Chapter 24: Problem 73
What are the oxidation numbers of \(\mathrm{O}\) and \(\mathrm{F}\) in HFO?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fluorine
Fluorine's high electronegativity dictates that it will aggressively pull electrons closer, giving it a more negative oxidation state. This is why in the compound HFO, the oxidation number assigned to fluorine is consistently -1.
- Most electronegative element
- Oxidation number usually -1
- Attracts electrons strongly
Hydrogen
In the context of the compound HFO, hydrogen's oxidation state of +1 is used in balancing the overall charges of the molecule, maintaining the necessary condition where the sum of oxidation numbers in a neutral molecule equals zero.
- Typically +1 oxidation state with nonmetals
- Contributes to balancing charge
- Single electron donor
Oxygen
For the molecule HFO, calculating the oxidation number of oxygen relies on the principle that the sum of oxidation numbers in a neutral molecule must equate to zero. Given hydrogen's +1 and fluorine's -1, oxygen assumes an oxidation number of 0 in this unique compound to satisfy the charge balance.
- Usually -2 oxidation state
- Variable in fluorine compounds
- Neutral molecule charge neutrality
Electronegativity
The differences in electronegativity between the elements within a compound determine how atoms share or transfer electrons, thus resulting in particular oxidation numbers.
- Drives electron attraction
- Crucial for oxidation number assignment
- Fluorine: most electronegative
Neutral Molecule
This concept is critical in identifying the oxidation states of atoms because it provides a constraint that helps calculate unknown oxidation numbers.
- Overall charge is zero
- Sum of oxidation numbers equals zero
- Helpful in solving oxidation number problems