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Why is the theoretical yield of a reaction determined only by the amount of the limiting reactant?

Short Answer

Expert verified
The limiting reactant controls the maximum product amount, hence determines theoretical yield.

Step by step solution

01

Understanding Theoretical Yield

The theoretical yield of a chemical reaction is the maximum amount of product that can be produced from the given reactants, assuming complete conversion of the limiting reactant into the desired product.
02

Identifying the Limiting Reactant

In any chemical reaction, the limiting reactant is the one that is completely consumed first, limiting the extent of the reaction and determining the maximum amount of product that can be formed.
03

Connection Between Limiting Reactant and Theoretical Yield

Since the limiting reactant is consumed completely when the reaction goes to completion, the theoretical yield of a reaction is calculated based entirely on the amount of limiting reactant present. Other reactants are in excess and do not influence the maximum possible amount of product.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limiting Reactant
In a chemical reaction, not all reactants are used up simultaneously. One of these reactants is consumed quicker than the others, preventing more product from being formed. This reactant is known as the limiting reactant. It essentially determines the endpoint of the reaction. If you think of a reaction like a recipe, the limiting reactant is like the ingredient you run out of first, which stops you from baking any more cookies. Understanding which reactant is the limiting one is crucial because it limits the amount of product that is formed. Without it, no more reaction can take place, much like you can't bake without flour if you're making cookies. This means that the limiting reactant directly impacts the maximum yield, or the maximum amount of product possible in any chemical reaction.
Chemical Reaction
A chemical reaction is a process where reactants are transformed into products. This happens through the breaking and forming of bonds between atoms, which results in a new substance. Reactions can be as simple as combining hydrogen and oxygen to form water, or they can be much more complex, involving multiple steps and reactants. It is important to balance equations that represent chemical reactions. Balanced equations ensure that you abide by the law of conservation of mass, which states that matter cannot be created or destroyed. This balance allows us to predict the amounts of reactants and products involved and ensures that all atoms in the reactants account for atoms in the products.
Product Formation
The formation of a product in a chemical reaction directly stems from the reactants involved. But crucially, it's the limiting reactant that dictates how much product we get. Once all of the limiting reactant is used up, the reaction stops, and the maximum amount of product has been formed. This culmination is what is referred to as the theoretical yield. Sometimes, reactions don't go to completion or are impaired by side reactions, which can lead to a lower yield than theoretically possible. Yet, understanding the relationship between limiting reactants and product formation is vital in achieving maximum efficiency in any chemical industry processes.
Stoichiometry
Stoichiometry is the quantitative study of reactants and products in a chemical reaction. It's essentially like a chemical cookbook, helping you calculate how much of each ingredient (or reactant) is required and what amounts of product will result. This involves using a balanced chemical equation to find the mole ratios of reactants and products. These ratios allow you to convert between quantities of different substances. For instance, if you have 2 moles of hydrogen and need to know how much water you can produce, stoichiometry helps you make that conversion. It is invaluable for scientists and engineers, ensuring reactants mix in proper amounts without excess or deficit, which is cost-effective and environmentally friendly.

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Most popular questions from this chapter

Determine whether each of the following equations represents a combination reaction, a decomposition reaction, or a combustion reaction: (a) \(\mathrm{C}_{3} \mathrm{H}_{8}+\) \(5 \mathrm{O}_{2} \longrightarrow 3 \mathrm{CO}_{2}+4 \mathrm{H}_{2} \mathrm{O},(\mathrm{b}) 2 \mathrm{NF}_{2} \longrightarrow \mathrm{N}_{2} \mathrm{~F}_{4}\) (c) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{CuSO}_{4}+5 \mathrm{H}_{2} \mathrm{O} .\)

One of the reactions that occurs in a blast furnace, where iron ore is converted to cast iron, is $$ \mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{CO} \longrightarrow 2 \mathrm{Fe}+3 \mathrm{CO}_{2} $$ Suppose that \(1.64 \times 10^{3} \mathrm{~kg}\) of Fe is obtained from a \(2.62 \times 10^{3}-\mathrm{kg}\) sample of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\). Assuming that the reaction goes to completion, what is the percent purity of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the original sample?

Describe the steps involved in balancing a chemical equation.

The compound 2,3 -dimercaptopropanol \(\left(\mathrm{HSCH}_{2} \mathrm{CHSHCH}_{2} \mathrm{OH}\right),\) commonly known as British Anti-Lewisite (BAL), was developed during World War I as an antidote to arsenic-containing poison gas. (a) If each BAL molecule binds one arsenic (As) atom, how many As atoms can be removed by \(1.0 \mathrm{~g}\) of BAL? (b) BAL can also be used to remove poisonous heavy metals like mercury \((\mathrm{Hg})\) and lead \((\mathrm{Pb})\). If each \(\mathrm{BAL}\) binds one \(\mathrm{Hg}\) atom, calculate the mass percent of \(\mathrm{Hg}\) in a BAL-Hg complex. (An \(\mathrm{H}\) atom is removed when a BAL molecule binds an \(\mathrm{Hg}\) atom.)

The aluminum sulfate hydrate \(\left[\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot x \mathrm{H}_{2} \mathrm{O}\right]\) contains 8\. 10 percent \(\mathrm{Al}\) by mass. Calculate \(x\), that is, the number of water molecules associated with each \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) unit.

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