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Describe the steps involved in balancing a chemical equation.

Short Answer

Expert verified
Write the unbalanced equation, count atoms, adjust coefficients for balance, and verify.

Step by step solution

01

Write the Unbalanced Equation

Start by writing the chemical equation with the correct formulas for each reactant and product. For instance, if you have the reaction between hydrogen gas and oxygen gas to form water, write it as: \[ \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} \] At this stage, the number of atoms for each element is not necessarily equal on both sides of the equation.
02

Count the Atoms of Each Element

List all the elements involved in the reaction and count how many atoms of each element are present in both the reactants and the products. With our example:Reactants: \(\text{H} = 2\), \(\text{O} = 2\) Products: \(\text{H} = 2\), \(\text{O} = 1\).
03

Balance One Element at a Time

Begin balancing the equation by adjusting the coefficients of compounds to equalize the number of atoms of an element on both sides. It's usually best to start with the most complex molecule or the one appearing less frequently. In this case, water is the only product so it's practical to balance oxygen first. Adjust the coefficient of \(\text{H}_2\text{O}\) to balance the oxygen: \[ \text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \] Now, recount the atoms: Reactants: \(\text{H} = 2\), \(\text{O} = 2\) Products: \(\text{H} = 4\), \(\text{O} = 2\).
04

Balance Remaining Elements

After adjusting for oxygen, balance the remaining elements, in this case, hydrogen. Adjust the hydrogen gas molecules:\[ 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \] Recount:Reactants: \(\text{H} = 4\), \(\text{O} = 2\) Products: \(\text{H} = 4\), \(\text{O} = 2\).
05

Verify the Balance

Check to ensure all elements are balanced. Each side of the equation has the same number of atoms for each element:\(\text{H} = 4\), \(\text{O} = 2\).The balanced chemical equation is: \[ 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction
A chemical reaction is a process where reactants are transformed into products through the reorganization of atoms. During this process, the chemical properties of substances change, forming new products with different molecules. For example, when hydrogen gas reacts with oxygen gas, they produce water. This transformation involves the breaking and forming of chemical bonds.

Understanding chemical reactions is crucial because they illustrate how matter interacts and changes. They occur in everyday life, from cooking food to driving a car. You should become familiar with writing equations that represent these reactions.

Here’s how a simple chemical reaction is represented:
  • Reactants: Initial substances present before the reaction.
  • Products: New substances formed as a result of the reaction.
  • Equation: A symbolic representation showing reactants changing into products.
This symbolic equation provides a clear depiction of the elements involved and how they transform during the reaction.
Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to interpret the relationship between the amounts of reactants consumed and products formed. This concept ensures that chemical equations represent reality by having the same quantity of each type of atom on both sides of the equation.

Balancing chemical equations is a fundamental application of stoichiometry. Here’s why it’s important:
  • Proportions: Stoichiometry uses coefficients to show the ratio of reactants and products, indicating how much of each is involved in the reaction.
  • Predictive power: It allows us to predict how much product can be obtained from a given amount of reactants or determine the quantity of reactants necessary for a desired amount of product.
  • Conservation: Reflects the law of conservation of mass by ensuring matter is neither lost nor gained in a reaction.
Applying stoichiometry to an equation helps us understand these relationships and ensures chemical reactions are accurate and meaningful.
Conservation of Mass
The law of conservation of mass states that in a closed system, mass is preserved in a chemical reaction. This means the mass of the reactants must equal the mass of the products. Balancing chemical equations is a practical way to apply this principle, now fundamental to chemistry.

Here’s how conservation of mass plays out in balancing equations:
  • Atom count: The number of each type of atom remains constant before and after a chemical reaction. This is why balancing equations relies on making sure every atom present in the reactants is accounted for among the products.
  • Practical outcomes: This principle ensures that industries, labs, and other fields can rely on predicted outcomes when working with chemical reactions.
  • Real-world significance: From pharmaceuticals to engineering, maintaining the mass consistency ensures safety and efficiency in chemical processes.
In summary, conservation of mass reassures us that our chemical equations reflect the true nature of how matter behaves, affirming that matter is neither created nor destroyed.

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Most popular questions from this chapter

Carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fuels is a major cause of the increased concentration of \(\mathrm{CO}_{2}\) in the atmosphere. Carbon dioxide is also the end product of metabolism (see Sample Problem 3.4). Using glucose as an example of food, calculate the annual human production of \(\mathrm{CO}_{2}\) in grams, assuming that each person consumes \(5.0 \times 10^{2} \mathrm{~g}\) of glucose per day, that the world's population is 6.5 billion, and that there are 365 days in a year.

Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of aluminum metal. It is prepared by the reaction $$ \mathrm{CaF}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \mathrm{CaSO}_{4}+2 \mathrm{HF} $$ In one process, \(6.00 \mathrm{~kg}\) of \(\mathrm{CaF}_{2}\) is treated with an excess of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and yields \(2.86 \mathrm{~kg}\) of \(\mathrm{HF}\). Calculate the percent yield of HF.

The empirical formula of a compound is \(\mathrm{CH}\). If the molar mass of this compound is about \(78 \mathrm{~g},\) what is its molecular formula?

When baking soda (sodium bicarbonate or sodium hydrogen carbonate, \(\mathrm{NaHCO}_{3}\) ) is heated, it releases carbon dioxide gas, which is responsible for the rising of cookies, doughnuts, and bread. (a) Write a balanced equation for the decomposition of the compound (one of the products is \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) ). (b) Calculate the mass of \(\mathrm{NaHCO}_{3}\) required to produce \(20.5 \mathrm{~g}\) of \(\mathrm{CO}_{2}\)

When combined, aqueous solutions of sulfuric acid and potassium hydroxide react to form water and aqueous potassium sulfate according to the following equation (unbalanced): $$ \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{KOH}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{K}_{2} \mathrm{SO}_{4}(a q) $$ Determine what mass of water is produced when a beaker containing \(100.0 \mathrm{~g} \mathrm{H}_{2} \mathrm{SO}_{4}\) dissolved in \(250 \mathrm{~mL}\) water is added to a larger beaker containing \(100.0 \mathrm{~g}\) KOH dissolved in \(225 \mathrm{~mL}\) water. Determine the mass amounts of each substance (other than water) present in the large beaker when the reaction is complete.

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