Chapter 3: Problem 77
Fermentation is a complex chemical process of winemaking in which glucose is converted into ethanol and carbon dioxide: $$ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+2 \mathrm{CO}_{2} $$ glucose ethanol Starting with \(500.4 \mathrm{~g}\) of glucose, what is the maximum amount of ethanol in grams and in liters that can be obtained by this process (density of ethanol \(=0.789 \mathrm{~g} / \mathrm{mL}\) )?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Process
The chemical reaction can be expressed simply with the equation:
- \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \rightarrow 2 \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OH} + 2\mathrm{CO}_{2} \)
Glucose Conversion
During this conversion, glucose \( \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 \) serves as the substrate, undergoing fermentation to yield ethanol \( \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \) and carbon dioxide \( \mathrm{CO}_2 \).
- Each glucose molecule breaks down into two molecules of ethanol.
- This biological conversion is energy-efficient and environmentally friendly, unlike many other chemical transformations that require external energy and resources.
- Understanding this conversion helps illustrate why glucose is fundamental in brewing and biofuel productions.
Ethanol Production
To calculate ethanol yield, you need to know the stoichiometry of the reaction, which determines that each glucose molecule produces two ethanol molecules. This information allows chemists to predict theoretical production quantities from known glucose amounts.
For example, starting with 500.4 grams of glucose, the maximum ethanol produced can be determined by calculating moles of glucose and thereby determining moles of ethanol, ultimately converting this to mass and volume with the knowledge of ethanol's density for practical purposes.
Carbon Dioxide
- During the fermentation of glucose by yeast, each glucose molecule results in two \( \mathrm{CO}_2 \) molecules.
- Even though \( \mathrm{CO}_2 \) is not the primary product in ethanol production, it is essential for creating the airy structure in baked goods.
Stoichiometry
- For every mole of glucose \( \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 \), two moles of ethanol \( \mathrm{C}_2\mathrm{H}_5\mathrm{OH} \) are produced.
- This understanding allows scientists and chemists to calculate the theoretical yields of products based on starting amounts of reactants, just like determining the mass and volume of ethanol possible from a given mass of glucose.