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Describe hydration. What properties of water enable its molecules to interact with ions in solution?

Short Answer

Expert verified
Water's polarity enables it to surround and stabilize ions in solution.

Step by step solution

01

Define Hydration

Hydration refers to the process where water molecules surround and interact with other particles, such as ions, molecules, or compounds. In a solution, this interaction helps to dissolve ionic substances by stabilizing the ions with water molecules.
02

Understand Water's Polarity

Water molecules are polar because they have a partial negative charge near the oxygen atom and a partial positive charge near the hydrogen atoms. This polarity allows water molecules to interact with ions effectively.
03

Attraction between Water Molecules and Ions

Positive ions (\[\text{cations}\]) in a solution are attracted to the negatively charged oxygen end of water molecules, while negative ions (\[\text{anions}\]) are attracted to the positively charged hydrogen ends. This creates a sphere of hydration around each ion.
04

Stabilization of Ions in Solution

The water molecules form a hydration shell around each ion, reducing electrostatic interactions between the ions and thus stabilizing them in the solution. This is essential in the dissolution process, enabling the ions to be uniformly distributed in the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polarity of Water
Water, a crucial molecule for life, exhibits a fascinating property known as polarity. Polarity refers to the uneven distribution of electrical charge across a molecule. Water molecules have a unique structure, featuring one large oxygen atom bonded to two smaller hydrogen atoms. The oxygen atom is more electronegative, which means it attracts electrons more strongly than the hydrogen atoms do.
The result is a slight negative charge near the oxygen and a slight positive charge near the hydrogens. This creates a dipole moment, with two distinct poles of charge. Because of this polarity, water molecules are excellent at forming hydrogen bonds. These bonds enable water to interact with a wide variety of substances, especially ionic compounds, and contribute to water's role as a "universal solvent."
Understanding water's polarity offers insight into why it can efficiently surround and stabilize ions in solution, aiding in their dissolution and distribution.
Hydration Shell
The concept of a hydration shell is key to understanding how water interacts with ions. When an ionic compound dissolves in water, the water molecules arrange themselves around individual ions. The negatively charged end of the water molecule (oxygen side) is drawn to positively charged ions, known as cations. Conversely, the positively charged end (hydrogen side) is attracted to negatively charged ions, known as anions.
This clustering of water molecules around each ion forms what is known as a hydration shell. These shells mitigate the electrostatic forces that might cause the ions to recouple. By effectively insulating the ions from each other, hydration shells increase the solubility of ionic compounds. This reduces the tendency of ions to precipitate out of the solution, maintaining their dispersion throughout the liquid.
Ionic Dissolution
Ionic dissolution is the process by which ionic compounds disintegrate into separate ions within a solvent, typically water. When an ionic solid is introduced to water, the polar water molecules interact with the solid's cations and anions. Due to the opposite charges attract principle, water molecules pull ions away from the lattice of the solid.
The attraction between the polar water molecules and the individual ions surpasses the ionic forces holding the compound together. As ions are surrounded by water, hydration shells are formed, which stabilize them and keep them in solution. This phenomenon is crucial for numerous bodily processes and industrial applications where reacting substances need to be in a dissolved, reactive state.
Thus, ionic dissolution is a fundamental chemical process that underpins many natural and artificial systems essential to life and technology.

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Most popular questions from this chapter

Calculate the volume in milliliters of a solution required to provide the following: (a) \(2.14 \mathrm{~g}\) of sodium chloride from a \(0.270-M\) solution, (b) \(4.30 \mathrm{~g}\) of ethanol from a \(1.50-M\) solution, (c) \(0.85 \mathrm{~g}\) of acetic acid \(\left(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)\) from a \(0.30-M\) solution.

A 0.9157 -g mixture of \(\mathrm{CaBr}_{2}\) and NaBr is dissolved in water, and \(\mathrm{AgNO}_{3}\) is added to the solution to form AgBr precipitate. If the mass of the precipitate is \(1.6930 \mathrm{~g}\), what is the percent by mass of \(\mathrm{NaBr}\) in the original mixture?

Describe in each case how you would separate the cations or anions in the following aqueous solutions: (a) \(\mathrm{NaNO}_{3}\) and \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) (b) \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) and \(\mathrm{K} \mathrm{NO}_{3},\) (c) \(\mathrm{KBr}\) and \(\mathrm{KNO}_{3},\) (d) \(\mathrm{K}_{3} \mathrm{PO}_{4}\) and \(\mathrm{KNO}_{3},\) (e) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(\mathrm{NaNO}_{3}\)

Describe how to prepare \(1.00 \mathrm{~L}\) of a \(0.646 \mathrm{M} \mathrm{HCl}\) solution, starting with a \(2.00 \mathrm{M} \mathrm{HCl}\) solution.

Hydrogen halides \((\mathrm{HF}, \mathrm{HCl}, \mathrm{HBr}, \mathrm{HI})\) are highly reactive compounds that have many industrial and laboratory uses. (a) In the laboratory, HF and \(\underline{H C l}\) can be generated by combining \(\mathrm{CaF}_{2}\) and \(\mathrm{NaCl}\) with concentrated sulfuric acid. Write appropriate equations for the reactions. (Hint: These are not redox reactions.) (b) Why is it that \(\mathrm{HBr}\) and HI cannot be prepared similarly, that is, by combining NaBr and NaI with concentrated sulfuric acid? (Hint: \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is a stronger oxidizing agent than both \(\mathrm{Br}_{2}\) and \(\mathrm{I}_{2} .\) ) \((\mathrm{c}) \mathrm{HBr}\) can be prepared by reacting phosphorus tribromide \(\left(\mathrm{PBr}_{3}\right)\) with water. Write an equation for this reaction.

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