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Define limiting reactant and excess reactant. What is the significance of the limiting reactant in predicting the amount of the product obtained in a reaction? Can there be a limiting reactant if only one reactant is present?

Short Answer

Expert verified
The limiting reactant determines the maximum product yield. With one reactant, there is no limiting reactant in the typical sense.

Step by step solution

01

Define Limiting Reactant

The limiting reactant in a chemical reaction is the substance that is completely consumed first, thus limiting the extent of the reaction and determining the maximum amount of product that can be formed.
02

Define Excess Reactant

The excess reactant is the substance that remains after the reaction has reached completion. It is not used up entirely in the reaction and remains after the limiting reactant is exhausted.
03

Significance of Limiting Reactant

The limiting reactant is crucial for predicting the amount of product obtained because it determines the theoretical yield of the reaction. The amount of product formed depends on the amount of the limiting reactant available.
04

Limiting Reactant with One Reactant

If only one reactant is present, there cannot be a limiting reactant in the traditional sense, as there isn't a competing reactant to restrict the formation of the product. However, the amount of product is limited by the quantity of the single reactant available.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
In the world of chemistry, a chemical reaction refers to a process where substances known as reactants transform into different substances called products. This transformation involves breaking existing chemical bonds and forming new ones. Chemical reactions can occur in various forms, such as combustion, synthesis, decomposition, and more.
Understanding chemical reactions is crucial because they underpin many natural and industrial processes. For example, when you burn wood, the reaction between oxygen and cellulose produces water, carbon dioxide, and energy, giving us warmth.
  • Reactants: Original substances that undergo change.
  • Products: New substances formed as a result of the reaction.
  • Chemical Equations: Representations of chemical reactions showing reactants and products.
Each reaction is characterized by a chemical equation that shows how many reactant molecules are needed to form the products. This equation is balanced so that the number of atoms of each element is the same on both sides, reflecting the conservation of mass.
Excess Reactant
In a chemical reaction, the excess reactant is the substance that is not completely used up when the reaction goes to completion. After the limiting reactant is exhausted, the reaction cannot proceed further, leaving some of the excess reactant unreacted.
The presence of an excess reactant can affect the course and efficiency of a reaction:
  • Unreacted Residue: Excess reactant remains after the reaction, which could lead to waste or require post-reaction separation processes.
  • Reaction Optimization: Understanding which reactant is in excess aids in optimizing reactions to minimize waste.
Calculating the excess reactant involves determining how much of it remains after the limiting reactant is used up. This calculation is essential for reactions in industrial settings where efficiency and cost-control are vital.
Theoretical Yield
The theoretical yield in a chemical reaction is the maximum amount of product that can be formed when the limiting reactant is completely consumed. It is a crucial concept for understanding reaction efficiency.
The theoretical yield assumes perfect conditions with no losses, side reactions, or inefficiencies. It is calculated based on stoichiometry from the balanced chemical equation. To calculate it:
  • Identify the Limiting Reactant: Determine which reactant will be entirely consumed first.
  • Use Stoichiometry: Calculate the amount of product that can be formed based on the mole ratios from the balanced equation.
Keep in mind that the actual yield (what you obtain in practice) is often less than the theoretical yield due to various practical factors. Knowing the theoretical yield helps in evaluating experiment success and efficiency.
Reaction Completion
Reaction completion refers to the point at which a chemical reaction has used up the limiting reactant, and no more products can be formed because there are no more reactants. This concept is important in predicting when a reaction will stop and in analyzing reaction efficiency.
Once the limiting reactant is gone, the reaction halts, even if other reactants are still available. Reaction completion has several implications:
  • End of Reaction: No further products can be formed after this point.
  • Remaining Reactants: Any reactants left unreacted at the end are considered in excess.
Monitoring reaction completion can involve techniques such as noting color changes, gas production, or other indicators that a reaction has stopped. Understanding when a reaction is complete ensures proper use of resources and aids in planning for subsequent processes or reactions.

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Most popular questions from this chapter

The compound 2,3 -dimercaptopropanol \(\left(\mathrm{HSCH}_{2} \mathrm{CHSHCH}_{2} \mathrm{OH}\right),\) commonly known as British Anti-Lewisite (BAL), was developed during World War I as an antidote to arsenic-containing poison gas. (a) If each BAL molecule binds one arsenic (As) atom, how many As atoms can be removed by \(1.0 \mathrm{~g}\) of BAL? (b) BAL can also be used to remove poisonous heavy metals like mercury \((\mathrm{Hg})\) and lead \((\mathrm{Pb})\). If each \(\mathrm{BAL}\) binds one \(\mathrm{Hg}\) atom, calculate the mass percent of \(\mathrm{Hg}\) in a BAL-Hg complex. (An \(\mathrm{H}\) atom is removed when a BAL molecule binds an \(\mathrm{Hg}\) atom.)

The annual production of sulfur dioxide from burning coal and fossil fuels, auto exhaust, and other sources is about 26 million tons. The equation for the reaction is $$ \mathrm{S}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{SO}_{2}(g) $$ How much sulfur (in tons), present in the original materials. would result in that quantity of \(\mathrm{SO}_{2}\) ?

Octane \(\left(\mathrm{C}_{8} \mathrm{H}_{18}\right)\) is a component of gasoline. Complete combustion of octane yields \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CO}_{2}\). Incomplete combustion produces \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CO},\) which not only reduces the efficiency of the engine using the fuel but is also toxic. In a certain test run, 1.000 gallon (gal) of octane is burned in an engine. The total mass of \(\mathrm{CO}, \mathrm{CO}_{2}\), and \(\mathrm{H}_{2} \mathrm{O}\) produced is \(11.53 \mathrm{~kg} .\) Calculate the efficiency of the process; that is, calculate the fraction of octane converted to \(\mathrm{CO}_{2}\). The density of octane is \(2.650 \mathrm{~kg} / \mathrm{gal}\).

Industrially, nitric acid is produced by the Ostwald process represented by the following equations: $$ \begin{aligned} 4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow & 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) \\ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) & \longrightarrow 2 \mathrm{NO}_{2}(g) \\ 2 \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) & \longrightarrow \mathrm{HNO}_{3}(a q)+\mathrm{HNO}_{2}(a q) \end{aligned} $$ What mass of \(\mathrm{NH}_{3}\) (in grams) must be used to produce 1.00 ton of \(\mathrm{HNO}_{3}\) by the Ostwald process, assuming an 80 percent yield in each step \((1\) ton \(=2000 \mathrm{lb} ;\) $$ 1 \mathrm{lb}=453.6 \mathrm{~g}) ? $$

Disulfide dichloride \(\left(\mathrm{S}_{2} \mathrm{Cl}_{2}\right)\) is used in the vulcanization of rubber, a process that prevents the slippage of rubber molecules past one another when stretched. It is prepared by heating sulfur in an atmosphere of chlorine: $$ \mathrm{S}_{8}(l)+4 \mathrm{Cl}_{2}(g) \stackrel{\Delta}{\longrightarrow} 4 \mathrm{~S}_{2} \mathrm{Cl}_{2}(l) $$ What is the theoretical yield of \(\mathrm{S}_{2} \mathrm{Cl}_{2}\) in grams when \(4.06 \mathrm{~g}\) of \(\mathrm{S}_{8}\) is heated with \(6.24 \mathrm{~g}\) of \(\mathrm{Cl}_{2}\) ? If the actual yield of \(\mathrm{S}_{2} \mathrm{Cl}_{2}\) is \(6.55 \mathrm{~g},\) what is the percent yield?

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