Chapter 4: Problem 46
Give the oxidation number for the following species: \(\mathrm{H}_{2}, \mathrm{Se}_{\mathrm{g}}, \mathrm{P}_{4}, \mathrm{O}, \mathrm{U}, \mathrm{As}_{4}, \mathrm{~B}_{12}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Free Elements
- \(\mathrm{H}_2\) represents hydrogen gas made entirely of hydrogen atoms.
- \(\mathrm{U}\) is simply pure uranium.
- \(\mathrm{As}_4\) is elemental arsenic in its natural form.
Chemical Compounds
- A compound like water, \(\mathrm{H}_2\mathrm{O}\), is not a free element, but a chemical compound with hydrogen and oxygen atoms bonded together.
- The oxidation number for hydrogen in \(\mathrm{H}_2\mathrm{O}\) is +1, while for oxygen it is -2, reflecting their electron-sharing behavior in the compound.
Oxidation State
- The oxidation state of a free element, as discussed earlier, is always zero due to no electron transfer occurring.
- In a chemical compound, elements have oxidation states that reflect their bonding and electron interaction. For instance, in \(\mathrm{NaCl}\), sodium has an oxidation state of +1 and chlorine -1, illustrating their electron transfer relationship.
- Oxidation states can also guide the balancing of chemical equations, aiding in the understanding of how atoms combine and rearrange during reactions.