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Define calorimetry and describe two commonly used calorimeters. In a calorimetric measurement, why is it important that we know the heat capacity of the calorimeter? How is this value determined?

Short Answer

Expert verified
Calorimetry measures heat changes; important calorimeters include bomb and coffee cup. Knowing heat capacity is crucial for accuracy and is determined via calibration.

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01

Understanding Calorimetry

Calorimetry is a technique used to measure the amount of heat involved in chemical reactions or physical changes. It helps in determining the heat transfer in a thermodynamic system.
02

Commonly Used Calorimeters

Two commonly used calorimeters are the Bomb Calorimeter and the Coffee Cup Calorimeter. The Bomb Calorimeter is used for measuring the energy content of substances, typically fuels and food, in a closed environment at constant volume. The Coffee Cup Calorimeter, on the other hand, is used at constant pressure and is often employed in education settings for simpler reactions.
03

Importance of Knowing Heat Capacity

Knowing the heat capacity of the calorimeter is crucial because it allows for more accurate measurements of the heat being transferred. Without this knowledge, it is impossible to determine the exact amount of heat released or absorbed by the substance being tested, since the calorimeter itself absorbs some of the heat.
04

Determination of Heat Capacity

The heat capacity of a calorimeter is usually determined by a calibration experiment. This involves adding a known quantity of heat to the calorimeter and measuring the resultant change in temperature. From this data, the heat capacity can be calculated using the formula \[ C_{cal} = \frac{q}{\Delta T} \]where \( C_{cal} \) is the heat capacity of the calorimeter, \( q \) is the known amount of heat added, and \( \Delta T \) is the change in temperature of the calorimeter.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Capacity
Understanding heat capacity is fundamental when involving calorimetry. Heat capacity is defined as the amount of heat required to change the temperature of a system by one degree Celsius.
  • It provides an idea of how much heat energy a calorimeter can absorb or release.
  • Knowing the heat capacity allows the user to correct measurements of heat flow, ensuring accuracy in calorimetric experiments.
  • Temperature changes in a calorimeter can directly affect calculated values, making heat capacity crucial.
Heat capacity is typically represented by the symbol \( C \). To determine the heat capacity of a calorimeter, you may perform a simple experiment by adding a known quantity of heat and measuring the temperature change. The heat capacity \( C_{cal} \) can then be calculated using \( C_{cal} = \frac{q}{\Delta T} \), where \( q \) is the amount of heat added, and \( \Delta T \) is the temperature change.
Bomb Calorimeter
The bomb calorimeter is a device used mainly for measuring the energy content of substances such as fuels and foods. This type of calorimeter operates in a closed system at constant volume.
  • It is designed to withstand high pressures, allowing for the combustion of solid and liquid samples.
  • Since the volume remains constant, any heat changes translate directly to internal energy changes.

The bomb calorimeter is composed of a robust container, often referred to as a "bomb," within which the reaction takes place. This container is submerged in a water bath which helps in measuring temperature changes resulting from the heat of reaction. Since the bomb calorimeter is isolated from its surroundings, it ensures minimal energy loss, increasing the accuracy of the measurements. The energy change measured is considered the internal energy of the reaction, providing vital information about the calorific value of the substance being tested.
Coffee Cup Calorimeter
The coffee cup calorimeter is another commonly used calorimeter, more frequently seen in educational settings. It operates at constant pressure, which makes it ideal for reactions occurring in open systems. The coffee cup calorimeter is relatively simple to set up and is more accessible than the bomb calorimeter.
  • It typically involves using a styrofoam cup to minimize energy loss to the environment.
  • It is most effective for reactions that occur in aqueous solutions, like neutralization reactions.
The reaction takes place in the solution within the cup, and the resulting temperature change is measured using a thermometer. As the system is at constant pressure, the heat change measured corresponds to the enthalpy change of the reaction. However, due to possible heat loss to the environment and the fact that it is less isolated than a bomb calorimeter, corrections using the heat capacity are often necessary.
Thermodynamic System
A thermodynamic system is an essential concept in the study of calorimetry. It refers to the material and energy being studied, isolated from the surroundings, which are everything else in the universe.
  • When performing calorimetry, the system is typically the chemical substances involved in the reaction.
  • Heat transfer occurs between the system and its surroundings.

There are three kinds of systems in thermodynamics:
  • Open System: Allows both energy and matter to be exchanged with the surroundings.
  • Closed System: Exchanges energy but not matter with its surroundings, as seen in a bomb calorimeter.
  • Isolated System: Neither energy nor matter exchanges occur with the environment.
Understanding the type of thermodynamic system at hand helps in predicting the behavior of the system during calorimetry experiments. It also guides the interpretation of experimental results, offering insights into the fundamental principles of thermodynamics.

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Most popular questions from this chapter

For which of the following reactions does \(\Delta H_{\mathrm{rxn}}^{\circ}=\Delta H_{\mathrm{f}}^{\circ}\) ? (a) \(\mathrm{H}_{2}(g)+\mathrm{S}(\) rhombic \() \longrightarrow \mathrm{H}_{2} \mathrm{~S}(g)\) (b) \(\mathrm{C}(\) diamond \()+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)\) (c) \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{CuO}(s) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Cu}(s)\) (d) \(\mathrm{O}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{O}_{3}(g)\)

Ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) and gasoline (assumed to be all octane, \(\mathrm{C}_{8} \mathrm{H}_{18}\) ) are both used as automobile fuel. If gasoline is selling for \(\$ 2.20 / \mathrm{gal},\) what would the price of ethanol have to be in order to provide the same amount of heat per dollar? The density and \(\Delta H_{\mathrm{f}}^{\circ}\) of octane are \(0.7025 \mathrm{~g} / \mathrm{mL}\) and \(-249.9 \mathrm{~kJ} / \mathrm{mol}\), respectively, and of ethanol are \(0.7894 \mathrm{~g} / \mathrm{mL}\) and \(-277.0 \mathrm{~kJ} / \mathrm{mol}\) respectively \((1 \mathrm{gal}=3.785 \mathrm{~L})\).

Calculate the heat released when \(2.00 \mathrm{~L}\) of \(\mathrm{Cl}_{2}(g)\) with a density of \(1.88 \mathrm{~g} / \mathrm{L}\) reacts with an excess of sodium metal at \(25^{\circ} \mathrm{C}\) and 1 atm to form sodium chloride.

A woman expends \(95 \mathrm{~kJ}\) of energy walking a kilometer. The energy is supplied by the metabolic breakdown of food, which has an efficiency of 35 percent. How much energy does she save by walking the kilometer instead of driving a car that gets \(8.2 \mathrm{~km}\) per liter of gasoline (approximately \(20 \mathrm{mi} / \mathrm{gal}) ?\) The density of gasoline is \(0.71 \mathrm{~g} / \mathrm{mL},\) and its enthalpy of combustion is \(-49 \mathrm{~kJ} / \mathrm{g}\).

Glauber's salt, sodium sulfate decahydrate \(\left(\mathrm{Na}_{2} \mathrm{SO}_{4} .\right.\) \(\left.10 \mathrm{H}_{2} \mathrm{O}\right),\) undergoes a phase transition (i.e., melting or freezing) at a convenient temperature of about \(32^{\circ} \mathrm{C}\) : \(\begin{aligned}{\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}(s) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}(l)}{\Delta H^{\circ}} &=74.4 \mathrm{~kJ} / \mathrm{mol} \end{aligned}\) As a result, this compound is used to regulate the temperature in homes. It is placed in plastic bags in the ceiling of a room. During the day, the endothermic melting process absorbs heat from the surroundings, cooling the room. At night, it gives off heat as it freezes. Calculate the mass of Glauber's salt in kilograms needed to lower the temperature of air in a room by \(8.2^{\circ} \mathrm{C}\). The mass of air in the room is \(605.4 \mathrm{~kg} ;\) the specific heat of air is \(1.2 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\).

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