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Explain why a solution of \(\mathrm{HCl}\) in benzene does not conduct electricity but in water it does.

Short Answer

Expert verified
HCl conducts electricity in water due to ionization but not in benzene, as it stays undissociated.

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01

Understanding HCl in Different Solvents

Hydrochloric acid (HCl) behaves differently depending on the solvent it is in. In water, HCl dissociates into ions, but in benzene, it does not.
02

Observing HCl in Water

In water, HCl dissociates into hydrogen ions ( ext{H}^+) and chloride ions ( ext{Cl}^-). This process is called ionization: \[ ext{HCl (aq)} ightarrow ext{H}^+ (aq) + ext{Cl}^- (aq) \]These ions are charged particles that move freely in solution, conducting electricity.
03

Observing HCl in Benzene

Benzene is a non-polar solvent, which means it does not support the ionization of HCl. As a result, HCl remains in its molecular form (HCl) in benzene, without dissociating into ions.
04

Comparing the Effects

The presence of free-moving ions is essential for the conduction of electricity. Since HCl in water generates ions and HCl in benzene does not, electricity is conducted in the aqueous HCl solution but not in benzene.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization
When hydrochloric acid (HCl) is dissolved in water, it undergoes a process called ionization. During ionization, HCl molecules dissociate into hydrogen ions (\( \text{H}^+ \)) and chloride ions (\( \text{Cl}^- \)). Water is a polar solvent, with a unique ability to stabilize these ions. This is why water facilitates the ionization of HCl effectively.In contrast, when HCl is mixed with benzene, a non-polar solvent, there is no ionization. Benzene does not have the ability to stabilize ions like water does. Therefore, HCl remains as intact molecules in benzene. This difference is crucial since the presence or absence of ions directly affects the solution's properties, such as electrical conductivity.
Conductivity
For a solution to conduct electricity, it must contain free-moving charged particles (ions). In the case of HCl in water, the ionization process produces hydrogen ions and chloride ions. These ions move freely in the aqueous solution, allowing electricity to pass through. However, in benzene, there is no ion formation because it doesn't support the ionization of HCl. Since there are no ions present to carry an electric current, a solution of HCl in benzene is unable to conduct electricity. Thus, understanding electrical conductivity in solutions requires an appreciation of how and why ions are formed.
Polar and Non-polar Solvents
The type of solvent plays a crucial role in determining whether a solute like HCl will ionize. Polar solvents, such as water, have molecules with positive and negative ends (dipoles) that can surround and stabilize ions formed from substances like HCl. Non-polar solvents, like benzene, lack this dipole characteristic. They have even distributions of electrical charge, meaning they cannot stabilize charged ions the way polar solvents do. Thus, polar solvents facilitate the ionization of solutes like HCl, while non-polar solvents do not. This fundamental difference in solvent properties explains why HCl behaves differently in water versus benzene.
Dissociation of Acids
Dissociation refers to the process where molecules split into smaller particles, usually ions. In the context of acids like HCl, dissociation is where the acid molecule separates into hydrogen ions and corresponding anions (chloride ions, in this case). This process is driven primarily by the nature of the solvent. A polar solvent encourages acid dissociation, while a non-polar solvent does not. Understanding dissociation is important because it is directly linked to the concept of acidity and conductivity in solutions. Without dissociation, an acid cannot exhibit its typical acidic or conductive properties, as seen with HCl in benzene.

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Most popular questions from this chapter

A student carried out two titrations using an \(\mathrm{NaOH}\) solution of unknown concentration in the burette. In one titration, she weighed out \(0.2458 \mathrm{~g}\) of KHP ([see page \(166 .]\) ) and transferred it to an Erlenmeyer flask. She then added \(20.00 \mathrm{~mL}\) of distilled water to dissolve the acid. In the other titration, she weighed out \(0.2507 \mathrm{~g}\) of KHP but added \(40.00 \mathrm{~mL}\) of distilled water to dissolve the acid. Assuming no experimental error, would she obtain the same result for the concentration of the \(\mathrm{NaOH}\) solution?

What volume of a \(0.500 \mathrm{M} \mathrm{HCl}\) solution is needed to neutralize each of the following: a) \(10.0 \mathrm{~mL}\) of a \(0.300 \mathrm{M} \mathrm{NaOH}\) solution b) \(10.0 \mathrm{~mL}\) of a \(0.200 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) solution

Give a chemical explanation for each of the following: (a) When calcium metal is added to a sulfuric acid solution, hydrogen gas is generated. After a few minutes, the reaction slows down and eventually stops even though none of the reactants is used up. Explain. (b) In the activity series, aluminum is above hydrogen, yet the metal appears to be unreactive toward hydrochloric acid. Why? (Hint: Al forms an oxide, \(\mathrm{Al}_{2} \mathrm{O}_{3},\) on the surface.) (c) Sodium and potassium lie above copper in the activity series. Explain why \(\mathrm{Cu}^{2+}\) ions in a \(\mathrm{CuSO}_{4}\) solution are not converted to metallic copper upon the addition of these metals. (d) A metal M reacts slowly with steam. There is no visible change when it is placed in a pale green iron(II) sulfate solution. Where should we place \(\mathrm{M}\) in the activity series? (e) Before aluminum metal was obtained by electrolysis, it was produced by reducing its chloride \(\left(\mathrm{AlCl}_{3}\right)\) with an active metal. What metals would you use to produce aluminum in that way?

(a) Determine the chloride ion concentration in each of the following solutions: \(0.150 \mathrm{M} \mathrm{BaCl}_{2}, 0.566 \mathrm{M} \mathrm{NaCl}\), \(1.202 \mathrm{M} \mathrm{AlCl}_{3}\) (b) What is the concentration of a \(\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}\) solution that is \(2.55 \mathrm{M}\) in nitrate ion?

Classify the following redox reactions as combination, decomposition, or displacement: (a) \(\mathrm{P}_{4}+10 \mathrm{Cl}_{2} \longrightarrow 4 \mathrm{PCl}_{5}\) (b) \(2 \mathrm{NO} \longrightarrow \mathrm{N}_{2}+\mathrm{O}_{2}\) (c) \(\mathrm{Cl}_{2}+2 \mathrm{KI} \longrightarrow 2 \mathrm{KCl}+\mathrm{I}_{2}\) (d) \(3 \mathrm{HNO}_{2} \longrightarrow \mathrm{HNO}_{3}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{NO}\)

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