Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Write the equation for calculating the enthalpy of a reaction. Define all the terms.

Short Answer

Expert verified
The enthalpy change equation is \( \Delta H = \sum \Delta H_{products} - \sum \Delta H_{reactants} \).

Step by step solution

01

Understanding Enthalpy Change

Enthalpy change (\( \Delta H \)) of a chemical reaction represents the total change in heat content or energy of the system when the reaction occurs at constant pressure. It can be positive (endothermic reaction) or negative (exothermic reaction).
02

Writing the Equation for Enthalpy Change

The standard equation to calculate the enthalpy change of a chemical reaction is:\[ \Delta H = \sum \Delta H_{products} - \sum \Delta H_{reactants} \]This equation states that the enthalpy change for the reaction is the difference between the sum of the enthalpies of the products and the sum of the enthalpies of the reactants.
03

Defining the Terms

- \( \Delta H \): Enthalpy change of the reaction.- \( \sum \Delta H_{products} \): Sum of the enthalpies of the products, each multiplied by their respective coefficients from the balanced chemical equation.- \( \sum \Delta H_{reactants} \): Sum of the enthalpies of the reactants, each multiplied by their respective coefficients from the balanced chemical equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
Enthalpy change is an essential concept in chemistry that represents the amount of energy absorbed or released during a chemical reaction. When a reaction takes place at constant pressure, the enthalpy change, denoted as \( \Delta H \), describes how the total heat content of a system changes. If a reaction releases energy into the surrounding environment, it results in a negative enthalpy change. Conversely, if a reaction absorbs energy from its environment, the enthalpy change is positive.

The equation for calculating enthalpy change is as follows: \[ \Delta H = \sum \Delta H_{products} - \sum \Delta H_{reactants} \] This equation helps us determine whether the overall reaction is releasing or taking in energy.
  • \( \Delta H \): Represents the enthalpy change.
  • \( \sum \Delta H_{products} \): Is the total enthalpy of the products, considering their stoichiometric coefficients.
  • \( \sum \Delta H_{reactants} \): Is the total enthalpy of the reactants, also adjusted by their stoichiometric coefficients.
Endothermic and Exothermic Reactions
When studying chemical reactions, it's important to understand two key types based on energy changes. These are endothermic and exothermic reactions. Both rely heavily on the concept of enthalpy change.

Endothermic reactions are processes where the system absorbs energy from its surroundings. As a result, \( \Delta H \) is positive, indicating that energy is taken in to form bonds in products. Common examples include photosynthesis and melting ice.

Exothermic reactions, on the other hand, occur when energy is released into the surroundings, making \( \Delta H \) negative. This happens because the bonds formed in the products release more energy than was required to break the bonds of the reactants. Examples of exothermic reactions are combustion and respiration.

By understanding the direction and magnitude of energy flow, we are better equipped to predict the behavior of chemical reactions in real-world applications.
Enthalpy Calculation
Calculating enthalpy involves understanding the energy changes that occur in chemical reactions. This is achieved using the enthalpy equation, which considers the enthalpies of reactants and products.

The process typically begins with identifying the balanced chemical equation for the reaction in question. Each reactant and product has a specific enthalpy value, often sourced from empirical data or standard tables. These values are then multiplied by their coefficients from the chemical equation.

Once all enthalpy values are adjusted accordingly, sum the enthalpies of the products and the reactants separately. Subtracting the total enthalpy of reactants from the total enthalpy of products will yield the overall enthalpy change, \( \Delta H \).
  • Understand and balance the chemical equation.
  • Adjust enthalpies using stoichiometric coefficients.
  • Calculate total enthalpy for reactants and products separately.
  • Find \( \Delta H \) using the enthalpy difference.
This calculation is vital for determining how energy flows within chemical reactions and is particularly useful in predicting reaction behavior and designing energy-efficient processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The standard enthalpy change for the following reaction is \(436.4 \mathrm{~kJ} / \mathrm{mol}\) : $$\mathrm{H}_{2}(g) \longrightarrow \mathrm{H}(g)+\mathrm{H}(g)$$ Calculate the standard enthalpy of formation of atomic hydrogen (H).

A \(3.52-\mathrm{g}\) sample of ammonium nitrate \(\left(\mathrm{NH}_{4} \mathrm{NO}_{3}\right)\) was added to \(80.0 \mathrm{~mL}\) of water in a constant-pressure calorimeter of negligible heat capacity. As a result, the temperature of the solution decreased from \(21.6^{\circ} \mathrm{C}\) to \(18.1^{\circ} \mathrm{C} .\) Calculate the heat of solution \(\left(\Delta H_{\mathrm{soln}}\right)\) in \(\mathrm{kJ} / \mathrm{mol}:\) \(\mathrm{NH}_{4} \mathrm{NO}_{3}(s) \longrightarrow \mathrm{NH}_{4}^{+}(a q)+\mathrm{NO}_{3}^{-}(a q)\) Assume the specific heat of the solution is the same as that of water.

Explain the meaning of this thermochemical equation:$$\begin{aligned}4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow & 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) \\ \Delta H=-904 \mathrm{~kJ} / \mathrm{mol}\end{aligned}$$

A 46-kg person drinks \(500 \mathrm{~g}\) of milk, which has a "caloric" value of approximately \(3.0 \mathrm{~kJ} / \mathrm{g}\). If only 17 percent of the energy in milk is converted to mechanical work, how high (in meters) can the person climb based on this energy intake?

A man ate 0.50 pound of cheese (an energy intake of \(4 \times 10^{3} \mathrm{~kJ}\) ). Suppose that none of the energy was stored in his body. What mass (in grams) of water would he need to perspire in order to maintain his original temperature? (It takes \(44.0 \mathrm{~kJ}\) to vaporize 1 mole of water.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free