
  • Burning wood in a fire
  • Combustion of gasoline in car engines
  • Mixing acids with bases
Exothermic processes demonstrate how energy tends to flow freely from reactions into their environment. They help us understand why certain reactions occur spontaneously with noticeable heat output. This concept is fundamental to energy management and transformation in both natural and engineered processes.

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Most popular questions from this chapter

A gas expands in volume from 26.7 to \(89.3 \mathrm{~mL}\) at constant temperature. Calculate the work done (in joules) if the gas expands (a) against a vacuum, (b) against a constant pressure of \(1.5 \mathrm{~atm},\) and \((\mathrm{c})\) against a constant pressure of \(2.8 \mathrm{~atm} .(1 \mathrm{~L} \cdot \mathrm{atm}=101.3 \mathrm{~J})\).

Consider the following data:$$\begin{array}{lcc}\text { Metal } & \text { Al } & \text { Cu } \\\\\hline \text { Mass }(\mathrm{g}) & 10 & 30 \\\\\text { Specific heat }\left(\mathrm{J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right) & 0.900 & 0.385 \\\\\text { Temnerature }{ }^{\circ}{ }^{\circ} \mathrm{C} \text { ) } & 40 & 60\end{array}$$ When these two metals are placed in contact, which of the following will take place? (a) Heat will flow from \(\mathrm{Al}\) to Cu because \(\mathrm{Al}\) has a larger specific heat. (b) Heat will flow from \(\mathrm{Cu}\) to \(\mathrm{Al}\) because \(\mathrm{Cu}\) has a larger mass. (c) Heat will flow from \(\mathrm{Cu}\) to \(\mathrm{Al}\) because \(\mathrm{Cu}\) has a larger heat capacity (d) Heat will flow from Cu to Al because Cu is at a higher temperature. (e) No heat will flow in either direction.

From the following heats of combustion, \(\begin{aligned} \mathrm{CH}_{3} \mathrm{OH}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) & \Delta H_{\mathrm{rxn}}^{\circ}=-726.4 \mathrm{~kJ} / \mathrm{mol} \\\ \mathrm{C}(\text { graphite })+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) & \\ \Delta H_{\mathrm{rxn}}^{\circ}=-393.5 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l) & \\ \Delta H_{\mathrm{rxn}}^{\circ}=-285.8 \mathrm{~kJ} / \mathrm{mol} \end{aligned}\) calculate the enthalpy of formation of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) from its elements: $$ \mathrm{C}(\text { graphite })+2 \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CH}_{3} \mathrm{OH}(l) $$

A 44.0-g sample of an unknown metal at \(99.0^{\circ} \mathrm{C}\) was placed in a constant-pressure calorimeter containing \(80.0 \mathrm{~g}\) of water at \(24.0^{\circ} \mathrm{C}\). The final temperature of the system was found to be \(28.4^{\circ} \mathrm{C}\). Calculate the specific heat of the metal. (The heat capacity of the calorimeter is \(12.4 \mathrm{~J} /{ }^{\circ} \mathrm{C} .\)

Define these terms: enthalpy and enthalpy of reaction. Under what condition is the heat of a reaction equal to the enthalpy change of the same reaction?

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