Chapter 3: Problem 13
Tooth enamel is \(\mathrm{Ca}_{5}\left(\mathrm{PO}_{4}\right)_{3}(\mathrm{OH}) .\) Calculate the percent composition of the elements present.
Short Answer
Expert verified
Calcium: 41.21%, Phosphorus: 19.10%, Oxygen: 39.49%, Hydrogen: 0.21%.
Step by step solution
01
Identify the Molar Mass
Identify the molar mass of each element in the chemical formula \( \mathrm{Ca}_{5}(\mathrm{PO}_{4})_{3}(\mathrm{OH}) \). The atomic masses are approximately: \( \mathrm{Ca}: 40.08 \, \mathrm{g/mol} \), \( \mathrm{P}: 30.97 \, \mathrm{g/mol} \), \( \mathrm{O}: 16.00 \, \mathrm{g/mol} \), and \( \mathrm{H}: 1.01 \, \mathrm{g/mol} \).
02
Calculate the Molar Mass of Each Element in the Compound
Calculate the total molar mass of each element in the compound:- \(5 \times 40.08 = 200.40 \, \mathrm{g/mol} \) for calcium- \(3 \times 30.97 = 92.91 \, \mathrm{g/mol} \) for phosphorus- \( (3 \times 4 + 1) \times 16.00 = 192.00 \, \mathrm{g/mol} \) for oxygen- \(1.01 \, \mathrm{g/mol} \) for hydrogen.
03
Calculate the Total Molar Mass of the Compound
Sum the molar masses of all elements to obtain the total molar mass:\[200.40 + 92.91 + 192.00 + 1.01 = 486.32 \, \mathrm{g/mol}.\]
04
Determine the Percent Composition of Each Element
Calculate the percent composition of each element:- Calcium: \((200.40 / 486.32) \times 100 \approx 41.21\%\)- Phosphorus: \((92.91 / 486.32) \times 100 \approx 19.10\%\)- Oxygen: \((192.00 / 486.32) \times 100 \approx 39.49\%\)- Hydrogen: \((1.01 / 486.32) \times 100 \approx 0.21\%\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
When working with chemical formulas, understanding molar mass is crucial. Molar mass is essentially the mass of one mole of a substance and is expressed in grams per mole (g/mol). To calculate the molar mass of a compound, you need to know the atomic masses of the individual elements present.
Here, you multiply the molar mass of each element by its corresponding number of atoms, and add these to get the total molar mass of 486.32 g/mol.
- The atomic mass for calcium (\( \mathrm{Ca} \)) is 40.08 g/mol.
- For phosphorus (\( \mathrm{P} \)), it's 30.97 g/mol.
- Oxygen (\( \mathrm{O} \)) has an atomic mass of 16.00 g/mol.
- While hydrogen (\( \mathrm{H} \)) is 1.01 g/mol.
Here, you multiply the molar mass of each element by its corresponding number of atoms, and add these to get the total molar mass of 486.32 g/mol.
Tooth Enamel Chemistry
The chemistry of tooth enamel is fascinating and integral to understanding its composition. Tooth enamel is primarily made of a compound known as hydroxyapatite, represented by the chemical formula \( \mathrm{Ca}_{5}(\mathrm{PO}_{4})_{3}(\mathrm{OH})\)\. This compound is a form of calcium phosphate and is responsible for the hardness of tooth enamel.
Enamel mainly consists of calcium, phosphorous, oxygen, and hydrogen. These elements come together to form a strong and resilient outer layer for our teeth.
Enamel mainly consists of calcium, phosphorous, oxygen, and hydrogen. These elements come together to form a strong and resilient outer layer for our teeth.
- Calcium contributes to the structural integrity of enamel.
- Phosphorus helps in building strength and resistance against decay.
- Oxygen and hydrogen bond within the hydroxide ions (\( \mathrm{OH}^{-} \)) in the compound, playing significant roles in the stability of the compound network.
Elemental Composition Calculation
Elemental composition calculation tells us the proportion of each element in a compound. This is done by determining the percentage of each element with respect to the total molar mass of the compound. The step-by-step approach involves calculating the mass of individual elements in the compound and dividing it by the total molar mass.
For instance:
For instance:
- The percent composition for calcium is found by taking its total mass in the compound (\(200.40\ g/mol\)) and dividing it by the total molar mass (\(486.32\ g/mol\)), then multiplying by 100. This gives roughly 41.21\%.
- Similarly, for phosphorus, oxygen, and hydrogen, the calculations yield 19.10\%, 39.49\%, and 0.21\% respectively.