Chapter 3: Problem 49
How many grams of sulfur (S) are needed to react completely with \(246 \mathrm{~g}\) of mercury \((\mathrm{Hg})\) to form \(\mathrm{HgS}\) ?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Balanced Chemical Equation
Hg + S → HgS.
This equation is balanced, meaning the number of atoms for each element is the same on both sides. One mercury atom reacts with one sulfur atom to form one molecule of mercuric sulfide. Balanced equations ensure the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction, is followed. This balance allows us to calculate the amount of substances needed or produced accurately.
Moles
Knowing the number of moles helps us understand how substances react in set proportions. In this exercise, calculating the moles of mercury is crucial. By determining the moles, we find out how many atoms are really taking part in the reaction with sulfur. One useful formula to remember is:
\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \]This calculation aligns with the balanced equation to find the exact moles of each component involved.
Molar Mass
- Molar mass allows chemists to convert between the mass of a substance and the number of moles.
- It's crucial in calculating how much of one material will react with another.
Mercuric Sulfide
Mercuric sulfide is noteworthy in various applications:
- Used historically as a pigment known for its vibrant red color.
- It's a more stable, nontoxic form of mercury, prevalent in traditional medicine and alchemy.