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Describe hydration. What properties of water enable its molecules to interact with ions in solution?

Short Answer

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Water's polarity enables it to surround and stabilize ions in solution.

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01

Define Hydration

Hydration refers to the process where water molecules surround and interact with other particles, such as ions, molecules, or compounds. In a solution, this interaction helps to dissolve ionic substances by stabilizing the ions with water molecules.
02

Understand Water's Polarity

Water molecules are polar because they have a partial negative charge near the oxygen atom and a partial positive charge near the hydrogen atoms. This polarity allows water molecules to interact with ions effectively.
03

Attraction between Water Molecules and Ions

Positive ions (\[\text{cations}\]) in a solution are attracted to the negatively charged oxygen end of water molecules, while negative ions (\[\text{anions}\]) are attracted to the positively charged hydrogen ends. This creates a sphere of hydration around each ion.
04

Stabilization of Ions in Solution

The water molecules form a hydration shell around each ion, reducing electrostatic interactions between the ions and thus stabilizing them in the solution. This is essential in the dissolution process, enabling the ions to be uniformly distributed in the solution.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polarity of Water
Water, a crucial molecule for life, exhibits a fascinating property known as polarity. Polarity refers to the uneven distribution of electrical charge across a molecule. Water molecules have a unique structure, featuring one large oxygen atom bonded to two smaller hydrogen atoms. The oxygen atom is more electronegative, which means it attracts electrons more strongly than the hydrogen atoms do.
The result is a slight negative charge near the oxygen and a slight positive charge near the hydrogens. This creates a dipole moment, with two distinct poles of charge. Because of this polarity, water molecules are excellent at forming hydrogen bonds. These bonds enable water to interact with a wide variety of substances, especially ionic compounds, and contribute to water's role as a "universal solvent."
Understanding water's polarity offers insight into why it can efficiently surround and stabilize ions in solution, aiding in their dissolution and distribution.
Hydration Shell
The concept of a hydration shell is key to understanding how water interacts with ions. When an ionic compound dissolves in water, the water molecules arrange themselves around individual ions. The negatively charged end of the water molecule (oxygen side) is drawn to positively charged ions, known as cations. Conversely, the positively charged end (hydrogen side) is attracted to negatively charged ions, known as anions.
This clustering of water molecules around each ion forms what is known as a hydration shell. These shells mitigate the electrostatic forces that might cause the ions to recouple. By effectively insulating the ions from each other, hydration shells increase the solubility of ionic compounds. This reduces the tendency of ions to precipitate out of the solution, maintaining their dispersion throughout the liquid.
Ionic Dissolution
Ionic dissolution is the process by which ionic compounds disintegrate into separate ions within a solvent, typically water. When an ionic solid is introduced to water, the polar water molecules interact with the solid's cations and anions. Due to the opposite charges attract principle, water molecules pull ions away from the lattice of the solid.
The attraction between the polar water molecules and the individual ions surpasses the ionic forces holding the compound together. As ions are surrounded by water, hydration shells are formed, which stabilize them and keep them in solution. This phenomenon is crucial for numerous bodily processes and industrial applications where reacting substances need to be in a dissolved, reactive state.
Thus, ionic dissolution is a fundamental chemical process that underpins many natural and artificial systems essential to life and technology.

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Most popular questions from this chapter

A volume of \(46.2 \mathrm{~mL}\) of a \(0.568 M\) calcium nitrate \(\left[\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\right]\) solution is mixed with \(80.5 \mathrm{~mL}\) of a \(1.396 M\) calcium nitrate solution. Calculate the concentration of the final solution.

Calculate the volume in milliliters of a \(1.420 \mathrm{M} \mathrm{NaOH}\) solution required to titrate the following solutions: a) \(25.00 \mathrm{~mL}\) of a \(2.430 \mathrm{M} \mathrm{HCl}\) solution b) \(25.00 \mathrm{~mL}\) of a \(4.500 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) solution c) \(25.00 \mathrm{~mL}\) of a \(1.500 \mathrm{M} \mathrm{H}_{3} \mathrm{PO}_{4}\) solution

Classify the following redox reactions as combination, decomposition, or displacement: (a) \(\mathrm{P}_{4}+10 \mathrm{Cl}_{2} \longrightarrow 4 \mathrm{PCl}_{5}\) (b) \(2 \mathrm{NO} \longrightarrow \mathrm{N}_{2}+\mathrm{O}_{2}\) (c) \(\mathrm{Cl}_{2}+2 \mathrm{KI} \longrightarrow 2 \mathrm{KCl}+\mathrm{I}_{2}\) (d) \(3 \mathrm{HNO}_{2} \longrightarrow \mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{NO}\)

Give a chemical explanation for each of the following: (a) When calcium metal is added to a sulfuric acid solution, hydrogen gas is generated. After a few minutes, the reaction slows down and eventually stops even though none of the reactants is used up. Explain. (b) In the activity series, aluminum is above hydrogen, yet the metal appears to be unreactive toward hydrochloric acid. Why? (Hint: Al forms an oxide, \(\mathrm{Al}_{2} \mathrm{O}_{3},\) on the surface.) (c) Sodium and potassium lie above copper in the activity series. Explain why \(\mathrm{Cu}^{2+}\) ions in a \(\mathrm{CuSO}_{4}\) solution are not converted to metallic copper upon the addition of these metals. (d) A metal M reacts slowly with steam. There is no visible change when it is placed in a pale green iron(II) sulfate solution. Where should we place \(\mathrm{M}\) in the activity series? (e) Before aluminum metal was obtained by electrolysis, it was produced by reducing its chloride \(\left(\mathrm{AlCl}_{3}\right)\) with an active metal. What metals would you use to produce aluminum in that way?

Calculate the concentration of the acid (or base) remaining in solution when \(10.7 \mathrm{~mL}\) of \(0.211 \mathrm{M} \mathrm{HNO}_{3}\) is added to \(16.3 \mathrm{~mL}\) of \(0.258 \mathrm{M} \mathrm{NaOH}\).

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