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Which of the following standard enthalpy of formation values is not zero at \(25^{\circ} \mathrm{C}: \mathrm{Na}(\) monoclinic \(), \mathrm{Ne}(g)\) \(\mathrm{CH}_{4}(g), \mathrm{S}_{8}(\) monoclinic \(), \mathrm{Hg}(l), \mathrm{H}(g) ?\)

Short Answer

Expert verified
\( \mathrm{CH}_{4}(g) \) and \( \mathrm{S}_{8} \) monoclinic both have non-zero standard enthalpy of formation.

Step by step solution

01

Understanding Enthalpy of Formation

The standard enthalpy of formation for an element in its most stable form is zero at 25°C and 1 atm pressure. This is a key principle of thermodynamics.
02

Identifying Elements

Determine which substances are elements and which are compounds. In the exercise, \( \mathrm{Na} \), \( \mathrm{Ne} \), \( \mathrm{Hg} \), and \( \mathrm{H} \) are elements, whereas \( \mathrm{CH}_{4} \) is a compound.
03

Comparing Elemental States

For elements, determine if the given state is the most stable at 25°C. \( \mathrm{Na} \) is normally solid, \( \mathrm{Ne} \) is gas, \( \mathrm{Hg} \) is liquid, and \( \mathrm{H} \) exists as \( \mathrm{H}_2 \) gas.
04

Recognizing Compounds

Compounds, like \( \mathrm{CH}_{4} \), do not have a standard enthalpy of formation of zero, as they are not in their elemental form. Each compound’s formation involves creating it from its constituent elements.
05

Identifying Most Common State

Verify the most common and stable form of elements at 25°C. \( \mathrm{S}_{8} \) normally exists as rhombic, not monoclinic. Therefore, \( \mathrm{S}_{8} \) monoclinic has a non-zero standard enthalpy of formation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics
Thermodynamics is a foundational concept in chemistry and physics that helps us understand how energy is transferred and transformed in a system. It deals with concepts such as energy, work, heat, and how they interact in various processes. The standard enthalpy of formation is an important thermodynamic quantity. It is defined as the heat absorbed or released when one mole of a compound is formed from its elements in their most stable forms at a pressure of 1 atm and a temperature of 25°C (standard conditions).

One key aspect of thermodynamics is the conservation of energy principle, which states that energy cannot be created or destroyed but can be transferred from one form to another. This principle is used to calculate enthalpy changes in reactions and understand how systems reach stability.
Identifying the Most Stable Form of Elements
The term 'most stable form' refers to the physical state and molecular configuration of an element that is most energetically favorable under standard conditions (25°C and 1 atm). The standard enthalpy of formation for an element in its most stable form is defined as zero because no energy is required to form the element from itself.

For example:
  • Sodium (\(\mathrm{Na}\)) is most stable as a solid metal.
  • Helium (\(\mathrm{Ne}\)) is most stable in its gaseous form.
  • Mercury (\(\mathrm{Hg}\)) is an exception among metals, being most stable as a liquid.
  • Hydrogen naturally forms \(\mathrm{H}_2\) molecules and is a gas at room temperature.
Understanding the stable form is crucial for determining the standard enthalpy of formation for both elements and compounds.
Distinguishing Compounds and Elements
A major part of thermodynamics is understanding the distinction between compounds and elements. Elements are pure substances consisting of only one type of atom, and they serve as the building blocks for compounds. Compounds are formed when two or more elements chemically bond together.

Since elements in their most stable forms have a standard enthalpy of formation of zero, it is important to recognize these states to correctly assess the energy changes in compound formation. Chemical compounds, however, always have a non-zero standard enthalpy of formation because they are created from their elements.

For instance, methane (\(\mathrm{CH}_4\)) is a compound, not an element, so it does not have a zero enthalpy of formation. This highlights the process of elements reaching a more stable state through the formation of compounds, often releasing or absorbing energy in the process.
Exploring Phase Stability
Phase stability refers to the ability of a substance to remain in a particular physical state (solid, liquid, or gas) under specific conditions of temperature and pressure. It relates closely to the concept of the most stable form.

For most elements, the phase stability is quite intuitive:
  • Solids like sodium (\(\mathrm{Na}\)) tend to retain their structure until a high temperature is reached.
  • Gases such as neon (\(\mathrm{Ne}\)) are stable at room temperature under standard pressure conditions.
  • Mercury (\(\mathrm{Hg}\)) is unique due to its liquid phase stability at standard conditions.
In the case of sulfur (\(\mathrm{S}_8\)), the rhombic form is more stable than the monoclinic form at 25°C, hence the monoclinic form has a non-zero enthalpy of formation.

Recognizing these stability characteristics is essential for correctly identifying the energy changes involved when substances transition between phases or form new compounds.

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Most popular questions from this chapter

The \(\Delta H_{\mathrm{f}}^{\circ}\) values of the two allotropes of oxygen, \(\mathrm{O}_{2}\) and \(\mathrm{O}_{3}\), are 0 and \(142.2 \mathrm{~kJ} / \mathrm{mol}\), respectively, at \(25^{\circ} \mathrm{C}\). Which is the more stable form at this temperature?

(a) A person drinks four glasses of cold water \(\left(3.0^{\circ} \mathrm{C}\right)\) every day. The volume of each glass is \(2.5 \times 10^{2} \mathrm{~mL}\). How much heat (in kJ) does the body have to supply to raise the temperature of the water to \(37^{\circ} \mathrm{C},\) the body temperature? (b) How much heat would your body lose if you were to ingest \(8.0 \times 10^{2} \mathrm{~g}\) of snow at \(0^{\circ} \mathrm{C}\) to quench your thirst? (The amount of heat necessary to melt snow is \(6.01 \mathrm{~kJ} / \mathrm{mol}\).)

A woman expends \(95 \mathrm{~kJ}\) of energy walking a kilometer. The energy is supplied by the metabolic breakdown of food, which has an efficiency of 35 percent. How much energy does she save by walking the kilometer instead of driving a car that gets \(8.2 \mathrm{~km}\) per liter of gasoline (approximately \(20 \mathrm{mi} / \mathrm{gal}) ?\) The density of gasoline is \(0.71 \mathrm{~g} / \mathrm{mL},\) and its enthalpy of combustion is \(-49 \mathrm{~kJ} / \mathrm{g}\).

Define these terms: thermochemistry, exothermic process, endothermic process.

Calculate the amount of heat liberated (in kJ) from 366 \(\mathrm{g}\) of mercury when it cools from \(77.0^{\circ} \mathrm{C}\) to \(12.0^{\circ} \mathrm{C}\).

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