Chapter 3: Problem 90
Nickel carbonyl can be prepared by the direct combination of nickel metal with carbon monoxide gas according to the following chemical equation: $$ \mathrm{Ni}(s)+4 \mathrm{CO}(g) \longrightarrow \mathrm{Ni}(\mathrm{CO})_{4}(s) $$ Determine the mass of nickel carbonyl that can be produced by the combination of \(50.03 \mathrm{~g} \mathrm{Ni}(s)\) with \(78.25 \mathrm{~g} \mathrm{CO}(g)\). Which reactant is consumed completely? How much of the other reactant remains when the reaction is complete?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Equation
In this particular case, the chemical equation is \( \mathrm{Ni}(s) + 4 \ \mathrm{CO}(g) \longrightarrow \mathrm{Ni}(\mathrm{CO})_4(s) \). Here, nickel metal \( \mathrm{Ni}(s) \) combines with carbon monoxide gas \( \mathrm{CO}(g) \) to form nickel carbonyl \( \mathrm{Ni}(\mathrm{CO})_4(s) \).
Understanding the chemical equation is essential as it provides the stoichiometric relationship between reactants and products. Each component in the equation must be balanced to conform to the principle of conservation of mass, which implies the same number of each type of atom appears on both sides of the reaction.
Molar Mass
To solve the problem, we first need the molar masses of the elements involved. For nickel \( \mathrm{Ni} \), the molar mass is approximately 58.69 g/mol. For carbon monoxide \( \mathrm{CO} \), you calculate by adding carbon's molar mass (12.01 g/mol) and oxygen's molar mass (16.00 g/mol), totaling about 28.01 g/mol.
These molar masses are crucial for converting the given masses of substances into moles, which can then be used in stoichiometric calculations to determine how many moles of each reactant will be used or formed during the reaction.
Nickel Carbonyl
This compound plays an essential role in industrial processes such as in the Mond process, which purifies nickel by exploiting the fact that nickel carbonyl decomposes to yield pure nickel. Its formation in the given reaction is significant because it highlights the practical applications of chemical reactions in industry.
The balanced reaction already provides the stoichiometry: one mole of nickel reacts with four moles of carbon monoxide to produce one mole of nickel carbonyl. This stoichiometric relationship is used to not only predict the amount of nickel carbonyl produced but also to understand the efficiency of the reaction.
Stoichiometry
In this problem, stoichiometry helps us determine the limiting reactant—carbon monoxide (CO) in this case—as we know from the chemical equation that 1 mole of nickel requires 4 moles of carbon monoxide to fully react. Given we have only 2.794 moles of CO with 0.852 moles of Ni, CO will be consumed completely before all of the nickel is used up.
Using stoichiometry, we can calculate the amount of nickel carbonyl produced. The moles of CO dictate the maximum amount of nickel carbonyl that can be formed, which is found to be approximately 0.698 moles. Knowing stoichiometry allows us to calculate other useful information like the remaining mass of unreacted nickel, reinforcing the importance of measuring and predicting chemical reactions in practical applications.