Chapter 4: Problem 120
You are given two colorless solutions, one containing \(\mathrm{NaCl}\) and the other sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right) .\) Suggest a chemical and a physical test that would allow you to distinguish between these two solutions.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Compounds
Ionic compounds, such as sodium chloride (\( \text{NaCl} \)), typically have high melting and boiling points. When dissolved in water, they dissociate into their respective ions and create a solution that can conduct electricity.
- They are usually soluble in water but not in non-polar solvents.
- Commonly used in various applications like electrolytes in batteries or deicing roads.
Covalent Compounds
The resulting molecules do not carry a charge, so covalent compounds generally do not conduct electricity when dissolved in water.
- Covalent compounds often have lower melting and boiling points compared to ionic compounds.
- They can be found in various states: gases, liquids, or solids at room temperature.
Conductivity Test
In this test:
- An ionic compound, like \( \text{NaCl} \), will increase the solution's conductivity because of its dissolved ions.
- A covalent compound, such as sucrose, will not dissociate into ions, resulting in low or no conductivity.
Precipitation Reaction
- Precipitation reactions help identify the presence of ions that form insoluble compounds.
- They are utilized in various applications, such as water treatment and testing water hardness.
Chemical Properties of Solutions
Covalent solutions, on the other hand, usually involve entirely different interactions:
- They might participate in unique reactions, like sugar dissolving in water without breaking into ions.
- Their reactions often involve changes to the molecules themselves rather than forming a different state like a precipitate.