Chapter 3: Problem 69
Describe the steps involved in balancing a chemical equation.
Short Answer
Expert verified
Write the unbalanced equation, count atoms, adjust coefficients for balance, and verify.
Step by step solution
01
Write the Unbalanced Equation
Start by writing the chemical equation with the correct formulas for each reactant and product. For instance, if you have the reaction between hydrogen gas and oxygen gas to form water, write it as: \[ \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} \] At this stage, the number of atoms for each element is not necessarily equal on both sides of the equation.
02
Count the Atoms of Each Element
List all the elements involved in the reaction and count how many atoms of each element are present in both the reactants and the products. With our example:Reactants: \(\text{H} = 2\), \(\text{O} = 2\) Products: \(\text{H} = 2\), \(\text{O} = 1\).
03
Balance One Element at a Time
Begin balancing the equation by adjusting the coefficients of compounds to equalize the number of atoms of an element on both sides. It's usually best to start with the most complex molecule or the one appearing less frequently. In this case, water is the only product so it's practical to balance oxygen first. Adjust the coefficient of \(\text{H}_2\text{O}\) to balance the oxygen: \[ \text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \] Now, recount the atoms: Reactants: \(\text{H} = 2\), \(\text{O} = 2\) Products: \(\text{H} = 4\), \(\text{O} = 2\).
04
Balance Remaining Elements
After adjusting for oxygen, balance the remaining elements, in this case, hydrogen. Adjust the hydrogen gas molecules:\[ 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \] Recount:Reactants: \(\text{H} = 4\), \(\text{O} = 2\) Products: \(\text{H} = 4\), \(\text{O} = 2\).
05
Verify the Balance
Check to ensure all elements are balanced. Each side of the equation has the same number of atoms for each element:\(\text{H} = 4\), \(\text{O} = 2\).The balanced chemical equation is: \[ 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Reaction
A chemical reaction is a process where reactants are transformed into products through the reorganization of atoms. During this process, the chemical properties of substances change, forming new products with different molecules. For example, when hydrogen gas reacts with oxygen gas, they produce water. This transformation involves the breaking and forming of chemical bonds.
Understanding chemical reactions is crucial because they illustrate how matter interacts and changes. They occur in everyday life, from cooking food to driving a car. You should become familiar with writing equations that represent these reactions.
Here’s how a simple chemical reaction is represented:
Understanding chemical reactions is crucial because they illustrate how matter interacts and changes. They occur in everyday life, from cooking food to driving a car. You should become familiar with writing equations that represent these reactions.
Here’s how a simple chemical reaction is represented:
- Reactants: Initial substances present before the reaction.
- Products: New substances formed as a result of the reaction.
- Equation: A symbolic representation showing reactants changing into products.
Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to interpret the relationship between the amounts of reactants consumed and products formed. This concept ensures that chemical equations represent reality by having the same quantity of each type of atom on both sides of the equation.
Balancing chemical equations is a fundamental application of stoichiometry. Here’s why it’s important:
Balancing chemical equations is a fundamental application of stoichiometry. Here’s why it’s important:
- Proportions: Stoichiometry uses coefficients to show the ratio of reactants and products, indicating how much of each is involved in the reaction.
- Predictive power: It allows us to predict how much product can be obtained from a given amount of reactants or determine the quantity of reactants necessary for a desired amount of product.
- Conservation: Reflects the law of conservation of mass by ensuring matter is neither lost nor gained in a reaction.
Conservation of Mass
The law of conservation of mass states that in a closed system, mass is preserved in a chemical reaction. This means the mass of the reactants must equal the mass of the products. Balancing chemical equations is a practical way to apply this principle, now fundamental to chemistry.
Here’s how conservation of mass plays out in balancing equations:
Here’s how conservation of mass plays out in balancing equations:
- Atom count: The number of each type of atom remains constant before and after a chemical reaction. This is why balancing equations relies on making sure every atom present in the reactants is accounted for among the products.
- Practical outcomes: This principle ensures that industries, labs, and other fields can rely on predicted outcomes when working with chemical reactions.
- Real-world significance: From pharmaceuticals to engineering, maintaining the mass consistency ensures safety and efficiency in chemical processes.