Chapter 3: Problem 76
When potassium cyanide ( \(\mathrm{KCN}\) ) reacts with acids, a deadly poisonous gas, hydrogen cyanide (HCN), is given off. Here is the equation: $$ \mathrm{KCN}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{KCl}(a q)+\mathrm{HCN}(g) $$ If a sample of \(0.140 \mathrm{~g}\) of \(\mathrm{KCN}\) is treated with an excess of \(\mathrm{HCl}\), calculate the amount of HCN formed, in grams.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Reactions
In this process, atoms are rearranged but not created or destroyed. This particular reaction is an example of a single replacement reaction, where an element in a compound is replaced by an element in another compound.
Understanding the type of reaction occurring helps in predicting the products and the behavior of the substances involved. It also provides insight into the safety precautions needed, especially when dealing with dangerous chemicals.
Molar Mass Calculation
To calculate the molar mass of \( \text{KCN} \), we sum the atomic masses of its constituent elements: potassium (K), carbon (C), and nitrogen (N).
- Potassium: 39.1 g/mol
- Carbon: 12.0 g/mol
- Nitrogen: 14.0 g/mol
Balanced Chemical Equations
In the equation \( \text{KCN} (aq) + \text{HCl} (aq) \rightarrow \text{KCl} (aq) + \text{HCN} (g) \), each molecule of KCN reacts with a molecule of HCl to produce one molecule each of KCl and HCN.
The balanced equation reflects a 1:1 molar ratio between the reactants and products, crucial for stoichiometric calculations. This ratio tells us that for every mole of KCN consumed, one mole of HCN is produced.
- This ensures that the equation respects the law of conservation of mass and predicts yields of products.
- Understanding this allows chemists to calculate the amounts of reactants needed or products formed and apply these skills effectively in laboratory settings or industry processes.