Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Identify each of the following compounds as a nonelectrolyte, a weak electrolyte, or a strong electrolyte: (a) lactose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right),(\mathrm{b})\) lactic acid \(\left(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right),\) (c) dimethylamine \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\right]\), (d) barium hydroxide \(\left[\mathrm{Ba}(\mathrm{OH})_{2}\right]\)

Short Answer

Expert verified
(a) Nonelectrolyte, (b) Weak electrolyte, (c) Weak electrolyte, (d) Strong electrolyte.

Step by step solution

01

Understanding Electrolytes

Compounds are classified into three types based on their ability to conduct electricity when dissolved in water: nonelectrolytes, which do not conduct electricity, weak electrolytes, which partially ionize and partially conduct electricity, and strong electrolytes, which completely ionize and conduct electricity efficiently.
02

Analyze Lactose

Lactose is a sugar with the molecular formula \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\). Sugars are covalent compounds that do not ionize in solution, making them nonelectrolytes.
03

Analyze Lactic Acid

Lactic acid \(\left(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right)\) is a weak acid. Weak acids partially ionize in water; thus, lactic acid is a weak electrolyte.
04

Analyze Dimethylamine

Dimethylamine \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\right]\) is a weak base. Similar to weak acids, weak bases partially ionize in solution, classifying dimethylamine as a weak electrolyte.
05

Analyze Barium Hydroxide

Barium hydroxide \(\left[\mathrm{Ba}( ext{OH})_{2}\right]\) is a strong base which fully dissociates into barium ions and hydroxide ions in solution, making it a strong electrolyte.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonelectrolyte
Nonelectrolytes are substances that do not produce ions or electric currents when dissolved in water. Simply put, they do not conduct electricity in a solution. These compounds typically consist of molecules without charge, such as sugars and many types of organic compounds.
For instance, lactose, with the formula \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\), is a nonelectrolyte. Even when dissolved, lactose doesn't break into ions. It remains as whole, neutral molecules in the solution.
  • Examples: Sugar, Ethanol, Urea
  • Does not ionize or dissociate in water
  • Cannot conduct electricity in solution
Weak Electrolyte
Weak electrolytes are compounds that partially ionize in solution. They exist in a state of equilibrium between the ionized and non-ionized forms. This partial ionization means they only partially conduct electricity.
Taking lactic acid, \(\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3} \), as an example, in solution, it does not completely break into its ions. This quality makes it a weak electrolyte.
  • Partially ionizes in water
  • Weak acids and bases are common examples
  • Conducts electricity poorly compared to strong electrolytes
Strong Electrolyte
Strong electrolytes are substances that fully ionize or dissociate in solution. They break down completely into ions, ensuring efficient electrical conduction.
A strong base like barium hydroxide \( \mathrm{Ba(OH)}_{2} \) is a strong electrolyte. In water, it dissociates entirely into barium \( \mathrm{Ba}^{2+} \) and hydroxide ions \( \mathrm{OH}^{-} \), allowing for excellent electrical conductivity.
  • Completely ionizes in solution
  • Includes most salts, strong acids, and strong bases
  • Conducts electricity very efficiently
Dissociation
Dissociation refers to the process where ionic compounds separate into positive and negative ions. This process is crucial for substances to act as electrolytes in solution.
Dissociation occurs in strong electrolytes like barium hydroxide, \( \mathrm{Ba(OH)}_{2} \), where the compound splits into \( \mathrm{Ba}^{2+} \) and \( \mathrm{OH}^{-} \) ions.
  • Applies mainly to ionic compounds
  • Drives the conductivity in strong electrolytes
  • Complete dissociation results in full electrical conduction
Ionization
Ionization is the process by which a neutral molecule produces charged ions. It is particularly relevant for acids and bases that do not naturally exist as ions. Unlike dissociation, which involves already-ionic substances, ionization can turn neutral molecules into ions.
Consider dimethylamine \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\right]\), which ionizes weakly in water. It forms a small number of \(\mathrm{CH}_{3}\) and \(\mathrm{NH}^{+}\) ions, qualifying it as a weak electrolyte.
  • Relates to the formation of ions from neutral molecules
  • Important for acids and bases
  • Weak ionization leads to weak electrical conduction

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine the mass of product that will precipitate when \(125.2 \mathrm{~mL} 0.8015 \mathrm{M} \mathrm{AgNO}_{3}\) and \(50.00 \mathrm{~mL}\) of \(0.7850 \mathrm{M} \mathrm{Na}_{2} \mathrm{Cr} \mathrm{O}_{4}\) are combined.

Predict the outcome of the reactions represented by the following equations by using the activity series, and balance the equations. (a) \(\mathrm{Cu}(s)+\mathrm{HCl}(a q) \longrightarrow\) (b) \(\mathrm{Au}(s)+\operatorname{NaBr}(a q)\) (c) \(\mathrm{Mg}(s)+\mathrm{CuSO}_{4}(a q)\) (d) \(\operatorname{Zn}(s)+\operatorname{KBr}(a q)\)

Give the oxidation numbers for the underlined atoms in the following molecules and ions: (a) \(\mathrm{Mg}_{3} \mathrm{~N}_{2},\) (b) \(\mathrm{Cs} \underline{\mathrm{O}}_{2},\) (c) \(\mathrm{Ca} \underline{\mathrm{C}}_{2}\) (d) \(\mathrm{CO}_{3}^{2-}\), (e) \(\underline{\mathrm{C}}_{2} \mathrm{O}_{4}^{2-}\) (f) \(\mathrm{ZnO}_{2}^{2-},(\mathrm{g}) \mathrm{Na} \underline{\mathrm{B}} \mathrm{H}_{4}\) (h) \(\underline{\mathrm{W}} \mathrm{O}_{4}^{2-}\)

Sulfites (compounds containing the \(\mathrm{SO}_{3}^{2-}\) ions) are used as preservatives in dried fruits and vegetables and in wine making. In an experiment to test for the presence of sulfite in fruit, a student first soaked several dried apricots in water overnight and then filtered the solution to remove all solid particles. She then treated the solution with hydrogen peroxide \(\left(\mathrm{H}_{2} \mathrm{O}_{2}\right)\) to oxidize the sulfite ions to sulfate ions. Finally, the sulfate ions were precipitated by treating the solution with a few drops of a barium chloride \(\left(\mathrm{BaCl}_{2}\right)\) solution. Write a balanced equation for each of the preceding steps.

Hydrochloric acid is not an oxidizing agent in the sense that sulfuric acid and nitric acid are. Explain why the chloride ion is not a strong oxidizing agent like \(\mathrm{SO}_{4}^{2-}\) and \(\mathrm{NO}_{3}^{-}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free