Chapter 24: Problem 74
Compare the physical and chemical properties of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{~S}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Physical Properties
For example,
- Water (\(\mathrm{H}_{2}\mathrm{O}\)) is a colorless and odorless liquid at room temperature.
- Hydrogen sulfide (\(\mathrm{H}_{2}\mathrm{S}\)), on the other hand, is a colorless gas with a noticeable rotten egg smell at room temperature.
Melting Point and Boiling Point
- Water (\(\mathrm{H}_{2}\mathrm{O}\)) has a melting point of 0°C and a boiling point of 100°C. This means ice melts at 0°C, and water boils at 100°C under normal atmospheric pressure.
- Hydrogen sulfide (\(\mathrm{H}_{2}\mathrm{S}\)) has a much lower melting point of about -83°C and boils at around -60°C. It is primarily gas at room temperature.
Molecular Structure
For instance,
- Water's molecular structure is bent due to the two hydrogen atoms being bonded to oxygen in a V-shape at an angle of about 104.5°.
- Hydrogen sulfide also has a bent shape, but with a smaller angle than water because sulfur is less electronegative than oxygen.
Polarity and Hydrogen Bonding
- Water is highly polar due to the significant electronegativity difference between hydrogen and oxygen. This enables water molecules to form hydrogen bonds with each other, resulting in stronger intermolecular forces.
- In contrast, hydrogen sulfide has a lower polarity because sulfur is less electronegative than oxygen. This results in weaker intermolecular forces and the inability to form effective hydrogen bonds.