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Define solute, solvent, and solution by describing the process of dissolving a solid in a liquid.

Short Answer

Expert verified
A solute is what is dissolved, a solvent does the dissolving, and a solution is the uniform mixture formed.

Step by step solution

01

Understanding Components

In a solution, there are two main components: the solute and the solvent. The solute is the substance that is being dissolved, and it is typically present in a smaller amount. The solvent is the substance that does the dissolving, and it is usually present in a larger amount. When a solid dissolves in a liquid, the solid is considered the solute and the liquid is the solvent.
02

Definition of Solution

A solution is a homogenous mixture formed when the solute completely dissolves in the solvent. This mixture has uniform properties throughout, meaning that the solute particles are evenly distributed within the solvent. The consistency of the solution ensures that it does not separate over time, provided conditions are stable.
03

The Dissolving Process

The dissolving process involves the interaction between the solute and solvent molecules. As the solid (solute) is introduced to the liquid (solvent), the solvent molecules surround the solute particles, separating them and dispersing them throughout the liquid. This separation occurs because of the attractive forces between the solute particles and the solvent molecules, which overcome the forces holding the solute particles together.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solute
In the realm of solution chemistry, the solute plays a crucial role. It is the substance that gets dissolved, like when sugar or salt is added to water. Solutes can be solids, liquids, or even gases, depending on the nature of the solution they are a part of. Understanding the nature of solutes involves acknowledging their fundamental characteristics:
  • Smaller Amount: Solutes are typically found in lesser quantities compared to the solvent.
  • Nature: They can vary widely, from salts which are ionic, to sugars which are molecular.
  • Role: The solute's particle interactions determine how easily and completely it will dissolve in a given solvent.
Once a solute dissolves in a solvent, it breaks into its individual particles, evenly dispersing throughout, forming a solution. The nature of these interactions can significantly influence how quickly dissolution occurs and the overall solubility of the solute. For instance, ionic solutes like salt dissociate into ions when dissolved, while molecular solutes stay as molecules. Understanding these interactions helps in predicting and controlling the behavior of solutions in various applications.
Solvent
The solvent is the medium in which the solute is dissolved, and it forms the bulk of a solution. Its ability to dissolve other substances makes it an essential part of the formulation of solutions. Typically, solvents are liquids, with water being the most common example.
  • Larger Amount: Solvents are present in greater quantities compared to solutes in a solution.
  • Versatility: Though they are often liquids, solvents can also be gases or even solids in certain contexts, expanding their applicability.
  • Properties: The effectiveness of a solvent in dissolving a solute heavily relies on its chemical properties, such as polarity, and temperature.
Different solvents have different capacities to dissolve solutes, meaning the choice of solvent can dictate the success and efficiency of the dissolving process. For instance, polar solvents like water are quite effective in dissolving ionic compounds, while non-polar solvents are better suited for dissolving non-polar substances. Understanding these aspects helps chemists manipulate solutions for desired outcomes.
Dissolving Process
The dissolving process is an engaging concept in solution chemistry that describes how solutes interact with solvents. When a solute is introduced into a solvent, several things happen simultaneously.
  • Interaction: The solvent molecules surround solute particles, pulling them apart and spreading them throughout the solution.
  • Forces at Play: As the solvent molecules interact with the solute, the attractive forces between them can overcome the internal cohesive forces holding the solute particles together, allowing them to separate.
  • Homogeneity: Once dissolved, the solute's presence is uniform throughout the solvent, resulting in a homogeneous mixture.
External factors such as temperature, stirring, and pressure can influence the rate and extent of the dissolving process. For example, increased temperatures often enhance the kinetic energy of molecules, leading to faster dissolution. Additionally, mechanical stirring can help distribute solute particles more evenly, promoting quicker interactions with solvent molecules. Understanding these dynamics is crucial for optimizing solution preparation across various fields and industries.

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Most popular questions from this chapter

The following "cycle of copper" experiment is performed in some general chemistry laboratories. The series of reactions starts with copper and ends with metallic copper. The steps are as follows: (1) A piece of copper wire of known mass is allowed to react with concentrated nitric acid [the products are copper(II) nitrate, nitrogen dioxide, and water]. (2) The copper(II) nitrate is treated with a sodium hydroxide solution to form copper(II) hydroxide precipitate. (3) On heating, copper(II) hydroxide decomposes to yield copper(II) oxide. (4) The copper(II) oxide is combined with concentrated sulfuric acid to yield copper(II) sulfate. (5) Copper(II) sulfate is treated with an excess of zinc metal to form metallic copper. (6) The remaining zinc metal is removed by treatment with hydrochloric acid, and metallic copper is filtered, dried, and weighed. (a) Write a balanced equation for each step and classify the reactions. (b) Assuming that a student started with \(65.6 \mathrm{~g}\) of copper, calculate the theoretical yield at each step. (c) Considering the nature of the steps, comment on why it is possible to recover most of the copper used at the start.

If \(30.0 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{CaCl}_{2}\) is added to \(15.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{AgNO}_{3},\) what is the mass in grams of \(\mathrm{AgCl}\) precipitate?

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Write the equation for calculating molarity. Why is molarity a convenient concentration unit in chemistry?

How many grams of \(\mathrm{KOH}\) are present in \(35.0 \mathrm{~mL}\) of a \(5.50 \mathrm{M} \mathrm{KOH}\) solution?

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