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Explain why, in combustion analysis, we cannot determine the amount of oxygen in the sample directly from the amount of oxygen in the products \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CO}_{2}\)

Short Answer

Expert verified
The oxygen in the products comes from both the sample and atmospheric oxygen, preventing direct measurement of the sample's oxygen content.

Step by step solution

01

Understand Combustion Analysis

In combustion analysis, a sample containing an unknown organic compound is burned, and the products are typically carbon dioxide \(\mathrm{CO}_2\) and water \(\mathrm{H}_2\mathrm{O}\). These products are analyzed to determine the composition of the original compound.
02

Identify the Source of Oxygen in the Products

The oxygen present in the products \(\mathrm{CO}_2\) and \(\mathrm{H}_2\mathrm{O}\) comes not only from the sample itself but also from the oxygen used in the combustion process. Thus, there are two sources of oxygen: the original sample and the atmospheric oxygen used to support combustion.
03

Recognize the Problem

Since the total oxygen in \(\mathrm{CO}_2\) and \(\mathrm{H}_2\mathrm{O}\) includes both the oxygen from the original sample and the added atmospheric oxygen, it's impossible to isolate and measure the exact amount of oxygen that was originally present in the sample just by examining these products.
04

Conclusion

This indirect nature of the measurement makes it necessary to use other analytical techniques or calculations to determine the original oxygen content in the sample, as the distinction between the two sources of oxygen cannot be achieved solely by analyzing \(\mathrm{CO}_2\) and \(\mathrm{H}_2\mathrm{O}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxygen Determination
In the process of combustion analysis, identifying the amount of oxygen in an organic compound proves challenging. This difficulty arises mainly because oxygen has dual origins during the combustion process. As an organic sample is ignited, two sources contribute to the oxygen measured: the compound itself and the atmospheric oxygen that facilitates the burning. This overlap makes it impossible to determine the precise oxygen content within the compound through direct measurements of the combustion products, such as carbon dioxide and water. Without differentiation between these sources, analysts must rely on indirect methods or supplementary data to ascertain the original oxygen content. To overcome this measurement barrier, alternative methods such as using additional chemical analysis are often employed. These might involve calculating oxygen content based on other elemental findings—like carbon or hydrogen—within the compound. Such approaches help bridge the gap caused by the indistinguishable contribution of oxygen from the atmosphere.
Organic Compounds
Understanding the nature of organic compounds is crucial when performing combustion analysis. These compounds primarily consist of carbon, hydrogen, and sometimes oxygen. During combustion, the carbon and hydrogen elements transform into carbon dioxide and water, respectively. The composition of organic compounds directly influences the type and amount of combustion products generated. To thoroughly analyze an organic compound, it's essential to understand its makeup, especially when the compound includes oxygen as a constituent. Knowing the basic molecule structure can help predict the behaviors seen in combustion analysis. For instance:
  • Compounds rich in carbon yield higher carbon dioxide.
  • Compounds with more hydrogen produce more water.
  • Presence of oxygen complicates exact analysis due to its role in both the sample and as an atmospheric aid in combustion.
Combustion Products
Combustion products are the result of burning an organic compound. The primary products are carbon dioxide (\( \text{CO}_2 \)) and water (\( \text{H}_2\text{O} \)).These products contain elements from both the original compounds and the atmospheric oxygen used during combustion. Analyzing these products allows scientists to infer the original compound's composition, except for directly identifying its oxygen content.Combustion analysis involves capturing and measuring these gases to determine the amounts of carbon and hydrogen in the compound. However, the complexity arises in differentiating between oxygen originating from the component and oxygen used for combustion. Despite this, understanding the nature of combustion products remains a foundational aspect of many esoteric and practical applications in chemistry.
Carbon Dioxide
Carbon dioxide (\( \text{CO}_2 \)) is a major product of combustion when analyzing organic compounds.It emerges from the oxidation of carbon present in the sample. By determining the amount of \( \text{CO}_2 \) produced, chemists can calculate the carbon content of the initial compound.This is relatively straightforward because the \( \text{CO}_2 \) produced is entirely derived from the carbon within the compound. Unlike oxygen, there's no issue with atmospheric carbon contributing to the measurement.However, since \( \text{CO}_2 \) only informs about carbon, its analysis must be combined with water analysis to gain a fuller understanding of the compound's makeup. This method can effectively illustrate the carbon content, yet offers no clues about the original oxygen in the compound itself.
Water
In combustion analysis, water (\( \text{H}_2\text{O} \)) is formed as hydrogen in the organic compound oxidizes.This makes water a critical indicator used to ascertain the hydrogen content. By measuring the quantity of water generated during combustion, chemists deduce the amount of hydrogen in the original organic substance.However, similar to oxygen measurements, water analysis doesn't inherently clarify whether the source of oxygen within the water comes from the compound or atmospheric oxygen. Therefore, while water provides valuable insight into the hydrogen composition, it doesn't directly reveal the level of oxygen present initially. Such complications necessitate further analysis or alternative methods to fully appreciate the compound's original structure and composition.

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Most popular questions from this chapter

Give an everyday example that illustrates the limiting reactant concept.

Potash is any potassium mineral that is used for its potassium content. Most of the potash produced in the United States goes into fertilizer. The major sources of potash are potassium chloride \((\mathrm{KCl})\) and potassium sulfate \(\left(\mathrm{K}_{2} \mathrm{SO}_{4}\right) .\) Potash production is often reported as the potassium oxide \(\left(\mathrm{K}_{2} \mathrm{O}\right)\) equivalent or the amount of \(\mathrm{K}_{2} \mathrm{O}\) that could be made from a given mineral. (a) If \(\mathrm{KCl}\) costs \(\$ 0.55\) per \(\mathrm{kg},\) for what price (dollar per kg) must \(\mathrm{K}_{2} \mathrm{SO}_{4}\) be sold to supply the same amount of potassium on a per dollar basis? (b) What mass (in kg) of \(\mathrm{K}_{2} \mathrm{O}\) contains the same number of moles of \(\mathrm{K}\) atoms as \(1.00 \mathrm{~kg}\) of \(\mathrm{KCl}\) ?

The depletion of ozone \(\left(\mathrm{O}_{3}\right)\) in the stratosphere has been a matter of great concern among scientists in recent years. It is believed that ozone can react with nitric oxide (NO) that is discharged from high-altitude jet planes. The reaction is $$ \mathrm{O}_{3}+\mathrm{NO} \longrightarrow \mathrm{O}_{2}+\mathrm{NO}_{2} $$ If \(0.740 \mathrm{~g}\) of \(\mathrm{O}_{3}\) reacts with \(0.670 \mathrm{~g}\) of NO, how many grams of \(\mathrm{NO}_{2}\) will be produced? Which compound is the limiting reactant? Calculate the number of moles of the excess reactant remaining at the end of the reaction.

Ascorbic acid (vitamin C) contains \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O} . \mathrm{In}\) one combustion analysis, \(5.24 \mathrm{~g}\) of ascorbic acid yields \(7.86 \mathrm{~g} \mathrm{CO}_{2}\) and \(2.14 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} .\) Calculate the empirical formula and molecular formula of ascorbic acid given that its molar mass is about \(176 \mathrm{~g}\).

The natural abundances of the two stable isotopes of hydrogen (hydrogen and deuterium) are 99.99 percent \({ }_{1}^{1} \mathrm{H}\) and 0.01 percent \({ }_{1}^{2} \mathrm{H}\). Assume that water exists as either \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{D}_{2} \mathrm{O} .\) Calculate the number of \(\mathrm{D}_{2} \mathrm{O}\) molecules in exactly \(400 \mathrm{~mL}\) of water \((\) density \(1.00 \mathrm{~g} / \mathrm{mL})\).

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