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Stoichiometry is based on the law of conservation of mass. On what law is thermochemistry based?

Short Answer

Expert verified
Thermochemistry is based on the First Law of Thermodynamics.

Step by step solution

01

Understand Thermochemistry

Thermochemistry is the study of the exchange of energy, primarily in the form of heat, during chemical reactions. It focuses on how energy is absorbed or released when chemical bonds are formed or broken.
02

Identify the Governing Law

The main law that thermochemistry is based on is the First Law of Thermodynamics. This law is also known as the law of energy conservation, stating that energy cannot be created or destroyed in an isolated system; it can only change forms.
03

Explain the First Law of Thermodynamics

The First Law of Thermodynamics can be expressed mathematically as \( \Delta U = Q - W \), where \( \Delta U \) is the change in internal energy, \( Q \) is the heat added to the system, and \( W \) is the work done by the system. This equation shows that any change in the internal energy of a system is due to the heat exchange and the work performed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Law of Thermodynamics
The First Law of Thermodynamics is the foundation of thermochemistry. It establishes that energy is conserved within an isolated system. This means energy can neither be created nor destroyed, only transformed from one form to another. For example, chemical reactions may convert potential energy in chemical bonds into heat energy. The mathematical expression for this law is given by \[ \Delta U = Q - W \] where:
  • \( \Delta U \) is the change in internal energy of the system,
  • \( Q \) is the heat added to the system, and
  • \( W \) is the work done by the system.
Understanding this law helps us predict how energy will behave during a chemical reaction.
Energy Conservation
Energy conservation is a key principle closely linked to the First Law of Thermodynamics. It denotes that the total energy in an isolated system remains constant, although it might change forms, such as from chemical potential energy to kinetic energy or heat. In the context of thermochemistry, understanding energy conservation allows us to analyze how energy transitions during different processes.

Here are some important points about energy conservation:
  • Every chemical reaction involves the redistribution of energy.
  • No energy is lost, it's only converted into different types.
  • Reactions that release energy in the form of heat are called exothermic, whereas those that absorb heat are endothermic.
Recognizing how these energy transformations take place is essential in predicting and measuring the outcome of chemical processes.
Chemical Reactions
Chemical reactions are the processes where the bonds between atoms are broken and reformed, leading to the transformation of substances. During these processes, energy is either absorbed or released.

The role of energy in chemical reactions involves:
  • Bond breaking requiring energy input, termed endothermic reactions.
  • Bond forming releasing energy, known as exothermic reactions.
Understanding the nature of chemical reactions is crucial because it helps predict whether a reaction will release or require energy, thus allowing us to anticipate the heat exchange involved.
Heat Exchange
Heat exchange refers to the transfer of thermal energy between a system and its surroundings. In thermochemistry, it's crucial to understand how heat is managed during chemical reactions, as it greatly influences reaction pathways and rates.

Key considerations of heat exchange include:
  • Calculating how much heat is absorbed or released during a reaction.
  • Determining if a reaction is exothermic (heat released) or endothermic (heat absorbed).
  • Knowing that in a closed system, heat exchanged will result in a change in internal energy, as denoted by the equation \( \Delta U = Q - W \).
By mastering these concepts, we can better control and manipulate chemical processes in both laboratory and industrial settings.

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Most popular questions from this chapter

Consider the following two reactions: $$ \begin{array}{ll} \mathrm{A} \longrightarrow 2 \mathrm{~B} & \Delta H_{\mathrm{rxn}}^{\circ}=H_{1} \\\ \mathrm{~A} \longrightarrow \mathrm{C} & \Delta H_{\mathrm{rxn}}^{\circ}=H_{2} \end{array} $$ Determine the enthalpy change for the process $$ 2 \mathrm{~B} \longrightarrow \mathrm{C} $$

From these data, $$\begin{array}{l}\mathrm{S} \text { (rhombic) }+\mathrm{O}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g) \\\\\qquad \begin{aligned}\Delta H_{\mathrm{rxn}}^{\circ} &=-296.4 \mathrm{~kJ} / \mathrm{mol}\end{aligned} \\\\\mathrm{S} \text { (monoclinic) }+\mathrm{O}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g) \\\\\Delta H_{\mathrm{rxn}}^{\circ}=-296.7 \mathrm{~kJ} / \mathrm{mol}\end{array}$$ calculate the enthalpy change for the transformation \(\mathrm{S}\) (rhombic) \(\longrightarrow \mathrm{S}\) (monoclinic) (Monoclinic and rhombic are different allotropic forms of elemental sulfur.)

Decomposition reactions are usually endothermic, whereas combination reactions are usually exothermic. Give a qualitative explanation for these trends.

Acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) can be made by combining calcium carbide \(\left(\mathrm{CaC}_{2}\right)\) with water. (a) Write an equation for the reaction. (b) What is the maximum amount of heat (in joules) that can be obtained from the combustion of acetylene, starting with \(74.6 \mathrm{~g}\) of \(\mathrm{CaC}_{2} ?\)

Given the thermochemical data, \(\mathrm{A}+\mathrm{B} \longrightarrow 2 \mathrm{C} \quad \Delta H_{1}=600 \mathrm{~kJ} / \mathrm{mol}\) \(\begin{array}{ll}2 \mathrm{C}+\mathrm{D} \longrightarrow 2 \mathrm{E} & \Delta H_{1}=210 \mathrm{~kJ} / \mathrm{mol}\end{array}\) Determine the enthalpy change for each of the following: a) \(4 \mathrm{E} \longrightarrow 4 \mathrm{C}+2 \mathrm{D}\) d) \(2 C+2 E \longrightarrow 2 A+2 B+D\) b) \(\mathrm{A}+\mathrm{B}+\mathrm{D} \longrightarrow 2 \mathrm{E}\) e) \(\mathrm{E} \longrightarrow \frac{1}{2} \mathrm{~A}+\frac{1}{2} \mathrm{~B}+\frac{1}{2} \mathrm{D}\) c) \(\mathrm{C} \longrightarrow \frac{1}{2} \mathrm{~A}+\frac{1}{2} \mathrm{~B}\)

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