Chapter 3: Problem 35
How many moles of cobalt (Co) atoms are there in \(6.00 \times 10^{9}(6\) billion) Co atoms?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Avogadro's number
When dealing with atoms, using Avogadro's number enables us to express quantities in moles, a more practical unit that relates to the macroscopic quantities we often handle in labs. If you think of moles like a "chemist's dozen," where instead of 12 items, we count approximately \(6.022 \times 10^{23}\) items, it all starts to make sense. This mass-to-quantity conversion is what makes Avogadro's number vital for calculations involving chemical reactions and physical substances.
cobalt atoms
In chemistry, understanding the number of cobalt atoms in a sample is crucial for determining the substance's mass, reacting proportions, and potential applications. When we say we have "6 billion cobalt atoms," we are specifying a very tiny amount from a macroscopic point of view, but quite substantial when talking about atomic-level quantities. Remember, due to Avogadro's immense number, \(6.00 \times 10^{9}\) atoms equate to just a tiny fraction of a mole, showcasing how vast an Avogadro number truly is.
conversion formula
- \(\text{number of moles} = \frac{\text{number of atoms}}{\text{Avogadro's number}}\)
Let's break down how it works: If you have \(6.00 \times 10^{9}\) cobalt atoms and wish to find the equivalent number of moles, you place the number of atoms over Avogadro's number in the formula. By performing the division \(\frac{6.00 \times 10^{9}}{6.022 \times 10^{23}}\), you go from counting individual atoms to expressing the quantity as approximately \(9.97 \times 10^{-15}\) moles.
This systematic approach goes beyond cobalt atoms, applying broadly to any substance you deal with on an atomic level. It's fundamental to mastering chemical calculations.